Print plain output with only a space in python












0














I have a dataframe with following columns and index :



   first  sec
0 z 50
2 b 3
1 a 3
4 c 2
5 e 1


I want to print this plain output :



z 50
b 3
a 3
c 2
e 1


I have used to_string , but its not giving desired results , i have used some loops too , but nothing is giving desired results










share|improve this question
























  • Are the columns guaranteed to take one character?
    – Willem Van Onsem
    Nov 14 '18 at 19:43










  • @WillemVanOnsem Yes, I just updated the question , first column will alwasys take one character , second column can have multiple characters just like I did in my edit
    – Mighty
    Nov 14 '18 at 19:48


















0














I have a dataframe with following columns and index :



   first  sec
0 z 50
2 b 3
1 a 3
4 c 2
5 e 1


I want to print this plain output :



z 50
b 3
a 3
c 2
e 1


I have used to_string , but its not giving desired results , i have used some loops too , but nothing is giving desired results










share|improve this question
























  • Are the columns guaranteed to take one character?
    – Willem Van Onsem
    Nov 14 '18 at 19:43










  • @WillemVanOnsem Yes, I just updated the question , first column will alwasys take one character , second column can have multiple characters just like I did in my edit
    – Mighty
    Nov 14 '18 at 19:48
















0












0








0







I have a dataframe with following columns and index :



   first  sec
0 z 50
2 b 3
1 a 3
4 c 2
5 e 1


I want to print this plain output :



z 50
b 3
a 3
c 2
e 1


I have used to_string , but its not giving desired results , i have used some loops too , but nothing is giving desired results










share|improve this question















I have a dataframe with following columns and index :



   first  sec
0 z 50
2 b 3
1 a 3
4 c 2
5 e 1


I want to print this plain output :



z 50
b 3
a 3
c 2
e 1


I have used to_string , but its not giving desired results , i have used some loops too , but nothing is giving desired results







python python-3.x python-2.7 pandas






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 19:47

























asked Nov 14 '18 at 19:43









Mighty

706




706












  • Are the columns guaranteed to take one character?
    – Willem Van Onsem
    Nov 14 '18 at 19:43










  • @WillemVanOnsem Yes, I just updated the question , first column will alwasys take one character , second column can have multiple characters just like I did in my edit
    – Mighty
    Nov 14 '18 at 19:48




















  • Are the columns guaranteed to take one character?
    – Willem Van Onsem
    Nov 14 '18 at 19:43










  • @WillemVanOnsem Yes, I just updated the question , first column will alwasys take one character , second column can have multiple characters just like I did in my edit
    – Mighty
    Nov 14 '18 at 19:48


















Are the columns guaranteed to take one character?
– Willem Van Onsem
Nov 14 '18 at 19:43




Are the columns guaranteed to take one character?
– Willem Van Onsem
Nov 14 '18 at 19:43












@WillemVanOnsem Yes, I just updated the question , first column will alwasys take one character , second column can have multiple characters just like I did in my edit
– Mighty
Nov 14 '18 at 19:48






@WillemVanOnsem Yes, I just updated the question , first column will alwasys take one character , second column can have multiple characters just like I did in my edit
– Mighty
Nov 14 '18 at 19:48














1 Answer
1






active

oldest

votes


















2














Use to_string specifying header and index to be None



>>> print(df.to_string(header=None, index=None))

z 50
b 3
a 3
c 2
e 1




If you want exactly your output, you can play with the series by adding exactly one space and then your next series.



>>> x = df['first'].add(' ').add(df['sec'].astype(str)).to_string(index=None).replace('n ', 'n')

z 50
b 3
a 3
c 2
e 1





share|improve this answer























  • spaces are many , i want something like exactly in my question
    – Mighty
    Nov 14 '18 at 19:55










  • @Mighty you can play with the series.. will edit
    – RafaelC
    Nov 14 '18 at 20:04











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














Use to_string specifying header and index to be None



>>> print(df.to_string(header=None, index=None))

z 50
b 3
a 3
c 2
e 1




If you want exactly your output, you can play with the series by adding exactly one space and then your next series.



>>> x = df['first'].add(' ').add(df['sec'].astype(str)).to_string(index=None).replace('n ', 'n')

z 50
b 3
a 3
c 2
e 1





share|improve this answer























  • spaces are many , i want something like exactly in my question
    – Mighty
    Nov 14 '18 at 19:55










  • @Mighty you can play with the series.. will edit
    – RafaelC
    Nov 14 '18 at 20:04
















2














Use to_string specifying header and index to be None



>>> print(df.to_string(header=None, index=None))

z 50
b 3
a 3
c 2
e 1




If you want exactly your output, you can play with the series by adding exactly one space and then your next series.



>>> x = df['first'].add(' ').add(df['sec'].astype(str)).to_string(index=None).replace('n ', 'n')

z 50
b 3
a 3
c 2
e 1





share|improve this answer























  • spaces are many , i want something like exactly in my question
    – Mighty
    Nov 14 '18 at 19:55










  • @Mighty you can play with the series.. will edit
    – RafaelC
    Nov 14 '18 at 20:04














2












2








2






Use to_string specifying header and index to be None



>>> print(df.to_string(header=None, index=None))

z 50
b 3
a 3
c 2
e 1




If you want exactly your output, you can play with the series by adding exactly one space and then your next series.



>>> x = df['first'].add(' ').add(df['sec'].astype(str)).to_string(index=None).replace('n ', 'n')

z 50
b 3
a 3
c 2
e 1





share|improve this answer














Use to_string specifying header and index to be None



>>> print(df.to_string(header=None, index=None))

z 50
b 3
a 3
c 2
e 1




If you want exactly your output, you can play with the series by adding exactly one space and then your next series.



>>> x = df['first'].add(' ').add(df['sec'].astype(str)).to_string(index=None).replace('n ', 'n')

z 50
b 3
a 3
c 2
e 1






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 14 '18 at 20:05

























answered Nov 14 '18 at 19:51









RafaelC

26k82649




26k82649












  • spaces are many , i want something like exactly in my question
    – Mighty
    Nov 14 '18 at 19:55










  • @Mighty you can play with the series.. will edit
    – RafaelC
    Nov 14 '18 at 20:04


















  • spaces are many , i want something like exactly in my question
    – Mighty
    Nov 14 '18 at 19:55










  • @Mighty you can play with the series.. will edit
    – RafaelC
    Nov 14 '18 at 20:04
















spaces are many , i want something like exactly in my question
– Mighty
Nov 14 '18 at 19:55




spaces are many , i want something like exactly in my question
– Mighty
Nov 14 '18 at 19:55












@Mighty you can play with the series.. will edit
– RafaelC
Nov 14 '18 at 20:04




@Mighty you can play with the series.. will edit
– RafaelC
Nov 14 '18 at 20:04


















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