Updating form class based on input using database lookup












0














I have no clue where to start with this. Basically, I want the class of a input to change to has-success when a username that is in a database table called Username is equal to the string that the user has written. The current code for the form is:



<div class='container col-md-3 rounded p-5 mt-5 border'>
<form action="Authentication.php" method ="post">
<h3 class='text-center'>Please Login</h3>
<h5 class='pt-3'>Enter Username and Password</h5>
<div class="form-group mb-0">
<input class='form-control float-left mt-3 mb-1' placeholder="Username" type="text" name="username">
<br>
<input class='form-control float-left mb-3' placeholder="Password" type="password" name="password">
<br>
</div>
<div class="text-center">
<input type="submit" class='btn btn-primary btn-sx' value="Login">
</div>
</form>
</div>


So whenever anyone types in the field with placeholder="username" it needs to check whether that string matches with any in the column Username in the table Students and if it does update the class to success.



Thanks so much for the help,
Toby










share|improve this question




















  • 1




    Use an ajax request to PHP & change the class with pure js or jquery.
    – Chad
    Nov 15 '18 at 12:55










  • Possible duplicate of JQUERY AJAX - change class of $(this) in case of success
    – Chad
    Nov 15 '18 at 12:55
















0














I have no clue where to start with this. Basically, I want the class of a input to change to has-success when a username that is in a database table called Username is equal to the string that the user has written. The current code for the form is:



<div class='container col-md-3 rounded p-5 mt-5 border'>
<form action="Authentication.php" method ="post">
<h3 class='text-center'>Please Login</h3>
<h5 class='pt-3'>Enter Username and Password</h5>
<div class="form-group mb-0">
<input class='form-control float-left mt-3 mb-1' placeholder="Username" type="text" name="username">
<br>
<input class='form-control float-left mb-3' placeholder="Password" type="password" name="password">
<br>
</div>
<div class="text-center">
<input type="submit" class='btn btn-primary btn-sx' value="Login">
</div>
</form>
</div>


So whenever anyone types in the field with placeholder="username" it needs to check whether that string matches with any in the column Username in the table Students and if it does update the class to success.



Thanks so much for the help,
Toby










share|improve this question




















  • 1




    Use an ajax request to PHP & change the class with pure js or jquery.
    – Chad
    Nov 15 '18 at 12:55










  • Possible duplicate of JQUERY AJAX - change class of $(this) in case of success
    – Chad
    Nov 15 '18 at 12:55














0












0








0







I have no clue where to start with this. Basically, I want the class of a input to change to has-success when a username that is in a database table called Username is equal to the string that the user has written. The current code for the form is:



<div class='container col-md-3 rounded p-5 mt-5 border'>
<form action="Authentication.php" method ="post">
<h3 class='text-center'>Please Login</h3>
<h5 class='pt-3'>Enter Username and Password</h5>
<div class="form-group mb-0">
<input class='form-control float-left mt-3 mb-1' placeholder="Username" type="text" name="username">
<br>
<input class='form-control float-left mb-3' placeholder="Password" type="password" name="password">
<br>
</div>
<div class="text-center">
<input type="submit" class='btn btn-primary btn-sx' value="Login">
</div>
</form>
</div>


So whenever anyone types in the field with placeholder="username" it needs to check whether that string matches with any in the column Username in the table Students and if it does update the class to success.



Thanks so much for the help,
Toby










share|improve this question















I have no clue where to start with this. Basically, I want the class of a input to change to has-success when a username that is in a database table called Username is equal to the string that the user has written. The current code for the form is:



<div class='container col-md-3 rounded p-5 mt-5 border'>
<form action="Authentication.php" method ="post">
<h3 class='text-center'>Please Login</h3>
<h5 class='pt-3'>Enter Username and Password</h5>
<div class="form-group mb-0">
<input class='form-control float-left mt-3 mb-1' placeholder="Username" type="text" name="username">
<br>
<input class='form-control float-left mb-3' placeholder="Password" type="password" name="password">
<br>
</div>
<div class="text-center">
<input type="submit" class='btn btn-primary btn-sx' value="Login">
</div>
</form>
</div>


So whenever anyone types in the field with placeholder="username" it needs to check whether that string matches with any in the column Username in the table Students and if it does update the class to success.



Thanks so much for the help,
Toby







php jquery mysql bootstrap-4






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edited Nov 15 '18 at 13:08









bcperth

2,0011514




2,0011514










asked Nov 15 '18 at 12:51









Toby Dixon SmithToby Dixon Smith

359




359








  • 1




    Use an ajax request to PHP & change the class with pure js or jquery.
    – Chad
    Nov 15 '18 at 12:55










  • Possible duplicate of JQUERY AJAX - change class of $(this) in case of success
    – Chad
    Nov 15 '18 at 12:55














  • 1




    Use an ajax request to PHP & change the class with pure js or jquery.
    – Chad
    Nov 15 '18 at 12:55










  • Possible duplicate of JQUERY AJAX - change class of $(this) in case of success
    – Chad
    Nov 15 '18 at 12:55








1




1




Use an ajax request to PHP & change the class with pure js or jquery.
– Chad
Nov 15 '18 at 12:55




Use an ajax request to PHP & change the class with pure js or jquery.
– Chad
Nov 15 '18 at 12:55












Possible duplicate of JQUERY AJAX - change class of $(this) in case of success
– Chad
Nov 15 '18 at 12:55




Possible duplicate of JQUERY AJAX - change class of $(this) in case of success
– Chad
Nov 15 '18 at 12:55












1 Answer
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If the code above is in Authentication.php witch is called by the form, then where you check if $_POST has been submitted, initialize a $extraClass = '';
If (your_condition is true) $extraClass = 'success';



and down there in the form, add an



This way it will keep it empty if the condition si not met.






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    If the code above is in Authentication.php witch is called by the form, then where you check if $_POST has been submitted, initialize a $extraClass = '';
    If (your_condition is true) $extraClass = 'success';



    and down there in the form, add an



    This way it will keep it empty if the condition si not met.






    share|improve this answer


























      0














      If the code above is in Authentication.php witch is called by the form, then where you check if $_POST has been submitted, initialize a $extraClass = '';
      If (your_condition is true) $extraClass = 'success';



      and down there in the form, add an



      This way it will keep it empty if the condition si not met.






      share|improve this answer
























        0












        0








        0






        If the code above is in Authentication.php witch is called by the form, then where you check if $_POST has been submitted, initialize a $extraClass = '';
        If (your_condition is true) $extraClass = 'success';



        and down there in the form, add an



        This way it will keep it empty if the condition si not met.






        share|improve this answer












        If the code above is in Authentication.php witch is called by the form, then where you check if $_POST has been submitted, initialize a $extraClass = '';
        If (your_condition is true) $extraClass = 'success';



        and down there in the form, add an



        This way it will keep it empty if the condition si not met.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 13:12









        Robert ŞtefanRobert Ştefan

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