JPA Bi-directional parent-child relationship and repositories












0















I have a table called test_run. This table has an id called parent_run_id that references the parent test run (I have this because we rerun failed tests in their own run). This class works as desired, and returns both the parent and child run when I query for an id.



I want to find all the test runs without a child. This essentially means that I want the most recent test reruns, or the original if there is no rerun. However, the query that the JPA repository generates isn't even close to what it should be.



My class (simplified):



@Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
public class TestRun implements Serializable {
private static final long serialVersionUID = 0L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long testRunId;

@OneToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "parent_run_id", referencedColumnName = "testRunId")
@JsonManagedReference
private TestRun parentRun;

@OneToOne(fetch = FetchType.LAZY, mappedBy = "parentRun")
@JsonBackReference
private TestRun childRun;
}


My jpa repository method:



List<TestRun> getByChildRunIsNull();


The relevant portions of the query it generates:



select * from "qa_result".test_run test_run 
where test_run.test_run_id is null


Obviously, that where clause will never return anything, since test_run_id is a required field. There are plenty of testRuns that have a null childRun when I query for all of them, so at the very least it's treating my object the way I want when it reads it from the database.



Can I do this via a JPA repository? Or do I have to write my own query?



I cannot query for only those results with a parent, because we can rerun a rerun.










share|improve this question

























  • The way you've structured it, you would need a nested query. You're asking: SELECT p.* FROM Test_Run as p WHERE p.test_run_id NOT IN (SELECT c.test_run_id from TEST_RUN as c where c.parent_run_id IS NOT NULL); There may be a way to write that with Spring's method naming conventions, but you can certainly do it with a

    – sofend
    Nov 19 '18 at 23:45
















0















I have a table called test_run. This table has an id called parent_run_id that references the parent test run (I have this because we rerun failed tests in their own run). This class works as desired, and returns both the parent and child run when I query for an id.



I want to find all the test runs without a child. This essentially means that I want the most recent test reruns, or the original if there is no rerun. However, the query that the JPA repository generates isn't even close to what it should be.



My class (simplified):



@Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
public class TestRun implements Serializable {
private static final long serialVersionUID = 0L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long testRunId;

@OneToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "parent_run_id", referencedColumnName = "testRunId")
@JsonManagedReference
private TestRun parentRun;

@OneToOne(fetch = FetchType.LAZY, mappedBy = "parentRun")
@JsonBackReference
private TestRun childRun;
}


My jpa repository method:



List<TestRun> getByChildRunIsNull();


The relevant portions of the query it generates:



select * from "qa_result".test_run test_run 
where test_run.test_run_id is null


Obviously, that where clause will never return anything, since test_run_id is a required field. There are plenty of testRuns that have a null childRun when I query for all of them, so at the very least it's treating my object the way I want when it reads it from the database.



Can I do this via a JPA repository? Or do I have to write my own query?



I cannot query for only those results with a parent, because we can rerun a rerun.










share|improve this question

























  • The way you've structured it, you would need a nested query. You're asking: SELECT p.* FROM Test_Run as p WHERE p.test_run_id NOT IN (SELECT c.test_run_id from TEST_RUN as c where c.parent_run_id IS NOT NULL); There may be a way to write that with Spring's method naming conventions, but you can certainly do it with a

    – sofend
    Nov 19 '18 at 23:45














0












0








0








I have a table called test_run. This table has an id called parent_run_id that references the parent test run (I have this because we rerun failed tests in their own run). This class works as desired, and returns both the parent and child run when I query for an id.



I want to find all the test runs without a child. This essentially means that I want the most recent test reruns, or the original if there is no rerun. However, the query that the JPA repository generates isn't even close to what it should be.



My class (simplified):



@Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
public class TestRun implements Serializable {
private static final long serialVersionUID = 0L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long testRunId;

@OneToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "parent_run_id", referencedColumnName = "testRunId")
@JsonManagedReference
private TestRun parentRun;

@OneToOne(fetch = FetchType.LAZY, mappedBy = "parentRun")
@JsonBackReference
private TestRun childRun;
}


My jpa repository method:



List<TestRun> getByChildRunIsNull();


The relevant portions of the query it generates:



select * from "qa_result".test_run test_run 
where test_run.test_run_id is null


Obviously, that where clause will never return anything, since test_run_id is a required field. There are plenty of testRuns that have a null childRun when I query for all of them, so at the very least it's treating my object the way I want when it reads it from the database.



Can I do this via a JPA repository? Or do I have to write my own query?



I cannot query for only those results with a parent, because we can rerun a rerun.










share|improve this question
















I have a table called test_run. This table has an id called parent_run_id that references the parent test run (I have this because we rerun failed tests in their own run). This class works as desired, and returns both the parent and child run when I query for an id.



I want to find all the test runs without a child. This essentially means that I want the most recent test reruns, or the original if there is no rerun. However, the query that the JPA repository generates isn't even close to what it should be.



My class (simplified):



@Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
public class TestRun implements Serializable {
private static final long serialVersionUID = 0L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long testRunId;

@OneToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "parent_run_id", referencedColumnName = "testRunId")
@JsonManagedReference
private TestRun parentRun;

@OneToOne(fetch = FetchType.LAZY, mappedBy = "parentRun")
@JsonBackReference
private TestRun childRun;
}


My jpa repository method:



List<TestRun> getByChildRunIsNull();


The relevant portions of the query it generates:



select * from "qa_result".test_run test_run 
where test_run.test_run_id is null


Obviously, that where clause will never return anything, since test_run_id is a required field. There are plenty of testRuns that have a null childRun when I query for all of them, so at the very least it's treating my object the way I want when it reads it from the database.



Can I do this via a JPA repository? Or do I have to write my own query?



I cannot query for only those results with a parent, because we can rerun a rerun.







spring hibernate spring-data-jpa






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 15:10









Billy Frost

1,799198




1,799198










asked Nov 19 '18 at 23:04









Tyler MacMillanTyler MacMillan

447520




447520













  • The way you've structured it, you would need a nested query. You're asking: SELECT p.* FROM Test_Run as p WHERE p.test_run_id NOT IN (SELECT c.test_run_id from TEST_RUN as c where c.parent_run_id IS NOT NULL); There may be a way to write that with Spring's method naming conventions, but you can certainly do it with a

    – sofend
    Nov 19 '18 at 23:45



















  • The way you've structured it, you would need a nested query. You're asking: SELECT p.* FROM Test_Run as p WHERE p.test_run_id NOT IN (SELECT c.test_run_id from TEST_RUN as c where c.parent_run_id IS NOT NULL); There may be a way to write that with Spring's method naming conventions, but you can certainly do it with a

    – sofend
    Nov 19 '18 at 23:45

















The way you've structured it, you would need a nested query. You're asking: SELECT p.* FROM Test_Run as p WHERE p.test_run_id NOT IN (SELECT c.test_run_id from TEST_RUN as c where c.parent_run_id IS NOT NULL); There may be a way to write that with Spring's method naming conventions, but you can certainly do it with a

– sofend
Nov 19 '18 at 23:45





The way you've structured it, you would need a nested query. You're asking: SELECT p.* FROM Test_Run as p WHERE p.test_run_id NOT IN (SELECT c.test_run_id from TEST_RUN as c where c.parent_run_id IS NOT NULL); There may be a way to write that with Spring's method naming conventions, but you can certainly do it with a

– sofend
Nov 19 '18 at 23:45












0






active

oldest

votes











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53383896%2fjpa-bi-directional-parent-child-relationship-and-repositories%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53383896%2fjpa-bi-directional-parent-child-relationship-and-repositories%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

鏡平學校

ꓛꓣだゔៀៅຸ໢ທຮ໕໒ ,ໂ'໥໓າ໼ឨឲ៵៭ៈゎゔit''䖳𥁄卿' ☨₤₨こゎもょの;ꜹꟚꞖꞵꟅꞛေၦေɯ,ɨɡ𛃵𛁹ޝ޳ޠ޾,ޤޒޯ޾𫝒𫠁သ𛅤チョ'サノބޘދ𛁐ᶿᶇᶀᶋᶠ㨑㽹⻮ꧬ꧹؍۩وَؠ㇕㇃㇪ ㇦㇋㇋ṜẰᵡᴠ 軌ᵕ搜۳ٰޗޮ޷ސޯ𫖾𫅀ल, ꙭ꙰ꚅꙁꚊꞻꝔ꟠Ꝭㄤﺟޱސꧨꧼ꧴ꧯꧽ꧲ꧯ'⽹⽭⾁⿞⼳⽋២៩ញណើꩯꩤ꩸ꩮᶻᶺᶧᶂ𫳲𫪭𬸄𫵰𬖩𬫣𬊉ၲ𛅬㕦䬺𫝌𫝼,,𫟖𫞽ហៅ஫㆔ాఆఅꙒꚞꙍ,Ꙟ꙱エ ,ポテ,フࢰࢯ𫟠𫞶 𫝤𫟠ﺕﹱﻜﻣ𪵕𪭸𪻆𪾩𫔷ġ,ŧآꞪ꟥,ꞔꝻ♚☹⛵𛀌ꬷꭞȄƁƪƬșƦǙǗdžƝǯǧⱦⱰꓕꓢႋ神 ဴ၀க௭எ௫ឫោ ' េㇷㇴㇼ神ㇸㇲㇽㇴㇼㇻㇸ'ㇸㇿㇸㇹㇰㆣꓚꓤ₡₧ ㄨㄟ㄂ㄖㄎ໗ツڒذ₶।ऩछएोञयूटक़कयँृी,冬'𛅢𛅥ㇱㇵㇶ𥄥𦒽𠣧𠊓𧢖𥞘𩔋цѰㄠſtʯʭɿʆʗʍʩɷɛ,əʏダヵㄐㄘR{gỚṖḺờṠṫảḙḭᴮᵏᴘᵀᵷᵕᴜᴏᵾq﮲ﲿﴽﭙ軌ﰬﶚﶧ﫲Ҝжюїкӈㇴffצּ﬘﭅﬈軌'ffistfflſtffतभफɳɰʊɲʎ𛁱𛁖𛁮𛀉 𛂯𛀞నఋŀŲ 𫟲𫠖𫞺ຆຆ ໹້໕໗ๆทԊꧢꧠ꧰ꓱ⿝⼑ŎḬẃẖỐẅ ,ờỰỈỗﮊDžȩꭏꭎꬻ꭮ꬿꭖꭥꭅ㇭神 ⾈ꓵꓑ⺄㄄ㄪㄙㄅㄇstA۵䞽ॶ𫞑𫝄㇉㇇゜軌𩜛𩳠Jﻺ‚Üမ႕ႌႊၐၸဓၞၞၡ៸wyvtᶎᶪᶹစဎ꣡꣰꣢꣤ٗ؋لㇳㇾㇻㇱ㆐㆔,,㆟Ⱶヤマފ޼ޝަݿݞݠݷݐ',ݘ,ݪݙݵ𬝉𬜁𫝨𫞘くせぉて¼óû×ó£…𛅑הㄙくԗԀ5606神45,神796'𪤻𫞧ꓐ㄁ㄘɥɺꓵꓲ3''7034׉ⱦⱠˆ“𫝋ȍ,ꩲ軌꩷ꩶꩧꩫఞ۔فڱێظペサ神ナᴦᵑ47 9238їﻂ䐊䔉㠸﬎ffiﬣ,לּᴷᴦᵛᵽ,ᴨᵤ ᵸᵥᴗᵈꚏꚉꚟ⻆rtǟƴ𬎎

Why https connections are so slow when debugging (stepping over) in Java?