Label Is Not Defined
What is wrong here please help. It's writing lbl1 is not defined. I defined it already is the order is wrong how can I repair it? Everyday im having a problem like this could you help mee???
import tkinter
window = tkinter.Tk()
window.title("Calculator 2")
window.geometry("400x400")
def func1():
lbl1 = tkinter.Label(window, text="1")
lbl1.pack()
def func2():
lbl2 = tkinter.Label(window, text="+")
lbl2.pack()
def func3():
lbl3 = tkinter.Label(window, text="2")
lbl3.pack()
btn1 = tkinter.Button(window, text="1", command=func1)
btn2 = tkinter.Button(window, text="+", command=func2)
btn3 = tkinter.Button(window, text="2", command=func3)
btn1.pack()
btn2.pack()
btn3.pack()
def funclst():
if lbl1 == "1" and lbl2 == "+" and lbl3 == "2":
rstt = tkinter.Label(window, text=(int(lbl1) + int(lbl3)))
rstt.pack()
lst = tkinter.Button(window, text="Calculate", command=funclst)
lst.pack()
window.mainloop()
python tkinter
asked Nov 17 '18 at 12:09
BatiBati
12
add a comment |
What is wrong here please help. It's writing lbl1 is not defined. I defined it already is the order is wrong how can I repair it? Everyday im having a problem like this could you help mee???
import tkinter
window = tkinter.Tk()
window.title("Calculator 2")
window.geometry("400x400")
def func1():
lbl1 = tkinter.Label(window, text="1")
lbl1.pack()
def func2():
lbl2 = tkinter.Label(window, text="+")
lbl2.pack()
def func3():
lbl3 = tkinter.Label(window, text="2")
lbl3.pack()
btn1 = tkinter.Button(window, text="1", command=func1)
btn2 = tkinter.Button(window, text="+", command=func2)
btn3 = tkinter.Button(window, text="2", command=func3)
btn1.pack()
btn2.pack()
btn3.pack()
def funclst():
if lbl1 == "1" and lbl2 == "+" and lbl3 == "2":
rstt = tkinter.Label(window, text=(int(lbl1) + int(lbl3)))
rstt.pack()
lst = tkinter.Button(window, text="Calculate", command=funclst)
lst.pack()
window.mainloop()
python tkinter
asked Nov 17 '18 at 12:09
BatiBati
12
Please include the complete error traceback, don't just cite approximately the error message.
– Thierry Lathuille
Nov 17 '18 at 12:11
add a comment |
What is wrong here please help. It's writing lbl1 is not defined. I defined it already is the order is wrong how can I repair it? Everyday im having a problem like this could you help mee???
import tkinter
window = tkinter.Tk()
window.title("Calculator 2")
window.geometry("400x400")
def func1():
lbl1 = tkinter.Label(window, text="1")
lbl1.pack()
def func2():
lbl2 = tkinter.Label(window, text="+")
lbl2.pack()
def func3():
lbl3 = tkinter.Label(window, text="2")
lbl3.pack()
btn1 = tkinter.Button(window, text="1", command=func1)
btn2 = tkinter.Button(window, text="+", command=func2)
btn3 = tkinter.Button(window, text="2", command=func3)
btn1.pack()
btn2.pack()
btn3.pack()
def funclst():
if lbl1 == "1" and lbl2 == "+" and lbl3 == "2":
rstt = tkinter.Label(window, text=(int(lbl1) + int(lbl3)))
rstt.pack()
lst = tkinter.Button(window, text="Calculate", command=funclst)
lst.pack()
window.mainloop()
python tkinter
asked Nov 17 '18 at 12:09
BatiBati
12
What is wrong here please help. It's writing lbl1 is not defined. I defined it already is the order is wrong how can I repair it? Everyday im having a problem like this could you help mee???
import tkinter
window = tkinter.Tk()
window.title("Calculator 2")
window.geometry("400x400")
def func1():
lbl1 = tkinter.Label(window, text="1")
lbl1.pack()
def func2():
lbl2 = tkinter.Label(window, text="+")
lbl2.pack()
def func3():
lbl3 = tkinter.Label(window, text="2")
lbl3.pack()
btn1 = tkinter.Button(window, text="1", command=func1)
btn2 = tkinter.Button(window, text="+", command=func2)
btn3 = tkinter.Button(window, text="2", command=func3)
btn1.pack()
btn2.pack()
btn3.pack()
def funclst():
if lbl1 == "1" and lbl2 == "+" and lbl3 == "2":
rstt = tkinter.Label(window, text=(int(lbl1) + int(lbl3)))
rstt.pack()
lst = tkinter.Button(window, text="Calculate", command=funclst)
lst.pack()
window.mainloop()
python tkinter
python tkinter
asked Nov 17 '18 at 12:09
BatiBati
12
asked Nov 17 '18 at 12:09
BatiBati
12
edited Nov 17 '18 at 12:25
Bati
asked Nov 17 '18 at 12:09
BatiBati
12
asked Nov 17 '18 at 12:09
BatiBati
12
asked Nov 17 '18 at 12:09
BatiBati
12
12
Please include the complete error traceback, don't just cite approximately the error message.
– Thierry Lathuille
Nov 17 '18 at 12:11
add a comment |
Please include the complete error traceback, don't just cite approximately the error message.
– Thierry Lathuille
Nov 17 '18 at 12:11
Please include the complete error traceback, don't just cite approximately the error message.
– Thierry Lathuille
Nov 17 '18 at 12:11
Please include the complete error traceback, don't just cite approximately the error message.
– Thierry Lathuille
Nov 17 '18 at 12:11
add a comment |
1 Answer
1
active
oldest
votes
You create the labels inside functions. When the function ends the names assigned to the labels are garbage collected. Later when you try to access the variables in the if statement they are not defined in the global scope.
Also; the if statements checks if lbl1 == "1" which will not work as lbl1 is the reference to the label and not to the text inside the label. The text can be accessed through lbl1['text'] or lbl1.cget("text")
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You create the labels inside functions. When the function ends the names assigned to the labels are garbage collected. Later when you try to access the variables in the if statement they are not defined in the global scope.
Also; the if statements checks if lbl1 == "1" which will not work as lbl1 is the reference to the label and not to the text inside the label. The text can be accessed through lbl1['text'] or lbl1.cget("text")
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
add a comment |
You create the labels inside functions. When the function ends the names assigned to the labels are garbage collected. Later when you try to access the variables in the if statement they are not defined in the global scope.
Also; the if statements checks if lbl1 == "1" which will not work as lbl1 is the reference to the label and not to the text inside the label. The text can be accessed through lbl1['text'] or lbl1.cget("text")
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
add a comment |
You create the labels inside functions. When the function ends the names assigned to the labels are garbage collected. Later when you try to access the variables in the if statement they are not defined in the global scope.
Also; the if statements checks if lbl1 == "1" which will not work as lbl1 is the reference to the label and not to the text inside the label. The text can be accessed through lbl1['text'] or lbl1.cget("text")
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
You create the labels inside functions. When the function ends the names assigned to the labels are garbage collected. Later when you try to access the variables in the if statement they are not defined in the global scope.
Also; the if statements checks if lbl1 == "1" which will not work as lbl1 is the reference to the label and not to the text inside the label. The text can be accessed through lbl1['text'] or lbl1.cget("text")
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
answered Nov 20 '18 at 5:34
figbeamfigbeam
3,0851310
3,0851310
add a comment |
add a comment |
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Please include the complete error traceback, don't just cite approximately the error message.
– Thierry Lathuille
Nov 17 '18 at 12:11