Getting second highest Salary value in MySQL












1















In a given question,




Write a SQL query to get the second highest salary from the Employee table.




+----+--------+
| Id | Salary |
+----+--------+
| 1 | 100 |
| 2 | 200 |
| 3 | 300 |
+----+--------+



For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.




+---------------------+
| SecondHighestSalary |
+---------------------+
| 200 |
+---------------------+




I wrote a code for this question, however, the expected output is different.



My Code:



SELECT
CASE
WHEN COUNT(*) = 1 THEN NULL
ELSE (SELECT Salary FROM Employee HAVING Salary < MAX(Salary) ORDER BY Salary DESC LIMIT 1)
END AS SecondHighestSalary
FROM Employee;


I think there's something wrong with my code but I cannot find what is the actual problem here. My code returns 100 not 200. What have I gotten wrong?



+---------------------+
| SecondHighestSalary |
+---------------------+
| 100 |
+---------------------+









share|improve this question

























  • You can get nth highest record visit stackoverflow.com/a/26732513/2893413

    – Sadikhasan
    Nov 21 '18 at 6:57
















1















In a given question,




Write a SQL query to get the second highest salary from the Employee table.




+----+--------+
| Id | Salary |
+----+--------+
| 1 | 100 |
| 2 | 200 |
| 3 | 300 |
+----+--------+



For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.




+---------------------+
| SecondHighestSalary |
+---------------------+
| 200 |
+---------------------+




I wrote a code for this question, however, the expected output is different.



My Code:



SELECT
CASE
WHEN COUNT(*) = 1 THEN NULL
ELSE (SELECT Salary FROM Employee HAVING Salary < MAX(Salary) ORDER BY Salary DESC LIMIT 1)
END AS SecondHighestSalary
FROM Employee;


I think there's something wrong with my code but I cannot find what is the actual problem here. My code returns 100 not 200. What have I gotten wrong?



+---------------------+
| SecondHighestSalary |
+---------------------+
| 100 |
+---------------------+









share|improve this question

























  • You can get nth highest record visit stackoverflow.com/a/26732513/2893413

    – Sadikhasan
    Nov 21 '18 at 6:57














1












1








1








In a given question,




Write a SQL query to get the second highest salary from the Employee table.




+----+--------+
| Id | Salary |
+----+--------+
| 1 | 100 |
| 2 | 200 |
| 3 | 300 |
+----+--------+



For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.




+---------------------+
| SecondHighestSalary |
+---------------------+
| 200 |
+---------------------+




I wrote a code for this question, however, the expected output is different.



My Code:



SELECT
CASE
WHEN COUNT(*) = 1 THEN NULL
ELSE (SELECT Salary FROM Employee HAVING Salary < MAX(Salary) ORDER BY Salary DESC LIMIT 1)
END AS SecondHighestSalary
FROM Employee;


I think there's something wrong with my code but I cannot find what is the actual problem here. My code returns 100 not 200. What have I gotten wrong?



+---------------------+
| SecondHighestSalary |
+---------------------+
| 100 |
+---------------------+









share|improve this question
















In a given question,




Write a SQL query to get the second highest salary from the Employee table.




+----+--------+
| Id | Salary |
+----+--------+
| 1 | 100 |
| 2 | 200 |
| 3 | 300 |
+----+--------+



For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.




+---------------------+
| SecondHighestSalary |
+---------------------+
| 200 |
+---------------------+




I wrote a code for this question, however, the expected output is different.



My Code:



SELECT
CASE
WHEN COUNT(*) = 1 THEN NULL
ELSE (SELECT Salary FROM Employee HAVING Salary < MAX(Salary) ORDER BY Salary DESC LIMIT 1)
END AS SecondHighestSalary
FROM Employee;


I think there's something wrong with my code but I cannot find what is the actual problem here. My code returns 100 not 200. What have I gotten wrong?



+---------------------+
| SecondHighestSalary |
+---------------------+
| 100 |
+---------------------+






mysql sql subquery






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 8:26









Strawberry

26.7k83250




26.7k83250










asked Nov 21 '18 at 6:50









Backrub32Backrub32

373322




373322













  • You can get nth highest record visit stackoverflow.com/a/26732513/2893413

    – Sadikhasan
    Nov 21 '18 at 6:57



















  • You can get nth highest record visit stackoverflow.com/a/26732513/2893413

    – Sadikhasan
    Nov 21 '18 at 6:57

















You can get nth highest record visit stackoverflow.com/a/26732513/2893413

– Sadikhasan
Nov 21 '18 at 6:57





You can get nth highest record visit stackoverflow.com/a/26732513/2893413

– Sadikhasan
Nov 21 '18 at 6:57












5 Answers
5






active

oldest

votes


















2














You can utilize LIMIT {[offset,] row_count}. Refer https://dev.mysql.com/doc/refman/8.0/en/select.html



Order by Salary in descending order, and get the second row by defining OFFSET as 1. We will use DISTINCT on Salary as there is a possibility to have multiple rows for the highest salary.



SELECT DISTINCT
Salary
FROM Employee
ORDER BY Salary DESC
LIMIT 1,1





share|improve this answer


























  • @Sadikhasan how does it even matter, as OP only wants the salary figure, not the full row.

    – Madhur Bhaiya
    Nov 21 '18 at 6:56











  • Thank you for your answer. But I tried this and this does not return null when there's only one employee. I think maybe adding IFNULL() would do?

    – Backrub32
    Nov 21 '18 at 7:20













  • @Poream3387 hmm.. let me test. I havent tested it.

    – Madhur Bhaiya
    Nov 21 '18 at 7:23











  • @Poream3387 it returns no results: db-fiddle.com/f/e1Efjj6SY5xVrTEuJ9oP4j/0 - It is pretty much equivalent to getting null. You can handle this in application code (eg: PHP), when no rows are returned.

    – Madhur Bhaiya
    Nov 21 '18 at 7:26











  • Oh, got it thanks!

    – Backrub32
    Nov 21 '18 at 8:30



















2














You can try below



SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





share|improve this answer































    1














    Try that out:



    SELECT salary FROM Employee ORDER BY salary DESC LIMIT 1,1


    or to a deeper approach you can use something like:



    SELECT salary FROM Employee GROUP BY salary ORDER BY salary DESC LIMIT 1,1


    All that queries have high performance, since they does not have any subqueries.






    share|improve this answer


























    • how it will work without order by clause

      – fa06
      Nov 21 '18 at 7:02











    • You was right fa06, I just edited.

      – rod.poli.diniz
      Nov 21 '18 at 7:12



















    0














    If you want to display a empty_row(null) in case there is no highest salary then the following does it, if there is a value then it gets shown



    select (select salary
    from Employee ORDER BY salary DESC LIMIT 1,1
    ) as x





    share|improve this answer
























    • I don't understand the point of the wrapper

      – Strawberry
      Nov 21 '18 at 8:23











    • The OP wanted to return a row with "null" value in case there is no second highest salary.. Without the "wrapper, the query would return "no_rows_returned" or an empty record set.

      – George Joseph
      Nov 21 '18 at 8:33













    • Right, got it!!

      – Strawberry
      Nov 21 '18 at 9:30



















    0














    Here is the solution.



    SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





    share|improve this answer























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      5 Answers
      5






      active

      oldest

      votes








      5 Answers
      5






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      You can utilize LIMIT {[offset,] row_count}. Refer https://dev.mysql.com/doc/refman/8.0/en/select.html



      Order by Salary in descending order, and get the second row by defining OFFSET as 1. We will use DISTINCT on Salary as there is a possibility to have multiple rows for the highest salary.



      SELECT DISTINCT
      Salary
      FROM Employee
      ORDER BY Salary DESC
      LIMIT 1,1





      share|improve this answer


























      • @Sadikhasan how does it even matter, as OP only wants the salary figure, not the full row.

        – Madhur Bhaiya
        Nov 21 '18 at 6:56











      • Thank you for your answer. But I tried this and this does not return null when there's only one employee. I think maybe adding IFNULL() would do?

        – Backrub32
        Nov 21 '18 at 7:20













      • @Poream3387 hmm.. let me test. I havent tested it.

        – Madhur Bhaiya
        Nov 21 '18 at 7:23











      • @Poream3387 it returns no results: db-fiddle.com/f/e1Efjj6SY5xVrTEuJ9oP4j/0 - It is pretty much equivalent to getting null. You can handle this in application code (eg: PHP), when no rows are returned.

        – Madhur Bhaiya
        Nov 21 '18 at 7:26











      • Oh, got it thanks!

        – Backrub32
        Nov 21 '18 at 8:30
















      2














      You can utilize LIMIT {[offset,] row_count}. Refer https://dev.mysql.com/doc/refman/8.0/en/select.html



      Order by Salary in descending order, and get the second row by defining OFFSET as 1. We will use DISTINCT on Salary as there is a possibility to have multiple rows for the highest salary.



      SELECT DISTINCT
      Salary
      FROM Employee
      ORDER BY Salary DESC
      LIMIT 1,1





      share|improve this answer


























      • @Sadikhasan how does it even matter, as OP only wants the salary figure, not the full row.

        – Madhur Bhaiya
        Nov 21 '18 at 6:56











      • Thank you for your answer. But I tried this and this does not return null when there's only one employee. I think maybe adding IFNULL() would do?

        – Backrub32
        Nov 21 '18 at 7:20













      • @Poream3387 hmm.. let me test. I havent tested it.

        – Madhur Bhaiya
        Nov 21 '18 at 7:23











      • @Poream3387 it returns no results: db-fiddle.com/f/e1Efjj6SY5xVrTEuJ9oP4j/0 - It is pretty much equivalent to getting null. You can handle this in application code (eg: PHP), when no rows are returned.

        – Madhur Bhaiya
        Nov 21 '18 at 7:26











      • Oh, got it thanks!

        – Backrub32
        Nov 21 '18 at 8:30














      2












      2








      2







      You can utilize LIMIT {[offset,] row_count}. Refer https://dev.mysql.com/doc/refman/8.0/en/select.html



      Order by Salary in descending order, and get the second row by defining OFFSET as 1. We will use DISTINCT on Salary as there is a possibility to have multiple rows for the highest salary.



      SELECT DISTINCT
      Salary
      FROM Employee
      ORDER BY Salary DESC
      LIMIT 1,1





      share|improve this answer















      You can utilize LIMIT {[offset,] row_count}. Refer https://dev.mysql.com/doc/refman/8.0/en/select.html



      Order by Salary in descending order, and get the second row by defining OFFSET as 1. We will use DISTINCT on Salary as there is a possibility to have multiple rows for the highest salary.



      SELECT DISTINCT
      Salary
      FROM Employee
      ORDER BY Salary DESC
      LIMIT 1,1






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 21 '18 at 7:23

























      answered Nov 21 '18 at 6:52









      Madhur BhaiyaMadhur Bhaiya

      19.6k62236




      19.6k62236













      • @Sadikhasan how does it even matter, as OP only wants the salary figure, not the full row.

        – Madhur Bhaiya
        Nov 21 '18 at 6:56











      • Thank you for your answer. But I tried this and this does not return null when there's only one employee. I think maybe adding IFNULL() would do?

        – Backrub32
        Nov 21 '18 at 7:20













      • @Poream3387 hmm.. let me test. I havent tested it.

        – Madhur Bhaiya
        Nov 21 '18 at 7:23











      • @Poream3387 it returns no results: db-fiddle.com/f/e1Efjj6SY5xVrTEuJ9oP4j/0 - It is pretty much equivalent to getting null. You can handle this in application code (eg: PHP), when no rows are returned.

        – Madhur Bhaiya
        Nov 21 '18 at 7:26











      • Oh, got it thanks!

        – Backrub32
        Nov 21 '18 at 8:30



















      • @Sadikhasan how does it even matter, as OP only wants the salary figure, not the full row.

        – Madhur Bhaiya
        Nov 21 '18 at 6:56











      • Thank you for your answer. But I tried this and this does not return null when there's only one employee. I think maybe adding IFNULL() would do?

        – Backrub32
        Nov 21 '18 at 7:20













      • @Poream3387 hmm.. let me test. I havent tested it.

        – Madhur Bhaiya
        Nov 21 '18 at 7:23











      • @Poream3387 it returns no results: db-fiddle.com/f/e1Efjj6SY5xVrTEuJ9oP4j/0 - It is pretty much equivalent to getting null. You can handle this in application code (eg: PHP), when no rows are returned.

        – Madhur Bhaiya
        Nov 21 '18 at 7:26











      • Oh, got it thanks!

        – Backrub32
        Nov 21 '18 at 8:30

















      @Sadikhasan how does it even matter, as OP only wants the salary figure, not the full row.

      – Madhur Bhaiya
      Nov 21 '18 at 6:56





      @Sadikhasan how does it even matter, as OP only wants the salary figure, not the full row.

      – Madhur Bhaiya
      Nov 21 '18 at 6:56













      Thank you for your answer. But I tried this and this does not return null when there's only one employee. I think maybe adding IFNULL() would do?

      – Backrub32
      Nov 21 '18 at 7:20







      Thank you for your answer. But I tried this and this does not return null when there's only one employee. I think maybe adding IFNULL() would do?

      – Backrub32
      Nov 21 '18 at 7:20















      @Poream3387 hmm.. let me test. I havent tested it.

      – Madhur Bhaiya
      Nov 21 '18 at 7:23





      @Poream3387 hmm.. let me test. I havent tested it.

      – Madhur Bhaiya
      Nov 21 '18 at 7:23













      @Poream3387 it returns no results: db-fiddle.com/f/e1Efjj6SY5xVrTEuJ9oP4j/0 - It is pretty much equivalent to getting null. You can handle this in application code (eg: PHP), when no rows are returned.

      – Madhur Bhaiya
      Nov 21 '18 at 7:26





      @Poream3387 it returns no results: db-fiddle.com/f/e1Efjj6SY5xVrTEuJ9oP4j/0 - It is pretty much equivalent to getting null. You can handle this in application code (eg: PHP), when no rows are returned.

      – Madhur Bhaiya
      Nov 21 '18 at 7:26













      Oh, got it thanks!

      – Backrub32
      Nov 21 '18 at 8:30





      Oh, got it thanks!

      – Backrub32
      Nov 21 '18 at 8:30













      2














      You can try below



      SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





      share|improve this answer




























        2














        You can try below



        SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





        share|improve this answer


























          2












          2








          2







          You can try below



          SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





          share|improve this answer













          You can try below



          SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 21 '18 at 6:53









          fa06fa06

          16.8k21018




          16.8k21018























              1














              Try that out:



              SELECT salary FROM Employee ORDER BY salary DESC LIMIT 1,1


              or to a deeper approach you can use something like:



              SELECT salary FROM Employee GROUP BY salary ORDER BY salary DESC LIMIT 1,1


              All that queries have high performance, since they does not have any subqueries.






              share|improve this answer


























              • how it will work without order by clause

                – fa06
                Nov 21 '18 at 7:02











              • You was right fa06, I just edited.

                – rod.poli.diniz
                Nov 21 '18 at 7:12
















              1














              Try that out:



              SELECT salary FROM Employee ORDER BY salary DESC LIMIT 1,1


              or to a deeper approach you can use something like:



              SELECT salary FROM Employee GROUP BY salary ORDER BY salary DESC LIMIT 1,1


              All that queries have high performance, since they does not have any subqueries.






              share|improve this answer


























              • how it will work without order by clause

                – fa06
                Nov 21 '18 at 7:02











              • You was right fa06, I just edited.

                – rod.poli.diniz
                Nov 21 '18 at 7:12














              1












              1








              1







              Try that out:



              SELECT salary FROM Employee ORDER BY salary DESC LIMIT 1,1


              or to a deeper approach you can use something like:



              SELECT salary FROM Employee GROUP BY salary ORDER BY salary DESC LIMIT 1,1


              All that queries have high performance, since they does not have any subqueries.






              share|improve this answer















              Try that out:



              SELECT salary FROM Employee ORDER BY salary DESC LIMIT 1,1


              or to a deeper approach you can use something like:



              SELECT salary FROM Employee GROUP BY salary ORDER BY salary DESC LIMIT 1,1


              All that queries have high performance, since they does not have any subqueries.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 21 '18 at 7:11

























              answered Nov 21 '18 at 6:58









              rod.poli.dinizrod.poli.diniz

              116118




              116118













              • how it will work without order by clause

                – fa06
                Nov 21 '18 at 7:02











              • You was right fa06, I just edited.

                – rod.poli.diniz
                Nov 21 '18 at 7:12



















              • how it will work without order by clause

                – fa06
                Nov 21 '18 at 7:02











              • You was right fa06, I just edited.

                – rod.poli.diniz
                Nov 21 '18 at 7:12

















              how it will work without order by clause

              – fa06
              Nov 21 '18 at 7:02





              how it will work without order by clause

              – fa06
              Nov 21 '18 at 7:02













              You was right fa06, I just edited.

              – rod.poli.diniz
              Nov 21 '18 at 7:12





              You was right fa06, I just edited.

              – rod.poli.diniz
              Nov 21 '18 at 7:12











              0














              If you want to display a empty_row(null) in case there is no highest salary then the following does it, if there is a value then it gets shown



              select (select salary
              from Employee ORDER BY salary DESC LIMIT 1,1
              ) as x





              share|improve this answer
























              • I don't understand the point of the wrapper

                – Strawberry
                Nov 21 '18 at 8:23











              • The OP wanted to return a row with "null" value in case there is no second highest salary.. Without the "wrapper, the query would return "no_rows_returned" or an empty record set.

                – George Joseph
                Nov 21 '18 at 8:33













              • Right, got it!!

                – Strawberry
                Nov 21 '18 at 9:30
















              0














              If you want to display a empty_row(null) in case there is no highest salary then the following does it, if there is a value then it gets shown



              select (select salary
              from Employee ORDER BY salary DESC LIMIT 1,1
              ) as x





              share|improve this answer
























              • I don't understand the point of the wrapper

                – Strawberry
                Nov 21 '18 at 8:23











              • The OP wanted to return a row with "null" value in case there is no second highest salary.. Without the "wrapper, the query would return "no_rows_returned" or an empty record set.

                – George Joseph
                Nov 21 '18 at 8:33













              • Right, got it!!

                – Strawberry
                Nov 21 '18 at 9:30














              0












              0








              0







              If you want to display a empty_row(null) in case there is no highest salary then the following does it, if there is a value then it gets shown



              select (select salary
              from Employee ORDER BY salary DESC LIMIT 1,1
              ) as x





              share|improve this answer













              If you want to display a empty_row(null) in case there is no highest salary then the following does it, if there is a value then it gets shown



              select (select salary
              from Employee ORDER BY salary DESC LIMIT 1,1
              ) as x






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 21 '18 at 8:21









              George JosephGeorge Joseph

              1,590510




              1,590510













              • I don't understand the point of the wrapper

                – Strawberry
                Nov 21 '18 at 8:23











              • The OP wanted to return a row with "null" value in case there is no second highest salary.. Without the "wrapper, the query would return "no_rows_returned" or an empty record set.

                – George Joseph
                Nov 21 '18 at 8:33













              • Right, got it!!

                – Strawberry
                Nov 21 '18 at 9:30



















              • I don't understand the point of the wrapper

                – Strawberry
                Nov 21 '18 at 8:23











              • The OP wanted to return a row with "null" value in case there is no second highest salary.. Without the "wrapper, the query would return "no_rows_returned" or an empty record set.

                – George Joseph
                Nov 21 '18 at 8:33













              • Right, got it!!

                – Strawberry
                Nov 21 '18 at 9:30

















              I don't understand the point of the wrapper

              – Strawberry
              Nov 21 '18 at 8:23





              I don't understand the point of the wrapper

              – Strawberry
              Nov 21 '18 at 8:23













              The OP wanted to return a row with "null" value in case there is no second highest salary.. Without the "wrapper, the query would return "no_rows_returned" or an empty record set.

              – George Joseph
              Nov 21 '18 at 8:33







              The OP wanted to return a row with "null" value in case there is no second highest salary.. Without the "wrapper, the query would return "no_rows_returned" or an empty record set.

              – George Joseph
              Nov 21 '18 at 8:33















              Right, got it!!

              – Strawberry
              Nov 21 '18 at 9:30





              Right, got it!!

              – Strawberry
              Nov 21 '18 at 9:30











              0














              Here is the solution.



              SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





              share|improve this answer




























                0














                Here is the solution.



                SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





                share|improve this answer


























                  0












                  0








                  0







                  Here is the solution.



                  SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);





                  share|improve this answer













                  Here is the solution.



                  SELECT MAX(salary) From Employee WHERE salary < ( SELECT Max(salary) FROM Employee);






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 21 '18 at 9:20









                  Sahil AnandSahil Anand

                  1395




                  1395






























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