Convert TensorFlow string to python string












10















I am aware that in TensorFlow, a tf.string tensor is basically a byte string. I need to do some operation with a filename which is stored in a queue using tf.train.string_input_producer().



A small snippet is shown below :



 key, value = reader.read(filename_queue)
filename = value.eval(session=sess)
print(filename)


However as a byte string it gives an output like the following :



b'xffxd8xffxe0x00x10JFIFx00x01x01x00x00x01x00x01x00x00xffxdbx00Cx00x08x06x06x07x06x05x08x07x07x07ttx08'


I tried to convert using



filename = tf.decode_raw(filename, tf.uint8)
filename = ''.join(chr(i) for i in filename)


However Tensor objects are not iterable and hence this fails.



Where am I going wrong ?



Is it a missing feature in TensorFlow that tf.string be converted to a Python string easily , or is there some other feature I am not aware about ?



More Info



The filename_queue has been prepared as follows :



train_set = ['file1.jpg', 'file2.jpg'] # Truncated for illustration
filename_queue = tf.train.string_input_producer(train_set, num_epochs=10, seed=0, capacity=1000)









share|improve this question

























  • If you'd like to work with the string in Python, you need to execute the TensorFlow graph first.

    – Allen Lavoie
    Feb 9 '17 at 20:53






  • 1





    As you can see I have executed the graph inside a session.

    – Ujjwal
    Feb 9 '17 at 20:59











  • Your second approach is fine (decode_raw), you just need to evaluate the Tensor first. Although I have a feeling the reason you're not getting the result you want in the first approach is that this is binary data rather than a sensible filename.

    – Allen Lavoie
    Feb 9 '17 at 21:05











  • The tensor has been evaluated using eval() . After that when I use decode_raw, I get the error as stated in the question. As to the validity of the data, it is valid since the tf.train.string_input_producer() has been fed using a list of python strings ( which are valid filenames).

    – Ujjwal
    Feb 9 '17 at 21:36






  • 1





    Hi, @Ujjwal, have you ever solved this problem? I'm looking for the solution. Thanks.

    – mining
    Jun 13 '17 at 22:12
















10















I am aware that in TensorFlow, a tf.string tensor is basically a byte string. I need to do some operation with a filename which is stored in a queue using tf.train.string_input_producer().



A small snippet is shown below :



 key, value = reader.read(filename_queue)
filename = value.eval(session=sess)
print(filename)


However as a byte string it gives an output like the following :



b'xffxd8xffxe0x00x10JFIFx00x01x01x00x00x01x00x01x00x00xffxdbx00Cx00x08x06x06x07x06x05x08x07x07x07ttx08'


I tried to convert using



filename = tf.decode_raw(filename, tf.uint8)
filename = ''.join(chr(i) for i in filename)


However Tensor objects are not iterable and hence this fails.



Where am I going wrong ?



Is it a missing feature in TensorFlow that tf.string be converted to a Python string easily , or is there some other feature I am not aware about ?



More Info



The filename_queue has been prepared as follows :



train_set = ['file1.jpg', 'file2.jpg'] # Truncated for illustration
filename_queue = tf.train.string_input_producer(train_set, num_epochs=10, seed=0, capacity=1000)









share|improve this question

























  • If you'd like to work with the string in Python, you need to execute the TensorFlow graph first.

    – Allen Lavoie
    Feb 9 '17 at 20:53






  • 1





    As you can see I have executed the graph inside a session.

    – Ujjwal
    Feb 9 '17 at 20:59











  • Your second approach is fine (decode_raw), you just need to evaluate the Tensor first. Although I have a feeling the reason you're not getting the result you want in the first approach is that this is binary data rather than a sensible filename.

    – Allen Lavoie
    Feb 9 '17 at 21:05











  • The tensor has been evaluated using eval() . After that when I use decode_raw, I get the error as stated in the question. As to the validity of the data, it is valid since the tf.train.string_input_producer() has been fed using a list of python strings ( which are valid filenames).

    – Ujjwal
    Feb 9 '17 at 21:36






  • 1





    Hi, @Ujjwal, have you ever solved this problem? I'm looking for the solution. Thanks.

    – mining
    Jun 13 '17 at 22:12














10












10








10


2






I am aware that in TensorFlow, a tf.string tensor is basically a byte string. I need to do some operation with a filename which is stored in a queue using tf.train.string_input_producer().



A small snippet is shown below :



 key, value = reader.read(filename_queue)
filename = value.eval(session=sess)
print(filename)


However as a byte string it gives an output like the following :



b'xffxd8xffxe0x00x10JFIFx00x01x01x00x00x01x00x01x00x00xffxdbx00Cx00x08x06x06x07x06x05x08x07x07x07ttx08'


I tried to convert using



filename = tf.decode_raw(filename, tf.uint8)
filename = ''.join(chr(i) for i in filename)


However Tensor objects are not iterable and hence this fails.



Where am I going wrong ?



Is it a missing feature in TensorFlow that tf.string be converted to a Python string easily , or is there some other feature I am not aware about ?



More Info



The filename_queue has been prepared as follows :



train_set = ['file1.jpg', 'file2.jpg'] # Truncated for illustration
filename_queue = tf.train.string_input_producer(train_set, num_epochs=10, seed=0, capacity=1000)









share|improve this question
















I am aware that in TensorFlow, a tf.string tensor is basically a byte string. I need to do some operation with a filename which is stored in a queue using tf.train.string_input_producer().



A small snippet is shown below :



 key, value = reader.read(filename_queue)
filename = value.eval(session=sess)
print(filename)


However as a byte string it gives an output like the following :



b'xffxd8xffxe0x00x10JFIFx00x01x01x00x00x01x00x01x00x00xffxdbx00Cx00x08x06x06x07x06x05x08x07x07x07ttx08'


I tried to convert using



filename = tf.decode_raw(filename, tf.uint8)
filename = ''.join(chr(i) for i in filename)


However Tensor objects are not iterable and hence this fails.



Where am I going wrong ?



Is it a missing feature in TensorFlow that tf.string be converted to a Python string easily , or is there some other feature I am not aware about ?



More Info



The filename_queue has been prepared as follows :



train_set = ['file1.jpg', 'file2.jpg'] # Truncated for illustration
filename_queue = tf.train.string_input_producer(train_set, num_epochs=10, seed=0, capacity=1000)






python tensorflow






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edited Nov 21 '18 at 19:09









Giovan Cruz

134114




134114










asked Feb 9 '17 at 19:07









UjjwalUjjwal

889626




889626













  • If you'd like to work with the string in Python, you need to execute the TensorFlow graph first.

    – Allen Lavoie
    Feb 9 '17 at 20:53






  • 1





    As you can see I have executed the graph inside a session.

    – Ujjwal
    Feb 9 '17 at 20:59











  • Your second approach is fine (decode_raw), you just need to evaluate the Tensor first. Although I have a feeling the reason you're not getting the result you want in the first approach is that this is binary data rather than a sensible filename.

    – Allen Lavoie
    Feb 9 '17 at 21:05











  • The tensor has been evaluated using eval() . After that when I use decode_raw, I get the error as stated in the question. As to the validity of the data, it is valid since the tf.train.string_input_producer() has been fed using a list of python strings ( which are valid filenames).

    – Ujjwal
    Feb 9 '17 at 21:36






  • 1





    Hi, @Ujjwal, have you ever solved this problem? I'm looking for the solution. Thanks.

    – mining
    Jun 13 '17 at 22:12



















  • If you'd like to work with the string in Python, you need to execute the TensorFlow graph first.

    – Allen Lavoie
    Feb 9 '17 at 20:53






  • 1





    As you can see I have executed the graph inside a session.

    – Ujjwal
    Feb 9 '17 at 20:59











  • Your second approach is fine (decode_raw), you just need to evaluate the Tensor first. Although I have a feeling the reason you're not getting the result you want in the first approach is that this is binary data rather than a sensible filename.

    – Allen Lavoie
    Feb 9 '17 at 21:05











  • The tensor has been evaluated using eval() . After that when I use decode_raw, I get the error as stated in the question. As to the validity of the data, it is valid since the tf.train.string_input_producer() has been fed using a list of python strings ( which are valid filenames).

    – Ujjwal
    Feb 9 '17 at 21:36






  • 1





    Hi, @Ujjwal, have you ever solved this problem? I'm looking for the solution. Thanks.

    – mining
    Jun 13 '17 at 22:12

















If you'd like to work with the string in Python, you need to execute the TensorFlow graph first.

– Allen Lavoie
Feb 9 '17 at 20:53





If you'd like to work with the string in Python, you need to execute the TensorFlow graph first.

– Allen Lavoie
Feb 9 '17 at 20:53




1




1





As you can see I have executed the graph inside a session.

– Ujjwal
Feb 9 '17 at 20:59





As you can see I have executed the graph inside a session.

– Ujjwal
Feb 9 '17 at 20:59













Your second approach is fine (decode_raw), you just need to evaluate the Tensor first. Although I have a feeling the reason you're not getting the result you want in the first approach is that this is binary data rather than a sensible filename.

– Allen Lavoie
Feb 9 '17 at 21:05





Your second approach is fine (decode_raw), you just need to evaluate the Tensor first. Although I have a feeling the reason you're not getting the result you want in the first approach is that this is binary data rather than a sensible filename.

– Allen Lavoie
Feb 9 '17 at 21:05













The tensor has been evaluated using eval() . After that when I use decode_raw, I get the error as stated in the question. As to the validity of the data, it is valid since the tf.train.string_input_producer() has been fed using a list of python strings ( which are valid filenames).

– Ujjwal
Feb 9 '17 at 21:36





The tensor has been evaluated using eval() . After that when I use decode_raw, I get the error as stated in the question. As to the validity of the data, it is valid since the tf.train.string_input_producer() has been fed using a list of python strings ( which are valid filenames).

– Ujjwal
Feb 9 '17 at 21:36




1




1





Hi, @Ujjwal, have you ever solved this problem? I'm looking for the solution. Thanks.

– mining
Jun 13 '17 at 22:12





Hi, @Ujjwal, have you ever solved this problem? I'm looking for the solution. Thanks.

– mining
Jun 13 '17 at 22:12












3 Answers
3






active

oldest

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0














key, value = reader.read(filename_queue)


In this, the Reader just read the file you give, so value is the content of the file, not the filename, but you can output key, then you get filename






share|improve this answer































    0














    If I understand your issue correctly you can try:



    print(filename.decode())





    share|improve this answer































      0














      Use the as_text function in compat (from tensorflow.python.util) to convert the byte string of tensorflow. I.e.



      filename = compat.as_text(filename)






      share|improve this answer
























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        3 Answers
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        3 Answers
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        active

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        active

        oldest

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        0














        key, value = reader.read(filename_queue)


        In this, the Reader just read the file you give, so value is the content of the file, not the filename, but you can output key, then you get filename






        share|improve this answer




























          0














          key, value = reader.read(filename_queue)


          In this, the Reader just read the file you give, so value is the content of the file, not the filename, but you can output key, then you get filename






          share|improve this answer


























            0












            0








            0







            key, value = reader.read(filename_queue)


            In this, the Reader just read the file you give, so value is the content of the file, not the filename, but you can output key, then you get filename






            share|improve this answer













            key, value = reader.read(filename_queue)


            In this, the Reader just read the file you give, so value is the content of the file, not the filename, but you can output key, then you get filename







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Apr 24 '18 at 12:18









            mxlmxl

            366




            366

























                0














                If I understand your issue correctly you can try:



                print(filename.decode())





                share|improve this answer




























                  0














                  If I understand your issue correctly you can try:



                  print(filename.decode())





                  share|improve this answer


























                    0












                    0








                    0







                    If I understand your issue correctly you can try:



                    print(filename.decode())





                    share|improve this answer













                    If I understand your issue correctly you can try:



                    print(filename.decode())






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 21 '18 at 16:37









                    Ohad MeirOhad Meir

                    350213




                    350213























                        0














                        Use the as_text function in compat (from tensorflow.python.util) to convert the byte string of tensorflow. I.e.



                        filename = compat.as_text(filename)






                        share|improve this answer




























                          0














                          Use the as_text function in compat (from tensorflow.python.util) to convert the byte string of tensorflow. I.e.



                          filename = compat.as_text(filename)






                          share|improve this answer


























                            0












                            0








                            0







                            Use the as_text function in compat (from tensorflow.python.util) to convert the byte string of tensorflow. I.e.



                            filename = compat.as_text(filename)






                            share|improve this answer













                            Use the as_text function in compat (from tensorflow.python.util) to convert the byte string of tensorflow. I.e.



                            filename = compat.as_text(filename)







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Mar 5 at 7:58









                            wontleavewontleave

                            536




                            536






























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