Single remove clause in while loop is removing two elements











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I am writing a simple secret santa script that selects a "GiftReceiver" and a "GiftGiver" from a list. Two lists and an empty dataframe to be populated are produced:



import pandas as pd
import random

santaslist_receivers = ['Rudolf',
'Blitzen',
'Prancer',
'Dasher',
'Vixen',
'Comet'
]

santaslist_givers = santaslist_receivers

finalDataFrame = pd.DataFrame(columns = ['GiftGiver','GiftReceiver'])


I then have a while loop that selects random elements from each list to pick a gift giver and receiver, then remove from the respective list:



while len(santaslist_receivers) > 0:

print (len(santaslist_receivers)) #Used for testing.

gift_receiver = random.choice(santaslist_receivers)
santaslist_receivers.remove(gift_receiver)

print (len(santaslist_receivers)) #Used for testing.

gift_giver = random.choice(santaslist_givers)
while gift_giver == gift_receiver: #While loop ensures that gift_giver != gift_receiver
gift_giver = random.choice(santaslist_givers)

santaslist_givers.remove(gift_giver)

dummyDF = pd.DataFrame({'GiftGiver':gift_giver,'GiftReceiver':gift_receiver}, index = [0])

finalDataFrame = finalDataFrame.append(dummyDF)


The final dataframe only contains three elements instead of six:



print(finalDataframe)


returns



    GiftGiver GiftReceiver
0 Dasher Prancer
0 Comet Vixen
0 Rudolf Blitzen


I have inserted two print lines within the while loop to investigate. These print the length of the list santaslist_receivers before and after the removal of an element. The expected return is to see original list length on the first print, then minus 1 on the second print, then the same length again on the first print of the next iteration of the while loop, then so on. Specifically I expect:



6,5,5,4,4,3,3... and so on.


What is returned is



6,5,4,3,2,1


Which is consistent with the DataFrame having only 3 rows, but I do not see the cause of this.



What is the error in my code or my approach?










share|improve this question






















  • Mandatory reading: nedbatchelder.com/text/names.html
    – bruno desthuilliers
    Nov 8 at 12:29















up vote
0
down vote

favorite












I am writing a simple secret santa script that selects a "GiftReceiver" and a "GiftGiver" from a list. Two lists and an empty dataframe to be populated are produced:



import pandas as pd
import random

santaslist_receivers = ['Rudolf',
'Blitzen',
'Prancer',
'Dasher',
'Vixen',
'Comet'
]

santaslist_givers = santaslist_receivers

finalDataFrame = pd.DataFrame(columns = ['GiftGiver','GiftReceiver'])


I then have a while loop that selects random elements from each list to pick a gift giver and receiver, then remove from the respective list:



while len(santaslist_receivers) > 0:

print (len(santaslist_receivers)) #Used for testing.

gift_receiver = random.choice(santaslist_receivers)
santaslist_receivers.remove(gift_receiver)

print (len(santaslist_receivers)) #Used for testing.

gift_giver = random.choice(santaslist_givers)
while gift_giver == gift_receiver: #While loop ensures that gift_giver != gift_receiver
gift_giver = random.choice(santaslist_givers)

santaslist_givers.remove(gift_giver)

dummyDF = pd.DataFrame({'GiftGiver':gift_giver,'GiftReceiver':gift_receiver}, index = [0])

finalDataFrame = finalDataFrame.append(dummyDF)


The final dataframe only contains three elements instead of six:



print(finalDataframe)


returns



    GiftGiver GiftReceiver
0 Dasher Prancer
0 Comet Vixen
0 Rudolf Blitzen


I have inserted two print lines within the while loop to investigate. These print the length of the list santaslist_receivers before and after the removal of an element. The expected return is to see original list length on the first print, then minus 1 on the second print, then the same length again on the first print of the next iteration of the while loop, then so on. Specifically I expect:



6,5,5,4,4,3,3... and so on.


What is returned is



6,5,4,3,2,1


Which is consistent with the DataFrame having only 3 rows, but I do not see the cause of this.



What is the error in my code or my approach?










share|improve this question






















  • Mandatory reading: nedbatchelder.com/text/names.html
    – bruno desthuilliers
    Nov 8 at 12:29













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am writing a simple secret santa script that selects a "GiftReceiver" and a "GiftGiver" from a list. Two lists and an empty dataframe to be populated are produced:



import pandas as pd
import random

santaslist_receivers = ['Rudolf',
'Blitzen',
'Prancer',
'Dasher',
'Vixen',
'Comet'
]

santaslist_givers = santaslist_receivers

finalDataFrame = pd.DataFrame(columns = ['GiftGiver','GiftReceiver'])


I then have a while loop that selects random elements from each list to pick a gift giver and receiver, then remove from the respective list:



while len(santaslist_receivers) > 0:

print (len(santaslist_receivers)) #Used for testing.

gift_receiver = random.choice(santaslist_receivers)
santaslist_receivers.remove(gift_receiver)

print (len(santaslist_receivers)) #Used for testing.

gift_giver = random.choice(santaslist_givers)
while gift_giver == gift_receiver: #While loop ensures that gift_giver != gift_receiver
gift_giver = random.choice(santaslist_givers)

santaslist_givers.remove(gift_giver)

dummyDF = pd.DataFrame({'GiftGiver':gift_giver,'GiftReceiver':gift_receiver}, index = [0])

finalDataFrame = finalDataFrame.append(dummyDF)


The final dataframe only contains three elements instead of six:



print(finalDataframe)


returns



    GiftGiver GiftReceiver
0 Dasher Prancer
0 Comet Vixen
0 Rudolf Blitzen


I have inserted two print lines within the while loop to investigate. These print the length of the list santaslist_receivers before and after the removal of an element. The expected return is to see original list length on the first print, then minus 1 on the second print, then the same length again on the first print of the next iteration of the while loop, then so on. Specifically I expect:



6,5,5,4,4,3,3... and so on.


What is returned is



6,5,4,3,2,1


Which is consistent with the DataFrame having only 3 rows, but I do not see the cause of this.



What is the error in my code or my approach?










share|improve this question













I am writing a simple secret santa script that selects a "GiftReceiver" and a "GiftGiver" from a list. Two lists and an empty dataframe to be populated are produced:



import pandas as pd
import random

santaslist_receivers = ['Rudolf',
'Blitzen',
'Prancer',
'Dasher',
'Vixen',
'Comet'
]

santaslist_givers = santaslist_receivers

finalDataFrame = pd.DataFrame(columns = ['GiftGiver','GiftReceiver'])


I then have a while loop that selects random elements from each list to pick a gift giver and receiver, then remove from the respective list:



while len(santaslist_receivers) > 0:

print (len(santaslist_receivers)) #Used for testing.

gift_receiver = random.choice(santaslist_receivers)
santaslist_receivers.remove(gift_receiver)

print (len(santaslist_receivers)) #Used for testing.

gift_giver = random.choice(santaslist_givers)
while gift_giver == gift_receiver: #While loop ensures that gift_giver != gift_receiver
gift_giver = random.choice(santaslist_givers)

santaslist_givers.remove(gift_giver)

dummyDF = pd.DataFrame({'GiftGiver':gift_giver,'GiftReceiver':gift_receiver}, index = [0])

finalDataFrame = finalDataFrame.append(dummyDF)


The final dataframe only contains three elements instead of six:



print(finalDataframe)


returns



    GiftGiver GiftReceiver
0 Dasher Prancer
0 Comet Vixen
0 Rudolf Blitzen


I have inserted two print lines within the while loop to investigate. These print the length of the list santaslist_receivers before and after the removal of an element. The expected return is to see original list length on the first print, then minus 1 on the second print, then the same length again on the first print of the next iteration of the while loop, then so on. Specifically I expect:



6,5,5,4,4,3,3... and so on.


What is returned is



6,5,4,3,2,1


Which is consistent with the DataFrame having only 3 rows, but I do not see the cause of this.



What is the error in my code or my approach?







python while-loop






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share|improve this question










asked Nov 8 at 11:21









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257420












  • Mandatory reading: nedbatchelder.com/text/names.html
    – bruno desthuilliers
    Nov 8 at 12:29


















  • Mandatory reading: nedbatchelder.com/text/names.html
    – bruno desthuilliers
    Nov 8 at 12:29
















Mandatory reading: nedbatchelder.com/text/names.html
– bruno desthuilliers
Nov 8 at 12:29




Mandatory reading: nedbatchelder.com/text/names.html
– bruno desthuilliers
Nov 8 at 12:29












2 Answers
2






active

oldest

votes

















up vote
2
down vote



accepted










You can solve it by simply changing this line



santaslist_givers = santaslist_receivers


to



 santaslist_givers = list(santaslist_receivers)


Python variables are pointers essentially so they refer to the same list , ie santaslist_givers and santaslist_receivers were accessing the same location in memory in your implementation . To make them different use a list function



And for some extra information , you can refer copy.deepcopy






share|improve this answer






























    up vote
    0
    down vote













    You should make an explicit copy of your list here



    santaslist_givers = santaslist_receivers


    there are multiple options for doing this as explained in this question.



    In this case I would recommend (if you have Python >= 3.3):



    santaslist_givers = santaslist_receivers.copy()


    If you are on an older version of Python, the typical way to do it is:



    santaslist_givers = santaslist_receivers[:]





    share|improve this answer





















      Your Answer






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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      2
      down vote



      accepted










      You can solve it by simply changing this line



      santaslist_givers = santaslist_receivers


      to



       santaslist_givers = list(santaslist_receivers)


      Python variables are pointers essentially so they refer to the same list , ie santaslist_givers and santaslist_receivers were accessing the same location in memory in your implementation . To make them different use a list function



      And for some extra information , you can refer copy.deepcopy






      share|improve this answer



























        up vote
        2
        down vote



        accepted










        You can solve it by simply changing this line



        santaslist_givers = santaslist_receivers


        to



         santaslist_givers = list(santaslist_receivers)


        Python variables are pointers essentially so they refer to the same list , ie santaslist_givers and santaslist_receivers were accessing the same location in memory in your implementation . To make them different use a list function



        And for some extra information , you can refer copy.deepcopy






        share|improve this answer

























          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          You can solve it by simply changing this line



          santaslist_givers = santaslist_receivers


          to



           santaslist_givers = list(santaslist_receivers)


          Python variables are pointers essentially so they refer to the same list , ie santaslist_givers and santaslist_receivers were accessing the same location in memory in your implementation . To make them different use a list function



          And for some extra information , you can refer copy.deepcopy






          share|improve this answer














          You can solve it by simply changing this line



          santaslist_givers = santaslist_receivers


          to



           santaslist_givers = list(santaslist_receivers)


          Python variables are pointers essentially so they refer to the same list , ie santaslist_givers and santaslist_receivers were accessing the same location in memory in your implementation . To make them different use a list function



          And for some extra information , you can refer copy.deepcopy







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 8 at 11:54

























          answered Nov 8 at 11:48









          Albin Paul

          1,220517




          1,220517
























              up vote
              0
              down vote













              You should make an explicit copy of your list here



              santaslist_givers = santaslist_receivers


              there are multiple options for doing this as explained in this question.



              In this case I would recommend (if you have Python >= 3.3):



              santaslist_givers = santaslist_receivers.copy()


              If you are on an older version of Python, the typical way to do it is:



              santaslist_givers = santaslist_receivers[:]





              share|improve this answer

























                up vote
                0
                down vote













                You should make an explicit copy of your list here



                santaslist_givers = santaslist_receivers


                there are multiple options for doing this as explained in this question.



                In this case I would recommend (if you have Python >= 3.3):



                santaslist_givers = santaslist_receivers.copy()


                If you are on an older version of Python, the typical way to do it is:



                santaslist_givers = santaslist_receivers[:]





                share|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  You should make an explicit copy of your list here



                  santaslist_givers = santaslist_receivers


                  there are multiple options for doing this as explained in this question.



                  In this case I would recommend (if you have Python >= 3.3):



                  santaslist_givers = santaslist_receivers.copy()


                  If you are on an older version of Python, the typical way to do it is:



                  santaslist_givers = santaslist_receivers[:]





                  share|improve this answer












                  You should make an explicit copy of your list here



                  santaslist_givers = santaslist_receivers


                  there are multiple options for doing this as explained in this question.



                  In this case I would recommend (if you have Python >= 3.3):



                  santaslist_givers = santaslist_receivers.copy()


                  If you are on an older version of Python, the typical way to do it is:



                  santaslist_givers = santaslist_receivers[:]






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 8 at 11:55









                  Pumpkin

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