How to end program if input == “quit” with many if statements?

I want the user to be able to quit this program at any point by typing in "quit".

Is there a way to do this with one instance of a break statement, or do I need to add a break to every "if y ==" statement in my code?

fruits = 

notfruits = 

print(fruits)

print(notfruits)



while len(fruits) < 3 or len(notfruits) < 3:   # replaced `and` with `or`

    print("Please enter fruits or notfruits:") #

    y = str(input(": "))                       # moved the input here

    if y == "fruits":

        while len(fruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in notfruits:

                print(x + " is not a fruit!")

            elif x in fruits:

                print(x + " is already in the list!")

            else:

                fruits.append(x)

                print(fruits)

    elif y == "notfruits":

         while len(notfruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in fruits:

                print(x + " is a fruit!")

            elif x in notfruits:

                print(x + " is already in the list!")

            else:

                notfruits.append(x)

                print(notfruits)

    elif y == "clearfruits":

        del fruits[:]

    elif y == "clearnotfruits":

        del notfruits[:]

    elif y == "quit":

        break

    else:

        print("Not a valid option!")

asked Nov 12 at 22:34

Bobert

284

3

You can create your own myInput function which calls input and calls sys.exit(0) if it founds "quit" and returns input otherwise. Then you replace all inputs by myInput.
– Michael Butscher
Nov 12 at 22:37

add a comment |

I want the user to be able to quit this program at any point by typing in "quit".

Is there a way to do this with one instance of a break statement, or do I need to add a break to every "if y ==" statement in my code?

fruits = 

notfruits = 

print(fruits)

print(notfruits)



while len(fruits) < 3 or len(notfruits) < 3:   # replaced `and` with `or`

    print("Please enter fruits or notfruits:") #

    y = str(input(": "))                       # moved the input here

    if y == "fruits":

        while len(fruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in notfruits:

                print(x + " is not a fruit!")

            elif x in fruits:

                print(x + " is already in the list!")

            else:

                fruits.append(x)

                print(fruits)

    elif y == "notfruits":

         while len(notfruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in fruits:

                print(x + " is a fruit!")

            elif x in notfruits:

                print(x + " is already in the list!")

            else:

                notfruits.append(x)

                print(notfruits)

    elif y == "clearfruits":

        del fruits[:]

    elif y == "clearnotfruits":

        del notfruits[:]

    elif y == "quit":

        break

    else:

        print("Not a valid option!")

asked Nov 12 at 22:34

Bobert

284

3

You can create your own myInput function which calls input and calls sys.exit(0) if it founds "quit" and returns input otherwise. Then you replace all inputs by myInput.
– Michael Butscher
Nov 12 at 22:37

add a comment |

I want the user to be able to quit this program at any point by typing in "quit".

Is there a way to do this with one instance of a break statement, or do I need to add a break to every "if y ==" statement in my code?

fruits = 

notfruits = 

print(fruits)

print(notfruits)



while len(fruits) < 3 or len(notfruits) < 3:   # replaced `and` with `or`

    print("Please enter fruits or notfruits:") #

    y = str(input(": "))                       # moved the input here

    if y == "fruits":

        while len(fruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in notfruits:

                print(x + " is not a fruit!")

            elif x in fruits:

                print(x + " is already in the list!")

            else:

                fruits.append(x)

                print(fruits)

    elif y == "notfruits":

         while len(notfruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in fruits:

                print(x + " is a fruit!")

            elif x in notfruits:

                print(x + " is already in the list!")

            else:

                notfruits.append(x)

                print(notfruits)

    elif y == "clearfruits":

        del fruits[:]

    elif y == "clearnotfruits":

        del notfruits[:]

    elif y == "quit":

        break

    else:

        print("Not a valid option!")

asked Nov 12 at 22:34

Bobert

284

I want the user to be able to quit this program at any point by typing in "quit".

Is there a way to do this with one instance of a break statement, or do I need to add a break to every "if y ==" statement in my code?

fruits = 

notfruits = 

print(fruits)

print(notfruits)



while len(fruits) < 3 or len(notfruits) < 3:   # replaced `and` with `or`

    print("Please enter fruits or notfruits:") #

    y = str(input(": "))                       # moved the input here

    if y == "fruits":

        while len(fruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in notfruits:

                print(x + " is not a fruit!")

            elif x in fruits:

                print(x + " is already in the list!")

            else:

                fruits.append(x)

                print(fruits)

    elif y == "notfruits":

         while len(notfruits) < 3:

            x = str(input(": "))

            x = x.strip()

            if x in fruits:

                print(x + " is a fruit!")

            elif x in notfruits:

                print(x + " is already in the list!")

            else:

                notfruits.append(x)

                print(notfruits)

    elif y == "clearfruits":

        del fruits[:]

    elif y == "clearnotfruits":

        del notfruits[:]

    elif y == "quit":

        break

    else:

        print("Not a valid option!")

python loops if-statement break

asked Nov 12 at 22:34

Bobert

284

asked Nov 12 at 22:34

Bobert

284

asked Nov 12 at 22:34

Bobert

284

asked Nov 12 at 22:34

Bobert

284

asked Nov 12 at 22:34

Bobert

284

3

You can create your own myInput function which calls input and calls sys.exit(0) if it founds "quit" and returns input otherwise. Then you replace all inputs by myInput.
– Michael Butscher
Nov 12 at 22:37

add a comment |

3

You can create your own myInput function which calls input and calls sys.exit(0) if it founds "quit" and returns input otherwise. Then you replace all inputs by myInput.
– Michael Butscher
Nov 12 at 22:37

You can create your own myInput function which calls input and calls sys.exit(0) if it founds "quit" and returns input otherwise. Then you replace all inputs by myInput.
– Michael Butscher
Nov 12 at 22:37

add a comment |

3 Answers
3

active

oldest

votes

Create a function, use it each time you taker an input, call "exit()" to leave

For example

import sys



def check_quit(inp):

    if inp == 'quit':

        sys.exit(0)

edited Nov 12 at 22:39

Michael Butscher

4,23321321

answered Nov 12 at 22:37

Skapin

665

@michael-butscher has the best answere.
– Skapin
Nov 12 at 22:40

Thanks. Was hoping to only need to call the function once, but I just placed it with each instance of user input.
– Bobert
Nov 12 at 23:04

add a comment |

You can use

import sys

sys.exit(0)

to immediately stop executing further program statements, so something like

elif y == "quit":

    import sys

    sys.exit(0)

should work.

Documentation: https://docs.python.org/3.5/library/sys.html#sys.exit

answered Nov 12 at 22:36

quant

1,59211526

used @michael-butscher solution, but your's is the same idea without the function. Thank you!
– Bobert
Nov 12 at 23:03

add a comment |

I think that both writing a function and using sys.exit are overkill for what OP asked, depending whether you're trying to break out of the loop or exit the program entirely

Specifically regarding your question, you can break right after your input() and it will exit the loop without executing the rest of the run. (BTW, you don't need to cast input to a string, input is a string by default)

y = input(": ")

if y.lower() == "quit":

    break    

if y == "fruits":

answered Nov 12 at 22:41

G. Anderson

1,06929

This breaks the current loop and reverts back to the previous loop. Useful because I wanted to create a "back" step at each loop, but doesn't end the whole program until you get to the first loop and enter "quit". Thank you for answering!
– Bobert
Nov 12 at 23:05

I suppose I misunderstood your question, the solution breaks out of the while loop if put right after the input. Hope it was helpful anyway
– G. Anderson
Nov 12 at 23:16

No problem. It was helpful, as I also wanted a way to break the current loop without exiting the whole program.
– Bobert
Nov 12 at 23:26

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53271077%2fhow-to-end-program-if-input-quit-with-many-if-statements%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

Create a function, use it each time you taker an input, call "exit()" to leave

For example

import sys



def check_quit(inp):

    if inp == 'quit':

        sys.exit(0)

edited Nov 12 at 22:39

Michael Butscher

4,23321321

answered Nov 12 at 22:37

Skapin

665

@michael-butscher has the best answere.
– Skapin
Nov 12 at 22:40

Thanks. Was hoping to only need to call the function once, but I just placed it with each instance of user input.
– Bobert
Nov 12 at 23:04

add a comment |

Create a function, use it each time you taker an input, call "exit()" to leave

For example

import sys



def check_quit(inp):

    if inp == 'quit':

        sys.exit(0)

edited Nov 12 at 22:39

Michael Butscher

4,23321321

answered Nov 12 at 22:37

Skapin

665

@michael-butscher has the best answere.
– Skapin
Nov 12 at 22:40

Thanks. Was hoping to only need to call the function once, but I just placed it with each instance of user input.
– Bobert
Nov 12 at 23:04

add a comment |

Create a function, use it each time you taker an input, call "exit()" to leave

For example

import sys



def check_quit(inp):

    if inp == 'quit':

        sys.exit(0)

edited Nov 12 at 22:39

Michael Butscher

4,23321321

answered Nov 12 at 22:37

Skapin

665

Create a function, use it each time you taker an input, call "exit()" to leave

For example

import sys



def check_quit(inp):

    if inp == 'quit':

        sys.exit(0)

edited Nov 12 at 22:39

Michael Butscher

4,23321321

answered Nov 12 at 22:37

Skapin

665

edited Nov 12 at 22:39

Michael Butscher

4,23321321

edited Nov 12 at 22:39

Michael Butscher

4,23321321

edited Nov 12 at 22:39

Michael Butscher

4,23321321

answered Nov 12 at 22:37

Skapin

665

answered Nov 12 at 22:37

Skapin

665

answered Nov 12 at 22:37

Skapin

665

@michael-butscher has the best answere.
– Skapin
Nov 12 at 22:40

Thanks. Was hoping to only need to call the function once, but I just placed it with each instance of user input.
– Bobert
Nov 12 at 23:04

add a comment |

@michael-butscher has the best answere.
– Skapin
Nov 12 at 22:40

Thanks. Was hoping to only need to call the function once, but I just placed it with each instance of user input.
– Bobert
Nov 12 at 23:04

@michael-butscher has the best answere.
– Skapin
Nov 12 at 22:40

Thanks. Was hoping to only need to call the function once, but I just placed it with each instance of user input.
– Bobert
Nov 12 at 23:04

add a comment |

You can use

import sys

sys.exit(0)

to immediately stop executing further program statements, so something like

elif y == "quit":

    import sys

    sys.exit(0)

should work.

Documentation: https://docs.python.org/3.5/library/sys.html#sys.exit

answered Nov 12 at 22:36

quant

1,59211526

used @michael-butscher solution, but your's is the same idea without the function. Thank you!
– Bobert
Nov 12 at 23:03

add a comment |

You can use

import sys

sys.exit(0)

to immediately stop executing further program statements, so something like

elif y == "quit":

    import sys

    sys.exit(0)

should work.

Documentation: https://docs.python.org/3.5/library/sys.html#sys.exit

answered Nov 12 at 22:36

quant

1,59211526

used @michael-butscher solution, but your's is the same idea without the function. Thank you!
– Bobert
Nov 12 at 23:03

add a comment |

You can use

import sys

sys.exit(0)

to immediately stop executing further program statements, so something like

elif y == "quit":

    import sys

    sys.exit(0)

should work.

Documentation: https://docs.python.org/3.5/library/sys.html#sys.exit

answered Nov 12 at 22:36

quant

1,59211526

You can use

import sys

sys.exit(0)

to immediately stop executing further program statements, so something like

elif y == "quit":

    import sys

    sys.exit(0)

should work.

Documentation: https://docs.python.org/3.5/library/sys.html#sys.exit

answered Nov 12 at 22:36

quant

1,59211526

answered Nov 12 at 22:36

quant

1,59211526

answered Nov 12 at 22:36

quant

1,59211526

answered Nov 12 at 22:36

quant

1,59211526

used @michael-butscher solution, but your's is the same idea without the function. Thank you!
– Bobert
Nov 12 at 23:03

add a comment |

used @michael-butscher solution, but your's is the same idea without the function. Thank you!
– Bobert
Nov 12 at 23:03

used @michael-butscher solution, but your's is the same idea without the function. Thank you!
– Bobert
Nov 12 at 23:03

add a comment |

I think that both writing a function and using sys.exit are overkill for what OP asked, depending whether you're trying to break out of the loop or exit the program entirely

y = input(": ")

if y.lower() == "quit":

    break    

if y == "fruits":

answered Nov 12 at 22:41

G. Anderson

1,06929

This breaks the current loop and reverts back to the previous loop. Useful because I wanted to create a "back" step at each loop, but doesn't end the whole program until you get to the first loop and enter "quit". Thank you for answering!
– Bobert
Nov 12 at 23:05

I suppose I misunderstood your question, the solution breaks out of the while loop if put right after the input. Hope it was helpful anyway
– G. Anderson
Nov 12 at 23:16

No problem. It was helpful, as I also wanted a way to break the current loop without exiting the whole program.
– Bobert
Nov 12 at 23:26

add a comment |

I think that both writing a function and using sys.exit are overkill for what OP asked, depending whether you're trying to break out of the loop or exit the program entirely

y = input(": ")

if y.lower() == "quit":

    break    

if y == "fruits":

answered Nov 12 at 22:41

G. Anderson

1,06929

This breaks the current loop and reverts back to the previous loop. Useful because I wanted to create a "back" step at each loop, but doesn't end the whole program until you get to the first loop and enter "quit". Thank you for answering!
– Bobert
Nov 12 at 23:05

I suppose I misunderstood your question, the solution breaks out of the while loop if put right after the input. Hope it was helpful anyway
– G. Anderson
Nov 12 at 23:16

No problem. It was helpful, as I also wanted a way to break the current loop without exiting the whole program.
– Bobert
Nov 12 at 23:26

add a comment |

I think that both writing a function and using sys.exit are overkill for what OP asked, depending whether you're trying to break out of the loop or exit the program entirely

y = input(": ")

if y.lower() == "quit":

    break    

if y == "fruits":

answered Nov 12 at 22:41

G. Anderson

1,06929

I think that both writing a function and using sys.exit are overkill for what OP asked, depending whether you're trying to break out of the loop or exit the program entirely

y = input(": ")

if y.lower() == "quit":

    break    

if y == "fruits":

answered Nov 12 at 22:41

G. Anderson

1,06929

answered Nov 12 at 22:41

G. Anderson

1,06929

answered Nov 12 at 22:41

G. Anderson

1,06929

answered Nov 12 at 22:41

G. Anderson

1,06929

This breaks the current loop and reverts back to the previous loop. Useful because I wanted to create a "back" step at each loop, but doesn't end the whole program until you get to the first loop and enter "quit". Thank you for answering!
– Bobert
Nov 12 at 23:05

I suppose I misunderstood your question, the solution breaks out of the while loop if put right after the input. Hope it was helpful anyway
– G. Anderson
Nov 12 at 23:16

No problem. It was helpful, as I also wanted a way to break the current loop without exiting the whole program.
– Bobert
Nov 12 at 23:26

add a comment |

This breaks the current loop and reverts back to the previous loop. Useful because I wanted to create a "back" step at each loop, but doesn't end the whole program until you get to the first loop and enter "quit". Thank you for answering!
– Bobert
Nov 12 at 23:05

I suppose I misunderstood your question, the solution breaks out of the while loop if put right after the input. Hope it was helpful anyway
– G. Anderson
Nov 12 at 23:16

No problem. It was helpful, as I also wanted a way to break the current loop without exiting the whole program.
– Bobert
Nov 12 at 23:26

This breaks the current loop and reverts back to the previous loop. Useful because I wanted to create a "back" step at each loop, but doesn't end the whole program until you get to the first loop and enter "quit". Thank you for answering!
– Bobert
Nov 12 at 23:05

I suppose I misunderstood your question, the solution breaks out of the while loop if put right after the input. Hope it was helpful anyway
– G. Anderson
Nov 12 at 23:16

No problem. It was helpful, as I also wanted a way to break the current loop without exiting the whole program.
– Bobert
Nov 12 at 23:26

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

Some of your past answers have not been well-received, and you're in danger of being blocked from answering.

Please pay close attention to the following guidance:

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Agfdhyk