Interpolate variable in command substitution in Makefile












0














I am trying to do variable interpolation inside a command substitution in a Makefile.



I have this code:



setup:
mkdir -p data_all ;
for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
git_url=$(shell jq -r ".$$i" assets.json) ;
git clone $$git_url data_all/$$i ;
done


The code is failing, however, because $$i does not expand in the "shell" line that sets git_url.



How do I interpolate the variable $i in the "shell" line that sets git_url?










share|improve this question



























    0














    I am trying to do variable interpolation inside a command substitution in a Makefile.



    I have this code:



    setup:
    mkdir -p data_all ;
    for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
    git_url=$(shell jq -r ".$$i" assets.json) ;
    git clone $$git_url data_all/$$i ;
    done


    The code is failing, however, because $$i does not expand in the "shell" line that sets git_url.



    How do I interpolate the variable $i in the "shell" line that sets git_url?










    share|improve this question

























      0












      0








      0







      I am trying to do variable interpolation inside a command substitution in a Makefile.



      I have this code:



      setup:
      mkdir -p data_all ;
      for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
      git_url=$(shell jq -r ".$$i" assets.json) ;
      git clone $$git_url data_all/$$i ;
      done


      The code is failing, however, because $$i does not expand in the "shell" line that sets git_url.



      How do I interpolate the variable $i in the "shell" line that sets git_url?










      share|improve this question













      I am trying to do variable interpolation inside a command substitution in a Makefile.



      I have this code:



      setup:
      mkdir -p data_all ;
      for i in $(shell jq -r 'keys | @tsv' assets.json) ; do
      git_url=$(shell jq -r ".$$i" assets.json) ;
      git clone $$git_url data_all/$$i ;
      done


      The code is failing, however, because $$i does not expand in the "shell" line that sets git_url.



      How do I interpolate the variable $i in the "shell" line that sets git_url?







      makefile






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 at 0:26









      Alex Harvey

      3,6901823




      3,6901823
























          1 Answer
          1






          active

          oldest

          votes


















          1














          You mixed up make functions ($(shell ...)) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:



          mkdir -p data_all ; 
          for i in $( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$( jq -r ".$i" assets.json ) ;
          git clone $git_url data_all/$i ;
          done


          And then escaping the unwanted $ expansion by make:



          mkdir -p data_all ; 
          for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$$( jq -r ".$$i" assets.json ) ;
          git clone $$git_url data_all/$$i ;
          done





          share|improve this answer





















          • Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
            – Alex Harvey
            Nov 13 at 6:42











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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

          votes









          1














          You mixed up make functions ($(shell ...)) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:



          mkdir -p data_all ; 
          for i in $( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$( jq -r ".$i" assets.json ) ;
          git clone $git_url data_all/$i ;
          done


          And then escaping the unwanted $ expansion by make:



          mkdir -p data_all ; 
          for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$$( jq -r ".$$i" assets.json ) ;
          git clone $$git_url data_all/$$i ;
          done





          share|improve this answer





















          • Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
            – Alex Harvey
            Nov 13 at 6:42
















          1














          You mixed up make functions ($(shell ...)) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:



          mkdir -p data_all ; 
          for i in $( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$( jq -r ".$i" assets.json ) ;
          git clone $git_url data_all/$i ;
          done


          And then escaping the unwanted $ expansion by make:



          mkdir -p data_all ; 
          for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$$( jq -r ".$$i" assets.json ) ;
          git clone $$git_url data_all/$$i ;
          done





          share|improve this answer





















          • Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
            – Alex Harvey
            Nov 13 at 6:42














          1












          1








          1






          You mixed up make functions ($(shell ...)) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:



          mkdir -p data_all ; 
          for i in $( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$( jq -r ".$i" assets.json ) ;
          git clone $git_url data_all/$i ;
          done


          And then escaping the unwanted $ expansion by make:



          mkdir -p data_all ; 
          for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$$( jq -r ".$$i" assets.json ) ;
          git clone $$git_url data_all/$$i ;
          done





          share|improve this answer












          You mixed up make functions ($(shell ...)) and true shell constructs. When writing a recipe the simplest is to write it first in plain shell:



          mkdir -p data_all ; 
          for i in $( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$( jq -r ".$i" assets.json ) ;
          git clone $git_url data_all/$i ;
          done


          And then escaping the unwanted $ expansion by make:



          mkdir -p data_all ; 
          for i in $$( jq -r 'keys | @tsv' assets.json ) ; do
          git_url=$$( jq -r ".$$i" assets.json ) ;
          git clone $$git_url data_all/$$i ;
          done






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 at 6:32









          Renaud Pacalet

          8,80921729




          8,80921729












          • Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
            – Alex Harvey
            Nov 13 at 6:42


















          • Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
            – Alex Harvey
            Nov 13 at 6:42
















          Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
          – Alex Harvey
          Nov 13 at 6:42




          Oh great, I can don't need those "shell" calls either. That's much nicer. Thanks!
          – Alex Harvey
          Nov 13 at 6:42


















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