Overflow/carry flag in MIPS











up vote
0
down vote

favorite












I have searched a bit and didn't find anything that properly explained this.



In MIPS you have add and addu to do additions. The main difference is that addu doesn't generate an overflow exceptions.



Let's say we have this binary (I'm using four bits although MIPS is 32 for simplification):



0111


If we add 1 it becomes 1000.



With the add instruction there is an overflow and no carry, since a positive 7 became a negative 1 (assuming two's complement in MIPS). This generates an overflow exception too.



With the addu there is no overflow and no carry, since everything went as expected.



Now let's say you have this binary:



1111


If we add 1 it becomes 0000.



With the add instruction there should be no overflow since a negative 1 became a 0. What about the carry out flag, does it change to 1?



And what happens with the addu instruction? Is it considered overflow, since 15 became 0? I know that there is no overflow exception, but what happens to the overflow flag? Does it get set to 1? What about the carry flag?










share|improve this question


















  • 1




    Which carry flag are you referring to? There's no status register in the MIPS architecture.
    – Michael
    Nov 12 at 11:18










  • @Michael oh I thought there was. My bad.
    – Myntekt
    Nov 13 at 12:18















up vote
0
down vote

favorite












I have searched a bit and didn't find anything that properly explained this.



In MIPS you have add and addu to do additions. The main difference is that addu doesn't generate an overflow exceptions.



Let's say we have this binary (I'm using four bits although MIPS is 32 for simplification):



0111


If we add 1 it becomes 1000.



With the add instruction there is an overflow and no carry, since a positive 7 became a negative 1 (assuming two's complement in MIPS). This generates an overflow exception too.



With the addu there is no overflow and no carry, since everything went as expected.



Now let's say you have this binary:



1111


If we add 1 it becomes 0000.



With the add instruction there should be no overflow since a negative 1 became a 0. What about the carry out flag, does it change to 1?



And what happens with the addu instruction? Is it considered overflow, since 15 became 0? I know that there is no overflow exception, but what happens to the overflow flag? Does it get set to 1? What about the carry flag?










share|improve this question


















  • 1




    Which carry flag are you referring to? There's no status register in the MIPS architecture.
    – Michael
    Nov 12 at 11:18










  • @Michael oh I thought there was. My bad.
    – Myntekt
    Nov 13 at 12:18













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have searched a bit and didn't find anything that properly explained this.



In MIPS you have add and addu to do additions. The main difference is that addu doesn't generate an overflow exceptions.



Let's say we have this binary (I'm using four bits although MIPS is 32 for simplification):



0111


If we add 1 it becomes 1000.



With the add instruction there is an overflow and no carry, since a positive 7 became a negative 1 (assuming two's complement in MIPS). This generates an overflow exception too.



With the addu there is no overflow and no carry, since everything went as expected.



Now let's say you have this binary:



1111


If we add 1 it becomes 0000.



With the add instruction there should be no overflow since a negative 1 became a 0. What about the carry out flag, does it change to 1?



And what happens with the addu instruction? Is it considered overflow, since 15 became 0? I know that there is no overflow exception, but what happens to the overflow flag? Does it get set to 1? What about the carry flag?










share|improve this question













I have searched a bit and didn't find anything that properly explained this.



In MIPS you have add and addu to do additions. The main difference is that addu doesn't generate an overflow exceptions.



Let's say we have this binary (I'm using four bits although MIPS is 32 for simplification):



0111


If we add 1 it becomes 1000.



With the add instruction there is an overflow and no carry, since a positive 7 became a negative 1 (assuming two's complement in MIPS). This generates an overflow exception too.



With the addu there is no overflow and no carry, since everything went as expected.



Now let's say you have this binary:



1111


If we add 1 it becomes 0000.



With the add instruction there should be no overflow since a negative 1 became a 0. What about the carry out flag, does it change to 1?



And what happens with the addu instruction? Is it considered overflow, since 15 became 0? I know that there is no overflow exception, but what happens to the overflow flag? Does it get set to 1? What about the carry flag?







overflow mips carryflag






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 11 at 19:12









Myntekt

1161111




1161111








  • 1




    Which carry flag are you referring to? There's no status register in the MIPS architecture.
    – Michael
    Nov 12 at 11:18










  • @Michael oh I thought there was. My bad.
    – Myntekt
    Nov 13 at 12:18














  • 1




    Which carry flag are you referring to? There's no status register in the MIPS architecture.
    – Michael
    Nov 12 at 11:18










  • @Michael oh I thought there was. My bad.
    – Myntekt
    Nov 13 at 12:18








1




1




Which carry flag are you referring to? There's no status register in the MIPS architecture.
– Michael
Nov 12 at 11:18




Which carry flag are you referring to? There's no status register in the MIPS architecture.
– Michael
Nov 12 at 11:18












@Michael oh I thought there was. My bad.
– Myntekt
Nov 13 at 12:18




@Michael oh I thought there was. My bad.
– Myntekt
Nov 13 at 12:18












1 Answer
1






active

oldest

votes

















up vote
0
down vote













There is no carryout flag in MIPS architecture.



Overflow exception in the case of addition happens when the sign of the result is different form the expected sign which can happen:




  • When you add two positive numbers and you get a negative number as a result

  • When you add two negative numbers and you get a positive number as a result


So yes, in you hypothetical 4 bit MIPS 0111+1 results in an overflow, with the corresponding flag being activated.






share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53252235%2foverflow-carry-flag-in-mips%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    There is no carryout flag in MIPS architecture.



    Overflow exception in the case of addition happens when the sign of the result is different form the expected sign which can happen:




    • When you add two positive numbers and you get a negative number as a result

    • When you add two negative numbers and you get a positive number as a result


    So yes, in you hypothetical 4 bit MIPS 0111+1 results in an overflow, with the corresponding flag being activated.






    share|improve this answer



























      up vote
      0
      down vote













      There is no carryout flag in MIPS architecture.



      Overflow exception in the case of addition happens when the sign of the result is different form the expected sign which can happen:




      • When you add two positive numbers and you get a negative number as a result

      • When you add two negative numbers and you get a positive number as a result


      So yes, in you hypothetical 4 bit MIPS 0111+1 results in an overflow, with the corresponding flag being activated.






      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        There is no carryout flag in MIPS architecture.



        Overflow exception in the case of addition happens when the sign of the result is different form the expected sign which can happen:




        • When you add two positive numbers and you get a negative number as a result

        • When you add two negative numbers and you get a positive number as a result


        So yes, in you hypothetical 4 bit MIPS 0111+1 results in an overflow, with the corresponding flag being activated.






        share|improve this answer














        There is no carryout flag in MIPS architecture.



        Overflow exception in the case of addition happens when the sign of the result is different form the expected sign which can happen:




        • When you add two positive numbers and you get a negative number as a result

        • When you add two negative numbers and you get a positive number as a result


        So yes, in you hypothetical 4 bit MIPS 0111+1 results in an overflow, with the corresponding flag being activated.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 19 at 0:37

























        answered Nov 18 at 17:06









        fasiume

        236




        236






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53252235%2foverflow-carry-flag-in-mips%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            鏡平學校

            ꓛꓣだゔៀៅຸ໢ທຮ໕໒ ,ໂ'໥໓າ໼ឨឲ៵៭ៈゎゔit''䖳𥁄卿' ☨₤₨こゎもょの;ꜹꟚꞖꞵꟅꞛေၦေɯ,ɨɡ𛃵𛁹ޝ޳ޠ޾,ޤޒޯ޾𫝒𫠁သ𛅤チョ'サノބޘދ𛁐ᶿᶇᶀᶋᶠ㨑㽹⻮ꧬ꧹؍۩وَؠ㇕㇃㇪ ㇦㇋㇋ṜẰᵡᴠ 軌ᵕ搜۳ٰޗޮ޷ސޯ𫖾𫅀ल, ꙭ꙰ꚅꙁꚊꞻꝔ꟠Ꝭㄤﺟޱސꧨꧼ꧴ꧯꧽ꧲ꧯ'⽹⽭⾁⿞⼳⽋២៩ញណើꩯꩤ꩸ꩮᶻᶺᶧᶂ𫳲𫪭𬸄𫵰𬖩𬫣𬊉ၲ𛅬㕦䬺𫝌𫝼,,𫟖𫞽ហៅ஫㆔ాఆఅꙒꚞꙍ,Ꙟ꙱エ ,ポテ,フࢰࢯ𫟠𫞶 𫝤𫟠ﺕﹱﻜﻣ𪵕𪭸𪻆𪾩𫔷ġ,ŧآꞪ꟥,ꞔꝻ♚☹⛵𛀌ꬷꭞȄƁƪƬșƦǙǗdžƝǯǧⱦⱰꓕꓢႋ神 ဴ၀க௭எ௫ឫោ ' េㇷㇴㇼ神ㇸㇲㇽㇴㇼㇻㇸ'ㇸㇿㇸㇹㇰㆣꓚꓤ₡₧ ㄨㄟ㄂ㄖㄎ໗ツڒذ₶।ऩछएोञयूटक़कयँृी,冬'𛅢𛅥ㇱㇵㇶ𥄥𦒽𠣧𠊓𧢖𥞘𩔋цѰㄠſtʯʭɿʆʗʍʩɷɛ,əʏダヵㄐㄘR{gỚṖḺờṠṫảḙḭᴮᵏᴘᵀᵷᵕᴜᴏᵾq﮲ﲿﴽﭙ軌ﰬﶚﶧ﫲Ҝжюїкӈㇴffצּ﬘﭅﬈軌'ffistfflſtffतभफɳɰʊɲʎ𛁱𛁖𛁮𛀉 𛂯𛀞నఋŀŲ 𫟲𫠖𫞺ຆຆ ໹້໕໗ๆทԊꧢꧠ꧰ꓱ⿝⼑ŎḬẃẖỐẅ ,ờỰỈỗﮊDžȩꭏꭎꬻ꭮ꬿꭖꭥꭅ㇭神 ⾈ꓵꓑ⺄㄄ㄪㄙㄅㄇstA۵䞽ॶ𫞑𫝄㇉㇇゜軌𩜛𩳠Jﻺ‚Üမ႕ႌႊၐၸဓၞၞၡ៸wyvtᶎᶪᶹစဎ꣡꣰꣢꣤ٗ؋لㇳㇾㇻㇱ㆐㆔,,㆟Ⱶヤマފ޼ޝަݿݞݠݷݐ',ݘ,ݪݙݵ𬝉𬜁𫝨𫞘くせぉて¼óû×ó£…𛅑הㄙくԗԀ5606神45,神796'𪤻𫞧ꓐ㄁ㄘɥɺꓵꓲ3''7034׉ⱦⱠˆ“𫝋ȍ,ꩲ軌꩷ꩶꩧꩫఞ۔فڱێظペサ神ナᴦᵑ47 9238їﻂ䐊䔉㠸﬎ffiﬣ,לּᴷᴦᵛᵽ,ᴨᵤ ᵸᵥᴗᵈꚏꚉꚟ⻆rtǟƴ𬎎

            Why https connections are so slow when debugging (stepping over) in Java?