Using PHP preg_replace to append text to pattern found with regex
0
I want to append a tag div before and after all tags img.
So I have
<img src=%random url image% />
And it should be replaced with
<div class="demo"><img src=%random url image% /></div>
Can I do it with preg_replace?
$string = %page source code%;
$find = array("/<img(.*?)/>/");
$replace = array('<div class="demo">'.$find[0].'</div>');
$result = preg_replace($find, $replace, $string);
But it not work :/
php regex
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
add a comment |
0
I want to append a tag div before and after all tags img.
So I have
<img src=%random url image% />
And it should be replaced with
<div class="demo"><img src=%random url image% /></div>
Can I do it with preg_replace?
$string = %page source code%;
$find = array("/<img(.*?)/>/");
$replace = array('<div class="demo">'.$find[0].'</div>');
$result = preg_replace($find, $replace, $string);
But it not work :/
php regex
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
3
You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.
– Tim Biegeleisen
Nov 18 '18 at 2:30
1
Please don't try to parse [X]HTML using regex. You may want to take a look at this.
– K.Dᴀᴠɪs
Nov 18 '18 at 3:05
add a comment |
0
0
0
I want to append a tag div before and after all tags img.
So I have
<img src=%random url image% />
And it should be replaced with
<div class="demo"><img src=%random url image% /></div>
Can I do it with preg_replace?
$string = %page source code%;
$find = array("/<img(.*?)/>/");
$replace = array('<div class="demo">'.$find[0].'</div>');
$result = preg_replace($find, $replace, $string);
But it not work :/
php regex
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
I want to append a tag div before and after all tags img.
So I have
<img src=%random url image% />
And it should be replaced with
<div class="demo"><img src=%random url image% /></div>
Can I do it with preg_replace?
$string = %page source code%;
$find = array("/<img(.*?)/>/");
$replace = array('<div class="demo">'.$find[0].'</div>');
$result = preg_replace($find, $replace, $string);
But it not work :/
php regex
php regex
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
edited Nov 18 '18 at 2:29
Migu3litto
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
asked Nov 18 '18 at 2:24
Migu3littoMigu3litto
315
315
3
You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.
– Tim Biegeleisen
Nov 18 '18 at 2:30
1
Please don't try to parse [X]HTML using regex. You may want to take a look at this.
– K.Dᴀᴠɪs
Nov 18 '18 at 3:05
add a comment |
3
You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.
– Tim Biegeleisen
Nov 18 '18 at 2:30
1
Please don't try to parse [X]HTML using regex. You may want to take a look at this.
– K.Dᴀᴠɪs
Nov 18 '18 at 3:05
3
3
You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.
– Tim Biegeleisen
Nov 18 '18 at 2:30
You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.
– Tim Biegeleisen
Nov 18 '18 at 2:30
1
1
Please don't try to parse [X]HTML using regex. You may want to take a look at this.
– K.Dᴀᴠɪs
Nov 18 '18 at 3:05
Please don't try to parse [X]HTML using regex. You may want to take a look at this.
– K.Dᴀᴠɪs
Nov 18 '18 at 3:05
add a comment |
1 Answer
1
active
oldest
votes
2
A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:
$html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
$doc = new DOMDocument();
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$images = $xpath->query('//img');
foreach ($images as $image) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'demo');
$image->parentNode->replaceChild($div, $image);
$div->appendChild($image);
}
echo $doc->saveHTML();
Output:
<div>
<div class="demo"><img src="http://x.com"></div>
<span>xyz</span>
<a href="http://example.com">
<div class="demo"><img src="http://example.com"></div>
</a>
</div>
Demo on 3v4l.org
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:
$html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
$doc = new DOMDocument();
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$images = $xpath->query('//img');
foreach ($images as $image) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'demo');
$image->parentNode->replaceChild($div, $image);
$div->appendChild($image);
}
echo $doc->saveHTML();
Output:
<div>
<div class="demo"><img src="http://x.com"></div>
<span>xyz</span>
<a href="http://example.com">
<div class="demo"><img src="http://example.com"></div>
</a>
</div>
Demo on 3v4l.org
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
add a comment |
2
A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:
$html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
$doc = new DOMDocument();
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$images = $xpath->query('//img');
foreach ($images as $image) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'demo');
$image->parentNode->replaceChild($div, $image);
$div->appendChild($image);
}
echo $doc->saveHTML();
Output:
<div>
<div class="demo"><img src="http://x.com"></div>
<span>xyz</span>
<a href="http://example.com">
<div class="demo"><img src="http://example.com"></div>
</a>
</div>
Demo on 3v4l.org
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
add a comment |
2
2
2
A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:
$html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
$doc = new DOMDocument();
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$images = $xpath->query('//img');
foreach ($images as $image) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'demo');
$image->parentNode->replaceChild($div, $image);
$div->appendChild($image);
}
echo $doc->saveHTML();
Output:
<div>
<div class="demo"><img src="http://x.com"></div>
<span>xyz</span>
<a href="http://example.com">
<div class="demo"><img src="http://example.com"></div>
</a>
</div>
Demo on 3v4l.org
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:
$html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
$doc = new DOMDocument();
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DOMXpath($doc);
$images = $xpath->query('//img');
foreach ($images as $image) {
$div = $doc->createElement('div');
$div->setAttribute('class', 'demo');
$image->parentNode->replaceChild($div, $image);
$div->appendChild($image);
}
echo $doc->saveHTML();
Output:
<div>
<div class="demo"><img src="http://x.com"></div>
<span>xyz</span>
<a href="http://example.com">
<div class="demo"><img src="http://example.com"></div>
</a>
</div>
Demo on 3v4l.org
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
answered Nov 18 '18 at 3:20
NickNick
26.4k111839
26.4k111839
add a comment |
add a comment |
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3
You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.
– Tim Biegeleisen
Nov 18 '18 at 2:30
1
Please don't try to parse [X]HTML using regex. You may want to take a look at this.
– K.Dᴀᴠɪs
Nov 18 '18 at 3:05