finding email addresses in python with regex [duplicate]












0
















This question already has an answer here:




  • Extract email sub-strings from large document

    6 answers




Hi I'm trying to find a list of e-mails from a website. there is 4 e-mail addresses on the website but only returns 2 emails.



I'm using this to help search for the emails.



emails = re.findall(r'[^s@<>]+@[^s@<>]+.[^s@<>]+',s)
print(count, ' email address found : ',item)
count += 1









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marked as duplicate by Wiktor Stribiżew python
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Nov 19 '18 at 16:57


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.



















  • Can you add the emails this does not capture to your question so we can help you modify the expression?

    – chris
    Nov 19 '18 at 15:38











  • Hard to tell when we don't know how the found and not found email adresses look like.

    – Tobias Brösamle
    Nov 19 '18 at 15:39
















0
















This question already has an answer here:




  • Extract email sub-strings from large document

    6 answers




Hi I'm trying to find a list of e-mails from a website. there is 4 e-mail addresses on the website but only returns 2 emails.



I'm using this to help search for the emails.



emails = re.findall(r'[^s@<>]+@[^s@<>]+.[^s@<>]+',s)
print(count, ' email address found : ',item)
count += 1









share|improve this question













marked as duplicate by Wiktor Stribiżew python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

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var $hover = $(this).addClass('hover-bound'),
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$hover.hover(
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$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
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Nov 19 '18 at 16:57


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.



















  • Can you add the emails this does not capture to your question so we can help you modify the expression?

    – chris
    Nov 19 '18 at 15:38











  • Hard to tell when we don't know how the found and not found email adresses look like.

    – Tobias Brösamle
    Nov 19 '18 at 15:39














0












0








0









This question already has an answer here:




  • Extract email sub-strings from large document

    6 answers




Hi I'm trying to find a list of e-mails from a website. there is 4 e-mail addresses on the website but only returns 2 emails.



I'm using this to help search for the emails.



emails = re.findall(r'[^s@<>]+@[^s@<>]+.[^s@<>]+',s)
print(count, ' email address found : ',item)
count += 1









share|improve this question















This question already has an answer here:




  • Extract email sub-strings from large document

    6 answers




Hi I'm trying to find a list of e-mails from a website. there is 4 e-mail addresses on the website but only returns 2 emails.



I'm using this to help search for the emails.



emails = re.findall(r'[^s@<>]+@[^s@<>]+.[^s@<>]+',s)
print(count, ' email address found : ',item)
count += 1




This question already has an answer here:




  • Extract email sub-strings from large document

    6 answers








python regex






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asked Nov 19 '18 at 15:35









First LastFirst Last

143




143




marked as duplicate by Wiktor Stribiżew python
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Nov 19 '18 at 16:57


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.









marked as duplicate by Wiktor Stribiżew python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

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function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
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Nov 19 '18 at 16:57


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • Can you add the emails this does not capture to your question so we can help you modify the expression?

    – chris
    Nov 19 '18 at 15:38











  • Hard to tell when we don't know how the found and not found email adresses look like.

    – Tobias Brösamle
    Nov 19 '18 at 15:39



















  • Can you add the emails this does not capture to your question so we can help you modify the expression?

    – chris
    Nov 19 '18 at 15:38











  • Hard to tell when we don't know how the found and not found email adresses look like.

    – Tobias Brösamle
    Nov 19 '18 at 15:39

















Can you add the emails this does not capture to your question so we can help you modify the expression?

– chris
Nov 19 '18 at 15:38





Can you add the emails this does not capture to your question so we can help you modify the expression?

– chris
Nov 19 '18 at 15:38













Hard to tell when we don't know how the found and not found email adresses look like.

– Tobias Brösamle
Nov 19 '18 at 15:39





Hard to tell when we don't know how the found and not found email adresses look like.

– Tobias Brösamle
Nov 19 '18 at 15:39












2 Answers
2






active

oldest

votes


















0














You can try out this regex :



regex = r"([w.-]+)@([w.-]+)(.[w.]+)"





share|improve this answer































    0














    The following pattern should match most forms of email addresses:



    emails = re.findall(r'^([0-9a-zA-Z]([-.w]*[0-9a-zA-Z])*@(([0-9a-zA-Z])+([-w]*[0-9a-zA-Z])*.)+[a-zA-Z]{2,9})$',s)





    share|improve this answer






























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      You can try out this regex :



      regex = r"([w.-]+)@([w.-]+)(.[w.]+)"





      share|improve this answer




























        0














        You can try out this regex :



        regex = r"([w.-]+)@([w.-]+)(.[w.]+)"





        share|improve this answer


























          0












          0








          0







          You can try out this regex :



          regex = r"([w.-]+)@([w.-]+)(.[w.]+)"





          share|improve this answer













          You can try out this regex :



          regex = r"([w.-]+)@([w.-]+)(.[w.]+)"






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 19 '18 at 15:39









          Shubham PanchalShubham Panchal

          479210




          479210

























              0














              The following pattern should match most forms of email addresses:



              emails = re.findall(r'^([0-9a-zA-Z]([-.w]*[0-9a-zA-Z])*@(([0-9a-zA-Z])+([-w]*[0-9a-zA-Z])*.)+[a-zA-Z]{2,9})$',s)





              share|improve this answer




























                0














                The following pattern should match most forms of email addresses:



                emails = re.findall(r'^([0-9a-zA-Z]([-.w]*[0-9a-zA-Z])*@(([0-9a-zA-Z])+([-w]*[0-9a-zA-Z])*.)+[a-zA-Z]{2,9})$',s)





                share|improve this answer


























                  0












                  0








                  0







                  The following pattern should match most forms of email addresses:



                  emails = re.findall(r'^([0-9a-zA-Z]([-.w]*[0-9a-zA-Z])*@(([0-9a-zA-Z])+([-w]*[0-9a-zA-Z])*.)+[a-zA-Z]{2,9})$',s)





                  share|improve this answer













                  The following pattern should match most forms of email addresses:



                  emails = re.findall(r'^([0-9a-zA-Z]([-.w]*[0-9a-zA-Z])*@(([0-9a-zA-Z])+([-w]*[0-9a-zA-Z])*.)+[a-zA-Z]{2,9})$',s)






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 19 '18 at 16:48









                  TimTim

                  1,767620




                  1,767620















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