Fix sql injection












0















I try to rebuild this function



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
data = db.query("select stack_area from screen_coordinates where screen_area = " + screen_area + " and active = 1")
return data[0]['stack_area']


To



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
sql = "select stack_area from screen_coordinates where screen_area = ? and active = ?"
row = db.query.first(sql, (screen_area,1))
return data[0]['stack_area']


But there is syntax error at or near "and". What I do wrong? First function works good but not safety. I use py-postgresql










share|improve this question

























  • What library are you using? That will affect what characters will be treated as placeholders. The error message you give implies the `? as being passed literally to the SQL engine, rather than be replaced first by the given arguments.

    – chepner
    Nov 19 '18 at 19:19











  • @chepner I use py-postgresql

    – dany
    Nov 19 '18 at 19:22






  • 1





    The example on pypi.org/project/py-postgresql suggests sql = "select ... where screen_area = $1 and active = $2" instead.

    – chepner
    Nov 19 '18 at 19:25













  • @chepner Thanks. It works. If post the answer I vote for it

    – dany
    Nov 19 '18 at 19:34
















0















I try to rebuild this function



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
data = db.query("select stack_area from screen_coordinates where screen_area = " + screen_area + " and active = 1")
return data[0]['stack_area']


To



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
sql = "select stack_area from screen_coordinates where screen_area = ? and active = ?"
row = db.query.first(sql, (screen_area,1))
return data[0]['stack_area']


But there is syntax error at or near "and". What I do wrong? First function works good but not safety. I use py-postgresql










share|improve this question

























  • What library are you using? That will affect what characters will be treated as placeholders. The error message you give implies the `? as being passed literally to the SQL engine, rather than be replaced first by the given arguments.

    – chepner
    Nov 19 '18 at 19:19











  • @chepner I use py-postgresql

    – dany
    Nov 19 '18 at 19:22






  • 1





    The example on pypi.org/project/py-postgresql suggests sql = "select ... where screen_area = $1 and active = $2" instead.

    – chepner
    Nov 19 '18 at 19:25













  • @chepner Thanks. It works. If post the answer I vote for it

    – dany
    Nov 19 '18 at 19:34














0












0








0








I try to rebuild this function



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
data = db.query("select stack_area from screen_coordinates where screen_area = " + screen_area + " and active = 1")
return data[0]['stack_area']


To



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
sql = "select stack_area from screen_coordinates where screen_area = ? and active = ?"
row = db.query.first(sql, (screen_area,1))
return data[0]['stack_area']


But there is syntax error at or near "and". What I do wrong? First function works good but not safety. I use py-postgresql










share|improve this question
















I try to rebuild this function



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
data = db.query("select stack_area from screen_coordinates where screen_area = " + screen_area + " and active = 1")
return data[0]['stack_area']


To



def getStackArea(screen_area):
db = postgresql.open(db_conf.connectionString())
sql = "select stack_area from screen_coordinates where screen_area = ? and active = ?"
row = db.query.first(sql, (screen_area,1))
return data[0]['stack_area']


But there is syntax error at or near "and". What I do wrong? First function works good but not safety. I use py-postgresql







python postgresql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 19:23







dany

















asked Nov 19 '18 at 19:15









danydany

62




62













  • What library are you using? That will affect what characters will be treated as placeholders. The error message you give implies the `? as being passed literally to the SQL engine, rather than be replaced first by the given arguments.

    – chepner
    Nov 19 '18 at 19:19











  • @chepner I use py-postgresql

    – dany
    Nov 19 '18 at 19:22






  • 1





    The example on pypi.org/project/py-postgresql suggests sql = "select ... where screen_area = $1 and active = $2" instead.

    – chepner
    Nov 19 '18 at 19:25













  • @chepner Thanks. It works. If post the answer I vote for it

    – dany
    Nov 19 '18 at 19:34



















  • What library are you using? That will affect what characters will be treated as placeholders. The error message you give implies the `? as being passed literally to the SQL engine, rather than be replaced first by the given arguments.

    – chepner
    Nov 19 '18 at 19:19











  • @chepner I use py-postgresql

    – dany
    Nov 19 '18 at 19:22






  • 1





    The example on pypi.org/project/py-postgresql suggests sql = "select ... where screen_area = $1 and active = $2" instead.

    – chepner
    Nov 19 '18 at 19:25













  • @chepner Thanks. It works. If post the answer I vote for it

    – dany
    Nov 19 '18 at 19:34

















What library are you using? That will affect what characters will be treated as placeholders. The error message you give implies the `? as being passed literally to the SQL engine, rather than be replaced first by the given arguments.

– chepner
Nov 19 '18 at 19:19





What library are you using? That will affect what characters will be treated as placeholders. The error message you give implies the `? as being passed literally to the SQL engine, rather than be replaced first by the given arguments.

– chepner
Nov 19 '18 at 19:19













@chepner I use py-postgresql

– dany
Nov 19 '18 at 19:22





@chepner I use py-postgresql

– dany
Nov 19 '18 at 19:22




1




1





The example on pypi.org/project/py-postgresql suggests sql = "select ... where screen_area = $1 and active = $2" instead.

– chepner
Nov 19 '18 at 19:25







The example on pypi.org/project/py-postgresql suggests sql = "select ... where screen_area = $1 and active = $2" instead.

– chepner
Nov 19 '18 at 19:25















@chepner Thanks. It works. If post the answer I vote for it

– dany
Nov 19 '18 at 19:34





@chepner Thanks. It works. If post the answer I vote for it

– dany
Nov 19 '18 at 19:34












1 Answer
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py-postgresql uses numbered parameters $1, $2, etc, rather than ? as placeholders.



sql = "select stack_area from screen_coordinates where screen_area = $1 and active = $2"





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    0














    py-postgresql uses numbered parameters $1, $2, etc, rather than ? as placeholders.



    sql = "select stack_area from screen_coordinates where screen_area = $1 and active = $2"





    share|improve this answer




























      0














      py-postgresql uses numbered parameters $1, $2, etc, rather than ? as placeholders.



      sql = "select stack_area from screen_coordinates where screen_area = $1 and active = $2"





      share|improve this answer


























        0












        0








        0







        py-postgresql uses numbered parameters $1, $2, etc, rather than ? as placeholders.



        sql = "select stack_area from screen_coordinates where screen_area = $1 and active = $2"





        share|improve this answer













        py-postgresql uses numbered parameters $1, $2, etc, rather than ? as placeholders.



        sql = "select stack_area from screen_coordinates where screen_area = $1 and active = $2"






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 19 '18 at 19:56









        chepnerchepner

        250k33236331




        250k33236331
































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