How to evaluate date from a string












1















Here are my files :



conf.txt



case1:fooYYYYmmdd.bar

case2:helloYYYYmmdd.world


script.sh



fname=`grep $1 conf.txt | cut -d ':' -f2`


When calling my script.sh with a parameter being case1 or case2, I obviously get my var fname fed with fooYYYYmmdd.bar or helloYYYmmdd.world.



How could I evaluate the date from my conf.txt so fname would be set with foo20181120.bar and hello20181120.world without going through breaking and building back my string ?










share|improve this question



























    1















    Here are my files :



    conf.txt



    case1:fooYYYYmmdd.bar

    case2:helloYYYYmmdd.world


    script.sh



    fname=`grep $1 conf.txt | cut -d ':' -f2`


    When calling my script.sh with a parameter being case1 or case2, I obviously get my var fname fed with fooYYYYmmdd.bar or helloYYYmmdd.world.



    How could I evaluate the date from my conf.txt so fname would be set with foo20181120.bar and hello20181120.world without going through breaking and building back my string ?










    share|improve this question

























      1












      1








      1








      Here are my files :



      conf.txt



      case1:fooYYYYmmdd.bar

      case2:helloYYYYmmdd.world


      script.sh



      fname=`grep $1 conf.txt | cut -d ':' -f2`


      When calling my script.sh with a parameter being case1 or case2, I obviously get my var fname fed with fooYYYYmmdd.bar or helloYYYmmdd.world.



      How could I evaluate the date from my conf.txt so fname would be set with foo20181120.bar and hello20181120.world without going through breaking and building back my string ?










      share|improve this question














      Here are my files :



      conf.txt



      case1:fooYYYYmmdd.bar

      case2:helloYYYYmmdd.world


      script.sh



      fname=`grep $1 conf.txt | cut -d ':' -f2`


      When calling my script.sh with a parameter being case1 or case2, I obviously get my var fname fed with fooYYYYmmdd.bar or helloYYYmmdd.world.



      How could I evaluate the date from my conf.txt so fname would be set with foo20181120.bar and hello20181120.world without going through breaking and building back my string ?







      bash shell date variables ksh






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Nov 20 '18 at 7:45









      WillWill

      418316




      418316
























          1 Answer
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          You could just declare a Date variable and use it in fname, like this:



          Date=$(date +%Y%m%d)

          fname=$(grep $1 conf.txt |sed "s/YYYYmmdd/$Date/g"|cut -d ':' -f2)
          echo $fname





          share|improve this answer

























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            1 Answer
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            active

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            active

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            1














            You could just declare a Date variable and use it in fname, like this:



            Date=$(date +%Y%m%d)

            fname=$(grep $1 conf.txt |sed "s/YYYYmmdd/$Date/g"|cut -d ':' -f2)
            echo $fname





            share|improve this answer






























              1














              You could just declare a Date variable and use it in fname, like this:



              Date=$(date +%Y%m%d)

              fname=$(grep $1 conf.txt |sed "s/YYYYmmdd/$Date/g"|cut -d ':' -f2)
              echo $fname





              share|improve this answer




























                1












                1








                1







                You could just declare a Date variable and use it in fname, like this:



                Date=$(date +%Y%m%d)

                fname=$(grep $1 conf.txt |sed "s/YYYYmmdd/$Date/g"|cut -d ':' -f2)
                echo $fname





                share|improve this answer















                You could just declare a Date variable and use it in fname, like this:



                Date=$(date +%Y%m%d)

                fname=$(grep $1 conf.txt |sed "s/YYYYmmdd/$Date/g"|cut -d ':' -f2)
                echo $fname






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 20 '18 at 9:02

























                answered Nov 20 '18 at 8:10









                User123User123

                647413




                647413
































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