whats the equivalent of java's instanceof in Swift?

Just like java's instanceOf keyword whats the equivalent in Swift?

java example:

A a = new A();

boolean isInstanceOfA = a instanceof A;

Here isInstanceOfA is true

So i need something similar in Swift

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

2

try operator "is": a is A

– nerowolfe
Jun 1 '16 at 8:30

nevermind I found the answer in one of stackoverflow chat rooms

– Bhargav
Jun 1 '16 at 8:31

or maybe I should delete this question if its already answer, a link to a similarly asked question would be good.

– Bhargav
Jun 1 '16 at 8:32

1

You can use is operator An example can be found here: stackoverflow.com/a/36900103/4791032

– Bogdan Ustyak
Jun 1 '16 at 8:32

add a comment |

Just like java's instanceOf keyword whats the equivalent in Swift?

java example:

A a = new A();

boolean isInstanceOfA = a instanceof A;

Here isInstanceOfA is true

So i need something similar in Swift

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

2

try operator "is": a is A

– nerowolfe
Jun 1 '16 at 8:30

nevermind I found the answer in one of stackoverflow chat rooms

– Bhargav
Jun 1 '16 at 8:31

or maybe I should delete this question if its already answer, a link to a similarly asked question would be good.

– Bhargav
Jun 1 '16 at 8:32

1

You can use is operator An example can be found here: stackoverflow.com/a/36900103/4791032

– Bogdan Ustyak
Jun 1 '16 at 8:32

add a comment |

Just like java's instanceOf keyword whats the equivalent in Swift?

java example:

A a = new A();

boolean isInstanceOfA = a instanceof A;

Here isInstanceOfA is true

So i need something similar in Swift

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

Just like java's instanceOf keyword whats the equivalent in Swift?

java example:

A a = new A();

boolean isInstanceOfA = a instanceof A;

Here isInstanceOfA is true

So i need something similar in Swift

ios swift

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

asked Jun 1 '16 at 8:28

Bhargav

5,41912551

2

try operator "is": a is A

– nerowolfe
Jun 1 '16 at 8:30

nevermind I found the answer in one of stackoverflow chat rooms

– Bhargav
Jun 1 '16 at 8:31

or maybe I should delete this question if its already answer, a link to a similarly asked question would be good.

– Bhargav
Jun 1 '16 at 8:32

1

You can use is operator An example can be found here: stackoverflow.com/a/36900103/4791032

– Bogdan Ustyak
Jun 1 '16 at 8:32

add a comment |

2

try operator "is": a is A

– nerowolfe
Jun 1 '16 at 8:30

nevermind I found the answer in one of stackoverflow chat rooms

– Bhargav
Jun 1 '16 at 8:31

or maybe I should delete this question if its already answer, a link to a similarly asked question would be good.

– Bhargav
Jun 1 '16 at 8:32

1

You can use is operator An example can be found here: stackoverflow.com/a/36900103/4791032

– Bogdan Ustyak
Jun 1 '16 at 8:32

try operator "is": a is A

– nerowolfe
Jun 1 '16 at 8:30

nevermind I found the answer in one of stackoverflow chat rooms

– Bhargav
Jun 1 '16 at 8:31

or maybe I should delete this question if its already answer, a link to a similarly asked question would be good.

– Bhargav
Jun 1 '16 at 8:32

You can use is operator An example can be found here: stackoverflow.com/a/36900103/4791032

– Bogdan Ustyak
Jun 1 '16 at 8:32

add a comment |

5 Answers
5

active

oldest

votes

isKindOfClass() method, from NSObjectProtocol is the equivalent of java's instanceof keyword, in java it's a keyword but in swift it's a protocol method, but they behave similarly and are used in similar contexts.

isKindOfClass: returns YES if the receiver is an instance of the
specified class or an instance of any class that inherits from the
specified class.

Which is exactly what instanceof keyword does in Java related link

Example:

let a: A = A()

let isInstanceOfA: Bool = a.isKindOfClass(A) // returns true.

Also you can use the is keyword

let a: A = A()

let isInstanceOfA: Bool = a is A

The difference:

is works with any class in Swift, whereas isKindOfClass() works only with those classes that are subclasses of NSObject or otherwise implement NSObjectProtocol.

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

So no is keyword doesn't work like instanceof

edited Jun 1 '16 at 9:53

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

1

AFAIK there aren't any cases where isKindOfClass is required. I would strongly suggest the answer is amended to make clear that is would be the preferred usage.

– PeejWeej
Sep 1 '17 at 21:58

@PEEJWEEJ the intention here is to provide all available options and what exactly it does thereby giving a "Complete" answer.

– Bhargav
Sep 4 '17 at 4:13

1

Yeah and that's fine, but given that it's Objective-C and not Swift and thus will be unavailable on any platform not including the Objective-C runtime, isKindOfClass is a platform specific alternative, not the Swift equivalent.

– PeejWeej
Sep 4 '17 at 17:39

add a comment |

let a = A()

let isInstanceOfA = a is A

answered Jun 1 '16 at 8:38

ZHZ

1,570715

is keyword works like instanceof?

– Bhargav
Jun 1 '16 at 8:45

yes, same as instanceof

– ZHZ
Jun 1 '16 at 8:57

ill give it a try

– Bhargav
Jun 1 '16 at 9:06

then this begs the question whats the difference between isKindOfClass method and is keyword

– Bhargav
Jun 1 '16 at 9:25

1

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

– Bhargav
Jun 1 '16 at 9:53

add a comment |

For swift3 and swift4 it's:

if someInstance is SomeClass {

    ...

}

if your class is extending NSObject you can also use:

if someInstance.isKind(of: SomeClass.self) {

    ...

}

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

answered Aug 7 '17 at 15:35

algrid

2,28121014

This is actually valid from Swift 1.0

– Sulthan
Nov 22 '18 at 15:34

add a comment |

For Swift 4.x it's:

func getOrElse<T>(defaultVal:T) -> T {

    if let selfVal = self, selfVal is T {

        return selfVal as! T

    } else {

        return defaultVal

    }

}

Very short variant(by suggestion @Sulthan):

extension Optional {

    func getOrElse<T>(defaultVal:T) -> T {

        return (self as? T) ?? defaultVal

    }

}

edited Nov 23 '18 at 6:47

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

1

You know that this would be easier to implement using (self as? T) ?? defaultVal?

– Sulthan
Nov 22 '18 at 15:35

Unlike Java, in Swift optionals are a native type and there are language operators that work with them. Thats why you rarely have to define new methods on Optional - the necessary funcionality is already there.

– Sulthan
Nov 23 '18 at 6:53

add a comment |

-1

With objective-c it's isKindOfClass:[ClassName class].

With swift it's isKindOfClass(Classname.class()).

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

isKindOfClass: returns YES if the receiver is an instance of the
specified class or an instance of any class that inherits from the
specified class.

Which is exactly what instanceof keyword does in Java related link

Example:

let a: A = A()

let isInstanceOfA: Bool = a.isKindOfClass(A) // returns true.

Also you can use the is keyword

let a: A = A()

let isInstanceOfA: Bool = a is A

The difference:

is works with any class in Swift, whereas isKindOfClass() works only with those classes that are subclasses of NSObject or otherwise implement NSObjectProtocol.

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

So no is keyword doesn't work like instanceof

edited Jun 1 '16 at 9:53

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

1

AFAIK there aren't any cases where isKindOfClass is required. I would strongly suggest the answer is amended to make clear that is would be the preferred usage.

– PeejWeej
Sep 1 '17 at 21:58

@PEEJWEEJ the intention here is to provide all available options and what exactly it does thereby giving a "Complete" answer.

– Bhargav
Sep 4 '17 at 4:13

1

Yeah and that's fine, but given that it's Objective-C and not Swift and thus will be unavailable on any platform not including the Objective-C runtime, isKindOfClass is a platform specific alternative, not the Swift equivalent.

– PeejWeej
Sep 4 '17 at 17:39

add a comment |

isKindOfClass: returns YES if the receiver is an instance of the
specified class or an instance of any class that inherits from the
specified class.

Which is exactly what instanceof keyword does in Java related link

Example:

let a: A = A()

let isInstanceOfA: Bool = a.isKindOfClass(A) // returns true.

Also you can use the is keyword

let a: A = A()

let isInstanceOfA: Bool = a is A

The difference:

is works with any class in Swift, whereas isKindOfClass() works only with those classes that are subclasses of NSObject or otherwise implement NSObjectProtocol.

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

So no is keyword doesn't work like instanceof

edited Jun 1 '16 at 9:53

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

1

AFAIK there aren't any cases where isKindOfClass is required. I would strongly suggest the answer is amended to make clear that is would be the preferred usage.

– PeejWeej
Sep 1 '17 at 21:58

@PEEJWEEJ the intention here is to provide all available options and what exactly it does thereby giving a "Complete" answer.

– Bhargav
Sep 4 '17 at 4:13

1

Yeah and that's fine, but given that it's Objective-C and not Swift and thus will be unavailable on any platform not including the Objective-C runtime, isKindOfClass is a platform specific alternative, not the Swift equivalent.

– PeejWeej
Sep 4 '17 at 17:39

add a comment |

isKindOfClass: returns YES if the receiver is an instance of the
specified class or an instance of any class that inherits from the
specified class.

Which is exactly what instanceof keyword does in Java related link

Example:

let a: A = A()

let isInstanceOfA: Bool = a.isKindOfClass(A) // returns true.

Also you can use the is keyword

let a: A = A()

let isInstanceOfA: Bool = a is A

The difference:

is works with any class in Swift, whereas isKindOfClass() works only with those classes that are subclasses of NSObject or otherwise implement NSObjectProtocol.

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

So no is keyword doesn't work like instanceof

edited Jun 1 '16 at 9:53

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

isKindOfClass: returns YES if the receiver is an instance of the
specified class or an instance of any class that inherits from the
specified class.

Which is exactly what instanceof keyword does in Java related link

Example:

let a: A = A()

let isInstanceOfA: Bool = a.isKindOfClass(A) // returns true.

Also you can use the is keyword

let a: A = A()

let isInstanceOfA: Bool = a is A

The difference:

is works with any class in Swift, whereas isKindOfClass() works only with those classes that are subclasses of NSObject or otherwise implement NSObjectProtocol.

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

So no is keyword doesn't work like instanceof

edited Jun 1 '16 at 9:53

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

edited Jun 1 '16 at 9:53

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

answered Jun 1 '16 at 8:30

Bhargav

5,41912551

1

AFAIK there aren't any cases where isKindOfClass is required. I would strongly suggest the answer is amended to make clear that is would be the preferred usage.

– PeejWeej
Sep 1 '17 at 21:58

@PEEJWEEJ the intention here is to provide all available options and what exactly it does thereby giving a "Complete" answer.

– Bhargav
Sep 4 '17 at 4:13

1

Yeah and that's fine, but given that it's Objective-C and not Swift and thus will be unavailable on any platform not including the Objective-C runtime, isKindOfClass is a platform specific alternative, not the Swift equivalent.

– PeejWeej
Sep 4 '17 at 17:39

add a comment |

1

AFAIK there aren't any cases where isKindOfClass is required. I would strongly suggest the answer is amended to make clear that is would be the preferred usage.

– PeejWeej
Sep 1 '17 at 21:58

@PEEJWEEJ the intention here is to provide all available options and what exactly it does thereby giving a "Complete" answer.

– Bhargav
Sep 4 '17 at 4:13

1

Yeah and that's fine, but given that it's Objective-C and not Swift and thus will be unavailable on any platform not including the Objective-C runtime, isKindOfClass is a platform specific alternative, not the Swift equivalent.

– PeejWeej
Sep 4 '17 at 17:39

AFAIK there aren't any cases where isKindOfClass is required. I would strongly suggest the answer is amended to make clear that is would be the preferred usage.

– PeejWeej
Sep 1 '17 at 21:58

@PEEJWEEJ the intention here is to provide all available options and what exactly it does thereby giving a "Complete" answer.

– Bhargav
Sep 4 '17 at 4:13

Yeah and that's fine, but given that it's Objective-C and not Swift and thus will be unavailable on any platform not including the Objective-C runtime, isKindOfClass is a platform specific alternative, not the Swift equivalent.

– PeejWeej
Sep 4 '17 at 17:39

add a comment |

let a = A()

let isInstanceOfA = a is A

answered Jun 1 '16 at 8:38

ZHZ

1,570715

is keyword works like instanceof?

– Bhargav
Jun 1 '16 at 8:45

yes, same as instanceof

– ZHZ
Jun 1 '16 at 8:57

ill give it a try

– Bhargav
Jun 1 '16 at 9:06

then this begs the question whats the difference between isKindOfClass method and is keyword

– Bhargav
Jun 1 '16 at 9:25

1

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

– Bhargav
Jun 1 '16 at 9:53

add a comment |

let a = A()

let isInstanceOfA = a is A

answered Jun 1 '16 at 8:38

ZHZ

1,570715

is keyword works like instanceof?

– Bhargav
Jun 1 '16 at 8:45

yes, same as instanceof

– ZHZ
Jun 1 '16 at 8:57

ill give it a try

– Bhargav
Jun 1 '16 at 9:06

then this begs the question whats the difference between isKindOfClass method and is keyword

– Bhargav
Jun 1 '16 at 9:25

1

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

– Bhargav
Jun 1 '16 at 9:53

add a comment |

let a = A()

let isInstanceOfA = a is A

answered Jun 1 '16 at 8:38

ZHZ

1,570715

let a = A()

let isInstanceOfA = a is A

answered Jun 1 '16 at 8:38

ZHZ

1,570715

answered Jun 1 '16 at 8:38

ZHZ

1,570715

answered Jun 1 '16 at 8:38

ZHZ

1,570715

answered Jun 1 '16 at 8:38

ZHZ

1,570715

is keyword works like instanceof?

– Bhargav
Jun 1 '16 at 8:45

yes, same as instanceof

– ZHZ
Jun 1 '16 at 8:57

ill give it a try

– Bhargav
Jun 1 '16 at 9:06

then this begs the question whats the difference between isKindOfClass method and is keyword

– Bhargav
Jun 1 '16 at 9:25

1

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

– Bhargav
Jun 1 '16 at 9:53

add a comment |

is keyword works like instanceof?

– Bhargav
Jun 1 '16 at 8:45

yes, same as instanceof

– ZHZ
Jun 1 '16 at 8:57

ill give it a try

– Bhargav
Jun 1 '16 at 9:06

then this begs the question whats the difference between isKindOfClass method and is keyword

– Bhargav
Jun 1 '16 at 9:25

1

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

– Bhargav
Jun 1 '16 at 9:53

is keyword works like instanceof?

– Bhargav
Jun 1 '16 at 8:45

yes, same as instanceof

– ZHZ
Jun 1 '16 at 8:57

ill give it a try

– Bhargav
Jun 1 '16 at 9:06

then this begs the question whats the difference between isKindOfClass method and is keyword

– Bhargav
Jun 1 '16 at 9:25

is takes a type that must be hard-coded at compile-time. isKindOfClass: takes an expression whose value can be computed at runtime.

– Bhargav
Jun 1 '16 at 9:53

add a comment |

For swift3 and swift4 it's:

if someInstance is SomeClass {

    ...

}

if your class is extending NSObject you can also use:

if someInstance.isKind(of: SomeClass.self) {

    ...

}

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

answered Aug 7 '17 at 15:35

algrid

2,28121014

This is actually valid from Swift 1.0

– Sulthan
Nov 22 '18 at 15:34

add a comment |

For swift3 and swift4 it's:

if someInstance is SomeClass {

    ...

}

if your class is extending NSObject you can also use:

if someInstance.isKind(of: SomeClass.self) {

    ...

}

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

answered Aug 7 '17 at 15:35

algrid

2,28121014

This is actually valid from Swift 1.0

– Sulthan
Nov 22 '18 at 15:34

add a comment |

For swift3 and swift4 it's:

if someInstance is SomeClass {

    ...

}

if your class is extending NSObject you can also use:

if someInstance.isKind(of: SomeClass.self) {

    ...

}

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

answered Aug 7 '17 at 15:35

algrid

2,28121014

For swift3 and swift4 it's:

if someInstance is SomeClass {

    ...

}

if your class is extending NSObject you can also use:

if someInstance.isKind(of: SomeClass.self) {

    ...

}

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

answered Aug 7 '17 at 15:35

algrid

2,28121014

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

edited Nov 22 '18 at 15:26

Mariusz Wiazowski

508513

answered Aug 7 '17 at 15:35

algrid

2,28121014

answered Aug 7 '17 at 15:35

algrid

2,28121014

answered Aug 7 '17 at 15:35

algrid

2,28121014

This is actually valid from Swift 1.0

– Sulthan
Nov 22 '18 at 15:34

add a comment |

This is actually valid from Swift 1.0

– Sulthan
Nov 22 '18 at 15:34

This is actually valid from Swift 1.0

– Sulthan
Nov 22 '18 at 15:34

add a comment |

For Swift 4.x it's:

func getOrElse<T>(defaultVal:T) -> T {

    if let selfVal = self, selfVal is T {

        return selfVal as! T

    } else {

        return defaultVal

    }

}

Very short variant(by suggestion @Sulthan):

extension Optional {

    func getOrElse<T>(defaultVal:T) -> T {

        return (self as? T) ?? defaultVal

    }

}

edited Nov 23 '18 at 6:47

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

1

You know that this would be easier to implement using (self as? T) ?? defaultVal?

– Sulthan
Nov 22 '18 at 15:35

Unlike Java, in Swift optionals are a native type and there are language operators that work with them. Thats why you rarely have to define new methods on Optional - the necessary funcionality is already there.

– Sulthan
Nov 23 '18 at 6:53

add a comment |

For Swift 4.x it's:

func getOrElse<T>(defaultVal:T) -> T {

    if let selfVal = self, selfVal is T {

        return selfVal as! T

    } else {

        return defaultVal

    }

}

Very short variant(by suggestion @Sulthan):

extension Optional {

    func getOrElse<T>(defaultVal:T) -> T {

        return (self as? T) ?? defaultVal

    }

}

edited Nov 23 '18 at 6:47

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

1

You know that this would be easier to implement using (self as? T) ?? defaultVal?

– Sulthan
Nov 22 '18 at 15:35

Unlike Java, in Swift optionals are a native type and there are language operators that work with them. Thats why you rarely have to define new methods on Optional - the necessary funcionality is already there.

– Sulthan
Nov 23 '18 at 6:53

add a comment |

For Swift 4.x it's:

func getOrElse<T>(defaultVal:T) -> T {

    if let selfVal = self, selfVal is T {

        return selfVal as! T

    } else {

        return defaultVal

    }

}

Very short variant(by suggestion @Sulthan):

extension Optional {

    func getOrElse<T>(defaultVal:T) -> T {

        return (self as? T) ?? defaultVal

    }

}

edited Nov 23 '18 at 6:47

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

For Swift 4.x it's:

func getOrElse<T>(defaultVal:T) -> T {

    if let selfVal = self, selfVal is T {

        return selfVal as! T

    } else {

        return defaultVal

    }

}

Very short variant(by suggestion @Sulthan):

extension Optional {

    func getOrElse<T>(defaultVal:T) -> T {

        return (self as? T) ?? defaultVal

    }

}

edited Nov 23 '18 at 6:47

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

edited Nov 23 '18 at 6:47

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

answered Nov 20 '18 at 6:36

mr.boyfox

9,18054361

1

You know that this would be easier to implement using (self as? T) ?? defaultVal?

– Sulthan
Nov 22 '18 at 15:35

Unlike Java, in Swift optionals are a native type and there are language operators that work with them. Thats why you rarely have to define new methods on Optional - the necessary funcionality is already there.

– Sulthan
Nov 23 '18 at 6:53

add a comment |

1

You know that this would be easier to implement using (self as? T) ?? defaultVal?

– Sulthan
Nov 22 '18 at 15:35

Unlike Java, in Swift optionals are a native type and there are language operators that work with them. Thats why you rarely have to define new methods on Optional - the necessary funcionality is already there.

– Sulthan
Nov 23 '18 at 6:53

You know that this would be easier to implement using (self as? T) ?? defaultVal?

– Sulthan
Nov 22 '18 at 15:35

Unlike Java, in Swift optionals are a native type and there are language operators that work with them. Thats why you rarely have to define new methods on Optional - the necessary funcionality is already there.

– Sulthan
Nov 23 '18 at 6:53

add a comment |

-1

With objective-c it's isKindOfClass:[ClassName class].

With swift it's isKindOfClass(Classname.class()).

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

add a comment |

-1

With objective-c it's isKindOfClass:[ClassName class].

With swift it's isKindOfClass(Classname.class()).

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

add a comment |

-1

With objective-c it's isKindOfClass:[ClassName class].

With swift it's isKindOfClass(Classname.class()).

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

With objective-c it's isKindOfClass:[ClassName class].

With swift it's isKindOfClass(Classname.class()).

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

edited Jun 1 '16 at 9:08

Aleksander Azizi

7,60665484

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

answered Jun 1 '16 at 8:39

Pushkraj

1,6751525

add a comment |

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