Why sql subtraction two colon
-2
code:
SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2,
examplecolon1 -(2 * examplecolon2) from
.................
example:
subtraction error :
examplecolon1 -(2 * examplecolon2)
why solved the problem?
sql
edited Nov 20 '18 at 12:38
fa06
15k2917
asked Nov 20 '18 at 12:36
michaelmichael
13
add a comment |
-2
code:
SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2,
examplecolon1 -(2 * examplecolon2) from
.................
example:
subtraction error :
examplecolon1 -(2 * examplecolon2)
why solved the problem?
sql
edited Nov 20 '18 at 12:38
fa06
15k2917
asked Nov 20 '18 at 12:36
michaelmichael
13
please provide sample data and expected output
– fa06
Nov 20 '18 at 12:37
1
You cannot re-use column aliases in the sameSELECTwhere they are defined. You need to use a subquery, CTE, or similar mechanism to define the logic.
– Gordon Linoff
Nov 20 '18 at 12:37
add a comment |
-2
-2
-2
code:
SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2,
examplecolon1 -(2 * examplecolon2) from
.................
example:
subtraction error :
examplecolon1 -(2 * examplecolon2)
why solved the problem?
sql
edited Nov 20 '18 at 12:38
fa06
15k2917
asked Nov 20 '18 at 12:36
michaelmichael
13
code:
SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2,
examplecolon1 -(2 * examplecolon2) from
.................
example:
subtraction error :
examplecolon1 -(2 * examplecolon2)
why solved the problem?
sql
sql
edited Nov 20 '18 at 12:38
fa06
15k2917
asked Nov 20 '18 at 12:36
michaelmichael
13
edited Nov 20 '18 at 12:38
fa06
15k2917
asked Nov 20 '18 at 12:36
michaelmichael
13
edited Nov 20 '18 at 12:38
fa06
15k2917
edited Nov 20 '18 at 12:38
fa06
15k2917
edited Nov 20 '18 at 12:38
fa06
15k2917
15k2917
asked Nov 20 '18 at 12:36
michaelmichael
13
asked Nov 20 '18 at 12:36
michaelmichael
13
asked Nov 20 '18 at 12:36
michaelmichael
13
13
please provide sample data and expected output
– fa06
Nov 20 '18 at 12:37
1
You cannot re-use column aliases in the sameSELECTwhere they are defined. You need to use a subquery, CTE, or similar mechanism to define the logic.
– Gordon Linoff
Nov 20 '18 at 12:37
add a comment |
please provide sample data and expected output
– fa06
Nov 20 '18 at 12:37
1
You cannot re-use column aliases in the sameSELECTwhere they are defined. You need to use a subquery, CTE, or similar mechanism to define the logic.
– Gordon Linoff
Nov 20 '18 at 12:37
please provide sample data and expected output
– fa06
Nov 20 '18 at 12:37
please provide sample data and expected output
– fa06
Nov 20 '18 at 12:37
1
1
You cannot re-use column aliases in the same
SELECT where they are defined. You need to use a subquery, CTE, or similar mechanism to define the logic.– Gordon Linoff
Nov 20 '18 at 12:37
You cannot re-use column aliases in the same
SELECT where they are defined. You need to use a subquery, CTE, or similar mechanism to define the logic.– Gordon Linoff
Nov 20 '18 at 12:37
add a comment |
1 Answer
1
active
oldest
votes
0
You need to use a subquery or a CTE (if your backend supports) to do that. ie:
select newcolon1, newcolon2,
examplecolon1, examplecolon2,
examplecolon1 -(2 * examplecolon2) as myNewColumn
from
(SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2
from myTable1 ms
[leftrightinner] join myTable2 mss on ... ) sq;
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
AKA derived table.
– jarlh
Nov 20 '18 at 13:20
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You need to use a subquery or a CTE (if your backend supports) to do that. ie:
select newcolon1, newcolon2,
examplecolon1, examplecolon2,
examplecolon1 -(2 * examplecolon2) as myNewColumn
from
(SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2
from myTable1 ms
[leftrightinner] join myTable2 mss on ... ) sq;
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
AKA derived table.
– jarlh
Nov 20 '18 at 13:20
add a comment |
0
You need to use a subquery or a CTE (if your backend supports) to do that. ie:
select newcolon1, newcolon2,
examplecolon1, examplecolon2,
examplecolon1 -(2 * examplecolon2) as myNewColumn
from
(SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2
from myTable1 ms
[leftrightinner] join myTable2 mss on ... ) sq;
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
AKA derived table.
– jarlh
Nov 20 '18 at 13:20
add a comment |
0
0
0
You need to use a subquery or a CTE (if your backend supports) to do that. ie:
select newcolon1, newcolon2,
examplecolon1, examplecolon2,
examplecolon1 -(2 * examplecolon2) as myNewColumn
from
(SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2
from myTable1 ms
[leftrightinner] join myTable2 mss on ... ) sq;
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
You need to use a subquery or a CTE (if your backend supports) to do that. ie:
select newcolon1, newcolon2,
examplecolon1, examplecolon2,
examplecolon1 -(2 * examplecolon2) as myNewColumn
from
(SELECT DISTINCT mss.colon1 AS newcolon1, ms.colon2 AS newcolon2,
(SELECT COUNT(mmm.numbertop) AS Expr1
FROM listtable AS mmm
WHERE (ms.number = mmm.number) ) AS examplecolon1,
(SELECT COUNT(stls.numbertop) AS Expr1
FROM listtable2 AS stls
WHERE ms.number = stls.number ) AS examplecolon2
from myTable1 ms
[leftrightinner] join myTable2 mss on ... ) sq;
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
answered Nov 20 '18 at 12:42
Cetin BasozCetin Basoz
11k11527
11k11527
AKA derived table.
– jarlh
Nov 20 '18 at 13:20
add a comment |
AKA derived table.
– jarlh
Nov 20 '18 at 13:20
AKA derived table.
– jarlh
Nov 20 '18 at 13:20
AKA derived table.
– jarlh
Nov 20 '18 at 13:20
add a comment |
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please provide sample data and expected output
– fa06
Nov 20 '18 at 12:37
1
You cannot re-use column aliases in the same
SELECTwhere they are defined. You need to use a subquery, CTE, or similar mechanism to define the logic.– Gordon Linoff
Nov 20 '18 at 12:37