How to recognize the last page of viewpager and automatically redirect to first page when swiped
0
My title is my problem, I have 3 pages in a viewPager. How do I redirect to first page when I swipe on the last page in viewPager?
ViewPager.OnPageChangeListener viewPagerPageChangeListener = new ViewPager.OnPageChangeListener() {
@Override
public void onPageSelected(int position) {
int x = position;
Log.i("ON Possition",Integer.Tostring(x));
if(x == 3){
viewPager.setCurrentItem(x);
Log.i("ON last Possition",Integer.Tostring());
}
}
@Override
public void onPageScrolled(int arg0, float arg1, int arg2) {
}
@Override
public void onPageScrollStateChanged(int arg0) {
}
};
java
android android-viewpager edited Nov 21 '18 at 9:46
Dominik
57114
asked Nov 21 '18 at 8:35
s-depts-dept
5619
add a comment |
0
My title is my problem, I have 3 pages in a viewPager. How do I redirect to first page when I swipe on the last page in viewPager?
ViewPager.OnPageChangeListener viewPagerPageChangeListener = new ViewPager.OnPageChangeListener() {
@Override
public void onPageSelected(int position) {
int x = position;
Log.i("ON Possition",Integer.Tostring(x));
if(x == 3){
viewPager.setCurrentItem(x);
Log.i("ON last Possition",Integer.Tostring());
}
}
@Override
public void onPageScrolled(int arg0, float arg1, int arg2) {
}
@Override
public void onPageScrollStateChanged(int arg0) {
}
};
java
android android-viewpager edited Nov 21 '18 at 9:46
Dominik
57114
asked Nov 21 '18 at 8:35
s-depts-dept
5619
add a comment |
0
0
0
My title is my problem, I have 3 pages in a viewPager. How do I redirect to first page when I swipe on the last page in viewPager?
ViewPager.OnPageChangeListener viewPagerPageChangeListener = new ViewPager.OnPageChangeListener() {
@Override
public void onPageSelected(int position) {
int x = position;
Log.i("ON Possition",Integer.Tostring(x));
if(x == 3){
viewPager.setCurrentItem(x);
Log.i("ON last Possition",Integer.Tostring());
}
}
@Override
public void onPageScrolled(int arg0, float arg1, int arg2) {
}
@Override
public void onPageScrollStateChanged(int arg0) {
}
};
java
android android-viewpager edited Nov 21 '18 at 9:46
Dominik
57114
asked Nov 21 '18 at 8:35
s-depts-dept
5619
My title is my problem, I have 3 pages in a viewPager. How do I redirect to first page when I swipe on the last page in viewPager?
ViewPager.OnPageChangeListener viewPagerPageChangeListener = new ViewPager.OnPageChangeListener() {
@Override
public void onPageSelected(int position) {
int x = position;
Log.i("ON Possition",Integer.Tostring(x));
if(x == 3){
viewPager.setCurrentItem(x);
Log.i("ON last Possition",Integer.Tostring());
}
}
@Override
public void onPageScrolled(int arg0, float arg1, int arg2) {
}
@Override
public void onPageScrollStateChanged(int arg0) {
}
};
java
android android-viewpager java
android android-viewpager edited Nov 21 '18 at 9:46
Dominik
57114
asked Nov 21 '18 at 8:35
s-depts-dept
5619
edited Nov 21 '18 at 9:46
Dominik
57114
asked Nov 21 '18 at 8:35
s-depts-dept
5619
edited Nov 21 '18 at 9:46
Dominik
57114
edited Nov 21 '18 at 9:46
Dominik
57114
edited Nov 21 '18 at 9:46
Dominik
57114
57114
asked Nov 21 '18 at 8:35
s-depts-dept
5619
asked Nov 21 '18 at 8:35
s-depts-dept
5619
asked Nov 21 '18 at 8:35
s-depts-dept
5619
5619
add a comment |
add a comment |
1 Answer
1
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oldest
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0
you can't move to first page smoothly from last page.
read below code. we should fake item count.
private class MyPagerAdapter extends PagerAdapter {
Context context;
public MyPagerAdapter(Context context) {
this.context= context;
}
@Override
public int getCount() {
if (tList != null && tList.size() > 1) {
return tList.size() * MAX_PAGE; // simulate infinite by big number of products
} else {
return tList.size();
}
}
@Override
public int getItemPosition(Object object) {
int position;
if (tList != null && tList.size() > 1) {
position = super.getItemPosition(object) % tList.size(); // use modulo for infinite cycling
return position;
} else {
return super.getItemPosition(object);
}
}
public int getItemPosition(int index) {
int position;
if (tList!= null && tList.size() > 1) {
position = index % tList.size(); // use modulo for infinite cycling
return position;
} else {
return index;
}
}
}
answered Nov 21 '18 at 8:52
user10684624user10684624
1
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
you can't move to first page smoothly from last page.
read below code. we should fake item count.
private class MyPagerAdapter extends PagerAdapter {
Context context;
public MyPagerAdapter(Context context) {
this.context= context;
}
@Override
public int getCount() {
if (tList != null && tList.size() > 1) {
return tList.size() * MAX_PAGE; // simulate infinite by big number of products
} else {
return tList.size();
}
}
@Override
public int getItemPosition(Object object) {
int position;
if (tList != null && tList.size() > 1) {
position = super.getItemPosition(object) % tList.size(); // use modulo for infinite cycling
return position;
} else {
return super.getItemPosition(object);
}
}
public int getItemPosition(int index) {
int position;
if (tList!= null && tList.size() > 1) {
position = index % tList.size(); // use modulo for infinite cycling
return position;
} else {
return index;
}
}
}
answered Nov 21 '18 at 8:52
user10684624user10684624
1
add a comment |
0
you can't move to first page smoothly from last page.
read below code. we should fake item count.
private class MyPagerAdapter extends PagerAdapter {
Context context;
public MyPagerAdapter(Context context) {
this.context= context;
}
@Override
public int getCount() {
if (tList != null && tList.size() > 1) {
return tList.size() * MAX_PAGE; // simulate infinite by big number of products
} else {
return tList.size();
}
}
@Override
public int getItemPosition(Object object) {
int position;
if (tList != null && tList.size() > 1) {
position = super.getItemPosition(object) % tList.size(); // use modulo for infinite cycling
return position;
} else {
return super.getItemPosition(object);
}
}
public int getItemPosition(int index) {
int position;
if (tList!= null && tList.size() > 1) {
position = index % tList.size(); // use modulo for infinite cycling
return position;
} else {
return index;
}
}
}
answered Nov 21 '18 at 8:52
user10684624user10684624
1
add a comment |
0
0
0
you can't move to first page smoothly from last page.
read below code. we should fake item count.
private class MyPagerAdapter extends PagerAdapter {
Context context;
public MyPagerAdapter(Context context) {
this.context= context;
}
@Override
public int getCount() {
if (tList != null && tList.size() > 1) {
return tList.size() * MAX_PAGE; // simulate infinite by big number of products
} else {
return tList.size();
}
}
@Override
public int getItemPosition(Object object) {
int position;
if (tList != null && tList.size() > 1) {
position = super.getItemPosition(object) % tList.size(); // use modulo for infinite cycling
return position;
} else {
return super.getItemPosition(object);
}
}
public int getItemPosition(int index) {
int position;
if (tList!= null && tList.size() > 1) {
position = index % tList.size(); // use modulo for infinite cycling
return position;
} else {
return index;
}
}
}
answered Nov 21 '18 at 8:52
user10684624user10684624
1
you can't move to first page smoothly from last page.
read below code. we should fake item count.
private class MyPagerAdapter extends PagerAdapter {
Context context;
public MyPagerAdapter(Context context) {
this.context= context;
}
@Override
public int getCount() {
if (tList != null && tList.size() > 1) {
return tList.size() * MAX_PAGE; // simulate infinite by big number of products
} else {
return tList.size();
}
}
@Override
public int getItemPosition(Object object) {
int position;
if (tList != null && tList.size() > 1) {
position = super.getItemPosition(object) % tList.size(); // use modulo for infinite cycling
return position;
} else {
return super.getItemPosition(object);
}
}
public int getItemPosition(int index) {
int position;
if (tList!= null && tList.size() > 1) {
position = index % tList.size(); // use modulo for infinite cycling
return position;
} else {
return index;
}
}
}
answered Nov 21 '18 at 8:52
user10684624user10684624
1
answered Nov 21 '18 at 8:52
user10684624user10684624
1
answered Nov 21 '18 at 8:52
user10684624user10684624
1
answered Nov 21 '18 at 8:52
user10684624user10684624
1
1
add a comment |
add a comment |
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