Masking replacing random string characters in array of objects
2
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
//desired output will be something like:
var arr = [{
email: 's*m*e*a*l@s*m*d*m*i*.n*t',
domain: 's*m*d*m*i*',
title: 's*f*w*r* d*v*l*p*r'
}];
This can be randomly masked with * it does not need to be every second char.
Thanks!
javascript
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
add a comment |
2
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
//desired output will be something like:
var arr = [{
email: 's*m*e*a*l@s*m*d*m*i*.n*t',
domain: 's*m*d*m*i*',
title: 's*f*w*r* d*v*l*p*r'
}];
This can be randomly masked with * it does not need to be every second char.
Thanks!
javascript
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
can your array object has different properties, or only email, domain and title ?
– Artyom Amiryan
Nov 21 '18 at 12:41
yes it can it will have n number of properties all will be strings.
– Ludi Kompjuteras
Nov 21 '18 at 12:42
should all properties values be changed?
– Artyom Amiryan
Nov 21 '18 at 12:42
add a comment |
2
2
2
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
//desired output will be something like:
var arr = [{
email: 's*m*e*a*l@s*m*d*m*i*.n*t',
domain: 's*m*d*m*i*',
title: 's*f*w*r* d*v*l*p*r'
}];
This can be randomly masked with * it does not need to be every second char.
Thanks!
javascript
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
//desired output will be something like:
var arr = [{
email: 's*m*e*a*l@s*m*d*m*i*.n*t',
domain: 's*m*d*m*i*',
title: 's*f*w*r* d*v*l*p*r'
}];
This can be randomly masked with * it does not need to be every second char.
Thanks!
javascript
javascript
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
asked Nov 21 '18 at 12:39
Ludi KompjuterasLudi Kompjuteras
283
283
can your array object has different properties, or only email, domain and title ?
– Artyom Amiryan
Nov 21 '18 at 12:41
yes it can it will have n number of properties all will be strings.
– Ludi Kompjuteras
Nov 21 '18 at 12:42
should all properties values be changed?
– Artyom Amiryan
Nov 21 '18 at 12:42
add a comment |
can your array object has different properties, or only email, domain and title ?
– Artyom Amiryan
Nov 21 '18 at 12:41
yes it can it will have n number of properties all will be strings.
– Ludi Kompjuteras
Nov 21 '18 at 12:42
should all properties values be changed?
– Artyom Amiryan
Nov 21 '18 at 12:42
can your array object has different properties, or only email, domain and title ?
– Artyom Amiryan
Nov 21 '18 at 12:41
can your array object has different properties, or only email, domain and title ?
– Artyom Amiryan
Nov 21 '18 at 12:41
yes it can it will have n number of properties all will be strings.
– Ludi Kompjuteras
Nov 21 '18 at 12:42
yes it can it will have n number of properties all will be strings.
– Ludi Kompjuteras
Nov 21 '18 at 12:42
should all properties values be changed?
– Artyom Amiryan
Nov 21 '18 at 12:42
should all properties values be changed?
– Artyom Amiryan
Nov 21 '18 at 12:42
add a comment |
2 Answers
2
active
oldest
votes
3
You could randomly change the characters and join the array back to a string.
var string = 'someemail@somedomain.net';
string = Array.from(string, c => Math.random() < 0.5 ? '*' : c).join('');
console.log(string);answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
add a comment |
2
You can loop through the objects and map over the string and change every 2nd, 3rd,... any letter to '*'
This solution is not for random, but for every 2nd, 3rd,... letter depending upon value passed to method
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
function getMaskedData(d, every) {
return [...d].map((v,i) => (i + 1) % every == 0 ? '*' : v).join('')
}
let newObj = {}
for(let [k, v] of Object.entries(arr[0])) {
newObj[k] = getMaskedData(v, 2)
}
console.log(newObj)answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
1
Awesome thanks!
– Ludi Kompjuteras
Nov 21 '18 at 13:00
1
Totally flexible, even no need to worry aboutkeyname
– Pardeep Jain
Nov 22 '18 at 7:42
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You could randomly change the characters and join the array back to a string.
var string = 'someemail@somedomain.net';
string = Array.from(string, c => Math.random() < 0.5 ? '*' : c).join('');
console.log(string);answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
add a comment |
3
You could randomly change the characters and join the array back to a string.
var string = 'someemail@somedomain.net';
string = Array.from(string, c => Math.random() < 0.5 ? '*' : c).join('');
console.log(string);answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
add a comment |
3
3
3
You could randomly change the characters and join the array back to a string.
var string = 'someemail@somedomain.net';
string = Array.from(string, c => Math.random() < 0.5 ? '*' : c).join('');
console.log(string);answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
You could randomly change the characters and join the array back to a string.
var string = 'someemail@somedomain.net';
string = Array.from(string, c => Math.random() < 0.5 ? '*' : c).join('');
console.log(string);var string = 'someemail@somedomain.net';
string = Array.from(string, c => Math.random() < 0.5 ? '*' : c).join('');
console.log(string);var string = 'someemail@somedomain.net';
string = Array.from(string, c => Math.random() < 0.5 ? '*' : c).join('');
console.log(string);answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
answered Nov 21 '18 at 12:43
Nina ScholzNina Scholz
193k15106177
193k15106177
add a comment |
add a comment |
2
You can loop through the objects and map over the string and change every 2nd, 3rd,... any letter to '*'
This solution is not for random, but for every 2nd, 3rd,... letter depending upon value passed to method
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
function getMaskedData(d, every) {
return [...d].map((v,i) => (i + 1) % every == 0 ? '*' : v).join('')
}
let newObj = {}
for(let [k, v] of Object.entries(arr[0])) {
newObj[k] = getMaskedData(v, 2)
}
console.log(newObj)answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
1
Awesome thanks!
– Ludi Kompjuteras
Nov 21 '18 at 13:00
1
Totally flexible, even no need to worry aboutkeyname
– Pardeep Jain
Nov 22 '18 at 7:42
add a comment |
2
You can loop through the objects and map over the string and change every 2nd, 3rd,... any letter to '*'
This solution is not for random, but for every 2nd, 3rd,... letter depending upon value passed to method
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
function getMaskedData(d, every) {
return [...d].map((v,i) => (i + 1) % every == 0 ? '*' : v).join('')
}
let newObj = {}
for(let [k, v] of Object.entries(arr[0])) {
newObj[k] = getMaskedData(v, 2)
}
console.log(newObj)answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
1
Awesome thanks!
– Ludi Kompjuteras
Nov 21 '18 at 13:00
1
Totally flexible, even no need to worry aboutkeyname
– Pardeep Jain
Nov 22 '18 at 7:42
add a comment |
2
2
2
You can loop through the objects and map over the string and change every 2nd, 3rd,... any letter to '*'
This solution is not for random, but for every 2nd, 3rd,... letter depending upon value passed to method
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
function getMaskedData(d, every) {
return [...d].map((v,i) => (i + 1) % every == 0 ? '*' : v).join('')
}
let newObj = {}
for(let [k, v] of Object.entries(arr[0])) {
newObj[k] = getMaskedData(v, 2)
}
console.log(newObj)answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
You can loop through the objects and map over the string and change every 2nd, 3rd,... any letter to '*'
This solution is not for random, but for every 2nd, 3rd,... letter depending upon value passed to method
var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
function getMaskedData(d, every) {
return [...d].map((v,i) => (i + 1) % every == 0 ? '*' : v).join('')
}
let newObj = {}
for(let [k, v] of Object.entries(arr[0])) {
newObj[k] = getMaskedData(v, 2)
}
console.log(newObj)var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
function getMaskedData(d, every) {
return [...d].map((v,i) => (i + 1) % every == 0 ? '*' : v).join('')
}
let newObj = {}
for(let [k, v] of Object.entries(arr[0])) {
newObj[k] = getMaskedData(v, 2)
}
console.log(newObj)var arr = [{
email: 'someemail@somedomain.net',
domain: 'somedomain',
title: 'software developer'
}];
function getMaskedData(d, every) {
return [...d].map((v,i) => (i + 1) % every == 0 ? '*' : v).join('')
}
let newObj = {}
for(let [k, v] of Object.entries(arr[0])) {
newObj[k] = getMaskedData(v, 2)
}
console.log(newObj)answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
answered Nov 21 '18 at 12:44
Nitish NarangNitish Narang
2,9701815
2,9701815
1
Awesome thanks!
– Ludi Kompjuteras
Nov 21 '18 at 13:00
1
Totally flexible, even no need to worry aboutkeyname
– Pardeep Jain
Nov 22 '18 at 7:42
add a comment |
1
Awesome thanks!
– Ludi Kompjuteras
Nov 21 '18 at 13:00
1
Totally flexible, even no need to worry aboutkeyname
– Pardeep Jain
Nov 22 '18 at 7:42
1
1
Awesome thanks!
– Ludi Kompjuteras
Nov 21 '18 at 13:00
Awesome thanks!
– Ludi Kompjuteras
Nov 21 '18 at 13:00
1
1
Totally flexible, even no need to worry about
key name– Pardeep Jain
Nov 22 '18 at 7:42
Totally flexible, even no need to worry about
key name– Pardeep Jain
Nov 22 '18 at 7:42
add a comment |
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can your array object has different properties, or only email, domain and title ?
– Artyom Amiryan
Nov 21 '18 at 12:41
yes it can it will have n number of properties all will be strings.
– Ludi Kompjuteras
Nov 21 '18 at 12:42
should all properties values be changed?
– Artyom Amiryan
Nov 21 '18 at 12:42