find the particular node which fit three criteria neo4j
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I would like to find the name node which trade with three fruits only.
I tried to use the following code in neo4j.
match (s:good)-[r:TRADES]-(n:Name)-[:TRADES]-(p:good)
WHERE (s.good = 'Apple' or s.good='Orange') and p.stock ='Grapes'
return s,n,p
where it returns the query as below.
However, I just want the following. Just the one who trade Grapes, Orange and Apple only.
I don't know which part of the cypher is incorrect. thank you for helping
neo4j
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
add a comment |
I would like to find the name node which trade with three fruits only.
I tried to use the following code in neo4j.
match (s:good)-[r:TRADES]-(n:Name)-[:TRADES]-(p:good)
WHERE (s.good = 'Apple' or s.good='Orange') and p.stock ='Grapes'
return s,n,p
where it returns the query as below.
However, I just want the following. Just the one who trade Grapes, Orange and Apple only.
I don't know which part of the cypher is incorrect. thank you for helping
neo4j
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
add a comment |
I would like to find the name node which trade with three fruits only.
I tried to use the following code in neo4j.
match (s:good)-[r:TRADES]-(n:Name)-[:TRADES]-(p:good)
WHERE (s.good = 'Apple' or s.good='Orange') and p.stock ='Grapes'
return s,n,p
where it returns the query as below.
However, I just want the following. Just the one who trade Grapes, Orange and Apple only.
I don't know which part of the cypher is incorrect. thank you for helping
neo4j
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
I would like to find the name node which trade with three fruits only.
I tried to use the following code in neo4j.
match (s:good)-[r:TRADES]-(n:Name)-[:TRADES]-(p:good)
WHERE (s.good = 'Apple' or s.good='Orange') and p.stock ='Grapes'
return s,n,p
where it returns the query as below.
However, I just want the following. Just the one who trade Grapes, Orange and Apple only.
I don't know which part of the cypher is incorrect. thank you for helping
neo4j
neo4j
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
asked Nov 22 '18 at 4:16
Platalea MinorPlatalea Minor
16412
16412
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
We have a knowledge base article on match intersection, what you're trying to do here, however your other restriction is that these are the only 3 connected nodes, so we have some additional work to do.
Using the first approach in the article, we just have to add an additional predicate to ensure the degree of :TRADES relationships equals the size of the collection:
WITH ['Apple', 'Orange', 'Grapes'] as names
MATCH (g:good)<-[:TRADES]-(n:Name)
WHERE g.good in names AND size((n)-[:TRADES]->()) = size(names)
WITH n, size(names) as inputCnt, count(DISTINCT g) as cnt
WHERE cnt = inputCnt
RETURN n
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
Hi @InverseFalcon I would like to know if I have another query with more than 5 fruits. What I need to need change is from three elements to five elements on WITH ['Apple', 'Orange', 'Grapes'] as names ?
– Platalea Minor
Dec 5 '18 at 8:17
The type of query provided doesn't use any hard-coded numbers for expected values, if you read through it you should notice it uses the number of elements in your input, so whether it's 3 or 5 or 5000 it should work the same.
– InverseFalcon
Dec 5 '18 at 9:28
However, if I want to query if any name node which have connected with three or more fruit nodes. I think this query won't be able to provide the name nodes?
– Platalea Minor
Dec 5 '18 at 9:40
Then just change up the last WHERE clause with the numbers you want:WHERE cnt >= 3
– InverseFalcon
Dec 5 '18 at 19:45
Hi @InverseFalcon Thank you for your help, yet it cannot resolve the question. I have raised another question below. If you have time please take a look. Thank you so much stackoverflow.com/questions/53629951/find-cluster-in-neo4j
– Platalea Minor
Dec 6 '18 at 5:11
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
We have a knowledge base article on match intersection, what you're trying to do here, however your other restriction is that these are the only 3 connected nodes, so we have some additional work to do.
Using the first approach in the article, we just have to add an additional predicate to ensure the degree of :TRADES relationships equals the size of the collection:
WITH ['Apple', 'Orange', 'Grapes'] as names
MATCH (g:good)<-[:TRADES]-(n:Name)
WHERE g.good in names AND size((n)-[:TRADES]->()) = size(names)
WITH n, size(names) as inputCnt, count(DISTINCT g) as cnt
WHERE cnt = inputCnt
RETURN n
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
Hi @InverseFalcon I would like to know if I have another query with more than 5 fruits. What I need to need change is from three elements to five elements on WITH ['Apple', 'Orange', 'Grapes'] as names ?
– Platalea Minor
Dec 5 '18 at 8:17
The type of query provided doesn't use any hard-coded numbers for expected values, if you read through it you should notice it uses the number of elements in your input, so whether it's 3 or 5 or 5000 it should work the same.
– InverseFalcon
Dec 5 '18 at 9:28
However, if I want to query if any name node which have connected with three or more fruit nodes. I think this query won't be able to provide the name nodes?
– Platalea Minor
Dec 5 '18 at 9:40
Then just change up the last WHERE clause with the numbers you want:WHERE cnt >= 3
– InverseFalcon
Dec 5 '18 at 19:45
Hi @InverseFalcon Thank you for your help, yet it cannot resolve the question. I have raised another question below. If you have time please take a look. Thank you so much stackoverflow.com/questions/53629951/find-cluster-in-neo4j
– Platalea Minor
Dec 6 '18 at 5:11
add a comment |
We have a knowledge base article on match intersection, what you're trying to do here, however your other restriction is that these are the only 3 connected nodes, so we have some additional work to do.
Using the first approach in the article, we just have to add an additional predicate to ensure the degree of :TRADES relationships equals the size of the collection:
WITH ['Apple', 'Orange', 'Grapes'] as names
MATCH (g:good)<-[:TRADES]-(n:Name)
WHERE g.good in names AND size((n)-[:TRADES]->()) = size(names)
WITH n, size(names) as inputCnt, count(DISTINCT g) as cnt
WHERE cnt = inputCnt
RETURN n
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
Hi @InverseFalcon I would like to know if I have another query with more than 5 fruits. What I need to need change is from three elements to five elements on WITH ['Apple', 'Orange', 'Grapes'] as names ?
– Platalea Minor
Dec 5 '18 at 8:17
The type of query provided doesn't use any hard-coded numbers for expected values, if you read through it you should notice it uses the number of elements in your input, so whether it's 3 or 5 or 5000 it should work the same.
– InverseFalcon
Dec 5 '18 at 9:28
However, if I want to query if any name node which have connected with three or more fruit nodes. I think this query won't be able to provide the name nodes?
– Platalea Minor
Dec 5 '18 at 9:40
Then just change up the last WHERE clause with the numbers you want:WHERE cnt >= 3
– InverseFalcon
Dec 5 '18 at 19:45
Hi @InverseFalcon Thank you for your help, yet it cannot resolve the question. I have raised another question below. If you have time please take a look. Thank you so much stackoverflow.com/questions/53629951/find-cluster-in-neo4j
– Platalea Minor
Dec 6 '18 at 5:11
add a comment |
We have a knowledge base article on match intersection, what you're trying to do here, however your other restriction is that these are the only 3 connected nodes, so we have some additional work to do.
Using the first approach in the article, we just have to add an additional predicate to ensure the degree of :TRADES relationships equals the size of the collection:
WITH ['Apple', 'Orange', 'Grapes'] as names
MATCH (g:good)<-[:TRADES]-(n:Name)
WHERE g.good in names AND size((n)-[:TRADES]->()) = size(names)
WITH n, size(names) as inputCnt, count(DISTINCT g) as cnt
WHERE cnt = inputCnt
RETURN n
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
We have a knowledge base article on match intersection, what you're trying to do here, however your other restriction is that these are the only 3 connected nodes, so we have some additional work to do.
Using the first approach in the article, we just have to add an additional predicate to ensure the degree of :TRADES relationships equals the size of the collection:
WITH ['Apple', 'Orange', 'Grapes'] as names
MATCH (g:good)<-[:TRADES]-(n:Name)
WHERE g.good in names AND size((n)-[:TRADES]->()) = size(names)
WITH n, size(names) as inputCnt, count(DISTINCT g) as cnt
WHERE cnt = inputCnt
RETURN n
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
answered Nov 22 '18 at 4:38
InverseFalconInverseFalcon
19.9k31831
19.9k31831
Hi @InverseFalcon I would like to know if I have another query with more than 5 fruits. What I need to need change is from three elements to five elements on WITH ['Apple', 'Orange', 'Grapes'] as names ?
– Platalea Minor
Dec 5 '18 at 8:17
The type of query provided doesn't use any hard-coded numbers for expected values, if you read through it you should notice it uses the number of elements in your input, so whether it's 3 or 5 or 5000 it should work the same.
– InverseFalcon
Dec 5 '18 at 9:28
However, if I want to query if any name node which have connected with three or more fruit nodes. I think this query won't be able to provide the name nodes?
– Platalea Minor
Dec 5 '18 at 9:40
Then just change up the last WHERE clause with the numbers you want:WHERE cnt >= 3
– InverseFalcon
Dec 5 '18 at 19:45
Hi @InverseFalcon Thank you for your help, yet it cannot resolve the question. I have raised another question below. If you have time please take a look. Thank you so much stackoverflow.com/questions/53629951/find-cluster-in-neo4j
– Platalea Minor
Dec 6 '18 at 5:11
add a comment |
Hi @InverseFalcon I would like to know if I have another query with more than 5 fruits. What I need to need change is from three elements to five elements on WITH ['Apple', 'Orange', 'Grapes'] as names ?
– Platalea Minor
Dec 5 '18 at 8:17
The type of query provided doesn't use any hard-coded numbers for expected values, if you read through it you should notice it uses the number of elements in your input, so whether it's 3 or 5 or 5000 it should work the same.
– InverseFalcon
Dec 5 '18 at 9:28
However, if I want to query if any name node which have connected with three or more fruit nodes. I think this query won't be able to provide the name nodes?
– Platalea Minor
Dec 5 '18 at 9:40
Then just change up the last WHERE clause with the numbers you want:WHERE cnt >= 3
– InverseFalcon
Dec 5 '18 at 19:45
Hi @InverseFalcon Thank you for your help, yet it cannot resolve the question. I have raised another question below. If you have time please take a look. Thank you so much stackoverflow.com/questions/53629951/find-cluster-in-neo4j
– Platalea Minor
Dec 6 '18 at 5:11
Hi @InverseFalcon I would like to know if I have another query with more than 5 fruits. What I need to need change is from three elements to five elements on WITH ['Apple', 'Orange', 'Grapes'] as names ?
– Platalea Minor
Dec 5 '18 at 8:17
Hi @InverseFalcon I would like to know if I have another query with more than 5 fruits. What I need to need change is from three elements to five elements on WITH ['Apple', 'Orange', 'Grapes'] as names ?
– Platalea Minor
Dec 5 '18 at 8:17
The type of query provided doesn't use any hard-coded numbers for expected values, if you read through it you should notice it uses the number of elements in your input, so whether it's 3 or 5 or 5000 it should work the same.
– InverseFalcon
Dec 5 '18 at 9:28
The type of query provided doesn't use any hard-coded numbers for expected values, if you read through it you should notice it uses the number of elements in your input, so whether it's 3 or 5 or 5000 it should work the same.
– InverseFalcon
Dec 5 '18 at 9:28
However, if I want to query if any name node which have connected with three or more fruit nodes. I think this query won't be able to provide the name nodes?
– Platalea Minor
Dec 5 '18 at 9:40
However, if I want to query if any name node which have connected with three or more fruit nodes. I think this query won't be able to provide the name nodes?
– Platalea Minor
Dec 5 '18 at 9:40
Then just change up the last WHERE clause with the numbers you want:
WHERE cnt >= 3– InverseFalcon
Dec 5 '18 at 19:45
Then just change up the last WHERE clause with the numbers you want:
WHERE cnt >= 3– InverseFalcon
Dec 5 '18 at 19:45
Hi @InverseFalcon Thank you for your help, yet it cannot resolve the question. I have raised another question below. If you have time please take a look. Thank you so much stackoverflow.com/questions/53629951/find-cluster-in-neo4j
– Platalea Minor
Dec 6 '18 at 5:11
Hi @InverseFalcon Thank you for your help, yet it cannot resolve the question. I have raised another question below. If you have time please take a look. Thank you so much stackoverflow.com/questions/53629951/find-cluster-in-neo4j
– Platalea Minor
Dec 6 '18 at 5:11
add a comment |
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