Ruby using count to tally instances of a word instead of its component letters












1















I'm trying to tally up the number of wins a team has, but my code has it counting the instances of each individual letter in the team's name.



wins = 0  

puts "Please enter a team name to check"

teamname = gets.chomp.to_s

tencentbeernight = IO.readlines("winners.txt").to_s

wins = tencentbeernight.count(teamname)

printf "The %2s have won %2i times" % [teamname, wins]


How do I get it to count the name of the team?










share|improve this question

























  • Unrelated, but canonical Ruby code uses _ to separate words in variable names, e.g., team_name or ten_cent_beer_night. Please either use that (preferred) or something to avoid word smashes.

    – Dave Newton
    Nov 21 '18 at 19:01











  • gets and chomp returns strings, so to_s is redundant.

    – Cary Swoveland
    Nov 21 '18 at 19:55


















1















I'm trying to tally up the number of wins a team has, but my code has it counting the instances of each individual letter in the team's name.



wins = 0  

puts "Please enter a team name to check"

teamname = gets.chomp.to_s

tencentbeernight = IO.readlines("winners.txt").to_s

wins = tencentbeernight.count(teamname)

printf "The %2s have won %2i times" % [teamname, wins]


How do I get it to count the name of the team?










share|improve this question

























  • Unrelated, but canonical Ruby code uses _ to separate words in variable names, e.g., team_name or ten_cent_beer_night. Please either use that (preferred) or something to avoid word smashes.

    – Dave Newton
    Nov 21 '18 at 19:01











  • gets and chomp returns strings, so to_s is redundant.

    – Cary Swoveland
    Nov 21 '18 at 19:55
















1












1








1








I'm trying to tally up the number of wins a team has, but my code has it counting the instances of each individual letter in the team's name.



wins = 0  

puts "Please enter a team name to check"

teamname = gets.chomp.to_s

tencentbeernight = IO.readlines("winners.txt").to_s

wins = tencentbeernight.count(teamname)

printf "The %2s have won %2i times" % [teamname, wins]


How do I get it to count the name of the team?










share|improve this question
















I'm trying to tally up the number of wins a team has, but my code has it counting the instances of each individual letter in the team's name.



wins = 0  

puts "Please enter a team name to check"

teamname = gets.chomp.to_s

tencentbeernight = IO.readlines("winners.txt").to_s

wins = tencentbeernight.count(teamname)

printf "The %2s have won %2i times" % [teamname, wins]


How do I get it to count the name of the team?







ruby






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 19:00









Wayne Phipps

1,15342130




1,15342130










asked Nov 21 '18 at 18:23









ValleyantValleyant

154




154













  • Unrelated, but canonical Ruby code uses _ to separate words in variable names, e.g., team_name or ten_cent_beer_night. Please either use that (preferred) or something to avoid word smashes.

    – Dave Newton
    Nov 21 '18 at 19:01











  • gets and chomp returns strings, so to_s is redundant.

    – Cary Swoveland
    Nov 21 '18 at 19:55





















  • Unrelated, but canonical Ruby code uses _ to separate words in variable names, e.g., team_name or ten_cent_beer_night. Please either use that (preferred) or something to avoid word smashes.

    – Dave Newton
    Nov 21 '18 at 19:01











  • gets and chomp returns strings, so to_s is redundant.

    – Cary Swoveland
    Nov 21 '18 at 19:55



















Unrelated, but canonical Ruby code uses _ to separate words in variable names, e.g., team_name or ten_cent_beer_night. Please either use that (preferred) or something to avoid word smashes.

– Dave Newton
Nov 21 '18 at 19:01





Unrelated, but canonical Ruby code uses _ to separate words in variable names, e.g., team_name or ten_cent_beer_night. Please either use that (preferred) or something to avoid word smashes.

– Dave Newton
Nov 21 '18 at 19:01













gets and chomp returns strings, so to_s is redundant.

– Cary Swoveland
Nov 21 '18 at 19:55







gets and chomp returns strings, so to_s is redundant.

– Cary Swoveland
Nov 21 '18 at 19:55














2 Answers
2






active

oldest

votes


















1














count counts the number of individual characters, not the instances of the string.



Try:



wins = tencentbeernight.scan(teamname).length


This will use teamname as a regular expression and count the number of times it appears.






share|improve this answer


























  • IO.readLines returns an array so I believe count would return the number of elements?

    – Wayne Phipps
    Nov 21 '18 at 19:01






  • 1





    @WaynePhipps - He calls ".to_s" on it so it comes back as a string representation of the Array.

    – Trinculo
    Nov 21 '18 at 19:05











  • well spotted, my bad

    – Wayne Phipps
    Nov 21 '18 at 19:07








  • 1





    Thanks a ton, that did it.

    – Valleyant
    Nov 21 '18 at 19:37



















0














Converting the array returned by IO::readlines to a string and then counting the number of times a string appears in that string can be made to work but it is not an approach that any experienced Rubiest would take.



First, let's create a file "winners.txt".



arr = ["Raiders", "Bears", "bearskin rug", "Chargers", "my bugbears", "bears"]
str = arr.join("n")
#=> "RaidersnBearsnbearskin rugnChargersnmy bugbearsnbears"
filename = "winners.txt"
File.write(filename, str)
#=> 53 (characters written)


and get the name of the team:



team = gets.chomp
#=> "bears"


See IO#write.1



The approach advocated in the question and provided in another answer is as follows:



array = IO.readlines(filename)
#> ["Raidersn", "Bearsn", "bearskin rugn", "Chargersn", "my bugbearsn", "bears"]
str = array.to_s
#=> "["Raiders\n", "Bears\n", "bearskin rug\n", "Chargers\n", "my bugbears\n", "bears"]"
a = str.scan(team)
#=> ["bears", "bears", "bears"]
a.size
#=> 3


which is incorrect. We could get around those problems, but the more conventional approach is the following:



team = gets.downcase.chomp
#=> "bears"

a = File.readlines(filename)
#=> ["raidersn", "bearsn", "bearskin rugn", "chargersn", "my bugbearsn", "bears"]
a.count { |s| s.downcase.match?(/b#{team}b/) }
#=> 2


which gives the correct answer, as a[1] and a[-1] (and only those elements) are matched. The regular expression reads, "match a word break (b) following by the value of team followed by another word break".



We can improve on this however. There is no need to create the temporary array, a. Instead we use IO::foreach, which reads the file line-by-line and, when used without a block, returns an enumerator:



enum = File.foreach(filename)
#=> #<Enumerator: File:foreach("winners.txt")>


We can see the values that will be generated by enum by converting it to an array:



enum.to_a
#=> ["raidersn", "n", "bearsn", "n", "bearskin rugn", "n", "chargersn",
# "n", "my bugbearsn", "n", "bearsn"]


Continuing,



enum.count { |s| s.downcase.match?(/b#{team}b/) }
#=> 2


One would normally chain the two methods:



File.foreach(filename).count { |s| s.downcase.match?(/b#{team}b/) }
#= 2


1 I've used File as the receiver for some methods that are defined in the class IO. That's commonly done and works because File.superclass #=> IO.






share|improve this answer
























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418354%2fruby-using-count-to-tally-instances-of-a-word-instead-of-its-component-letters%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    count counts the number of individual characters, not the instances of the string.



    Try:



    wins = tencentbeernight.scan(teamname).length


    This will use teamname as a regular expression and count the number of times it appears.






    share|improve this answer


























    • IO.readLines returns an array so I believe count would return the number of elements?

      – Wayne Phipps
      Nov 21 '18 at 19:01






    • 1





      @WaynePhipps - He calls ".to_s" on it so it comes back as a string representation of the Array.

      – Trinculo
      Nov 21 '18 at 19:05











    • well spotted, my bad

      – Wayne Phipps
      Nov 21 '18 at 19:07








    • 1





      Thanks a ton, that did it.

      – Valleyant
      Nov 21 '18 at 19:37
















    1














    count counts the number of individual characters, not the instances of the string.



    Try:



    wins = tencentbeernight.scan(teamname).length


    This will use teamname as a regular expression and count the number of times it appears.






    share|improve this answer


























    • IO.readLines returns an array so I believe count would return the number of elements?

      – Wayne Phipps
      Nov 21 '18 at 19:01






    • 1





      @WaynePhipps - He calls ".to_s" on it so it comes back as a string representation of the Array.

      – Trinculo
      Nov 21 '18 at 19:05











    • well spotted, my bad

      – Wayne Phipps
      Nov 21 '18 at 19:07








    • 1





      Thanks a ton, that did it.

      – Valleyant
      Nov 21 '18 at 19:37














    1












    1








    1







    count counts the number of individual characters, not the instances of the string.



    Try:



    wins = tencentbeernight.scan(teamname).length


    This will use teamname as a regular expression and count the number of times it appears.






    share|improve this answer















    count counts the number of individual characters, not the instances of the string.



    Try:



    wins = tencentbeernight.scan(teamname).length


    This will use teamname as a regular expression and count the number of times it appears.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 21 '18 at 19:00









    Dave Newton

    141k19215258




    141k19215258










    answered Nov 21 '18 at 18:58









    TrinculoTrinculo

    7651519




    7651519













    • IO.readLines returns an array so I believe count would return the number of elements?

      – Wayne Phipps
      Nov 21 '18 at 19:01






    • 1





      @WaynePhipps - He calls ".to_s" on it so it comes back as a string representation of the Array.

      – Trinculo
      Nov 21 '18 at 19:05











    • well spotted, my bad

      – Wayne Phipps
      Nov 21 '18 at 19:07








    • 1





      Thanks a ton, that did it.

      – Valleyant
      Nov 21 '18 at 19:37



















    • IO.readLines returns an array so I believe count would return the number of elements?

      – Wayne Phipps
      Nov 21 '18 at 19:01






    • 1





      @WaynePhipps - He calls ".to_s" on it so it comes back as a string representation of the Array.

      – Trinculo
      Nov 21 '18 at 19:05











    • well spotted, my bad

      – Wayne Phipps
      Nov 21 '18 at 19:07








    • 1





      Thanks a ton, that did it.

      – Valleyant
      Nov 21 '18 at 19:37

















    IO.readLines returns an array so I believe count would return the number of elements?

    – Wayne Phipps
    Nov 21 '18 at 19:01





    IO.readLines returns an array so I believe count would return the number of elements?

    – Wayne Phipps
    Nov 21 '18 at 19:01




    1




    1





    @WaynePhipps - He calls ".to_s" on it so it comes back as a string representation of the Array.

    – Trinculo
    Nov 21 '18 at 19:05





    @WaynePhipps - He calls ".to_s" on it so it comes back as a string representation of the Array.

    – Trinculo
    Nov 21 '18 at 19:05













    well spotted, my bad

    – Wayne Phipps
    Nov 21 '18 at 19:07







    well spotted, my bad

    – Wayne Phipps
    Nov 21 '18 at 19:07






    1




    1





    Thanks a ton, that did it.

    – Valleyant
    Nov 21 '18 at 19:37





    Thanks a ton, that did it.

    – Valleyant
    Nov 21 '18 at 19:37













    0














    Converting the array returned by IO::readlines to a string and then counting the number of times a string appears in that string can be made to work but it is not an approach that any experienced Rubiest would take.



    First, let's create a file "winners.txt".



    arr = ["Raiders", "Bears", "bearskin rug", "Chargers", "my bugbears", "bears"]
    str = arr.join("n")
    #=> "RaidersnBearsnbearskin rugnChargersnmy bugbearsnbears"
    filename = "winners.txt"
    File.write(filename, str)
    #=> 53 (characters written)


    and get the name of the team:



    team = gets.chomp
    #=> "bears"


    See IO#write.1



    The approach advocated in the question and provided in another answer is as follows:



    array = IO.readlines(filename)
    #> ["Raidersn", "Bearsn", "bearskin rugn", "Chargersn", "my bugbearsn", "bears"]
    str = array.to_s
    #=> "["Raiders\n", "Bears\n", "bearskin rug\n", "Chargers\n", "my bugbears\n", "bears"]"
    a = str.scan(team)
    #=> ["bears", "bears", "bears"]
    a.size
    #=> 3


    which is incorrect. We could get around those problems, but the more conventional approach is the following:



    team = gets.downcase.chomp
    #=> "bears"

    a = File.readlines(filename)
    #=> ["raidersn", "bearsn", "bearskin rugn", "chargersn", "my bugbearsn", "bears"]
    a.count { |s| s.downcase.match?(/b#{team}b/) }
    #=> 2


    which gives the correct answer, as a[1] and a[-1] (and only those elements) are matched. The regular expression reads, "match a word break (b) following by the value of team followed by another word break".



    We can improve on this however. There is no need to create the temporary array, a. Instead we use IO::foreach, which reads the file line-by-line and, when used without a block, returns an enumerator:



    enum = File.foreach(filename)
    #=> #<Enumerator: File:foreach("winners.txt")>


    We can see the values that will be generated by enum by converting it to an array:



    enum.to_a
    #=> ["raidersn", "n", "bearsn", "n", "bearskin rugn", "n", "chargersn",
    # "n", "my bugbearsn", "n", "bearsn"]


    Continuing,



    enum.count { |s| s.downcase.match?(/b#{team}b/) }
    #=> 2


    One would normally chain the two methods:



    File.foreach(filename).count { |s| s.downcase.match?(/b#{team}b/) }
    #= 2


    1 I've used File as the receiver for some methods that are defined in the class IO. That's commonly done and works because File.superclass #=> IO.






    share|improve this answer




























      0














      Converting the array returned by IO::readlines to a string and then counting the number of times a string appears in that string can be made to work but it is not an approach that any experienced Rubiest would take.



      First, let's create a file "winners.txt".



      arr = ["Raiders", "Bears", "bearskin rug", "Chargers", "my bugbears", "bears"]
      str = arr.join("n")
      #=> "RaidersnBearsnbearskin rugnChargersnmy bugbearsnbears"
      filename = "winners.txt"
      File.write(filename, str)
      #=> 53 (characters written)


      and get the name of the team:



      team = gets.chomp
      #=> "bears"


      See IO#write.1



      The approach advocated in the question and provided in another answer is as follows:



      array = IO.readlines(filename)
      #> ["Raidersn", "Bearsn", "bearskin rugn", "Chargersn", "my bugbearsn", "bears"]
      str = array.to_s
      #=> "["Raiders\n", "Bears\n", "bearskin rug\n", "Chargers\n", "my bugbears\n", "bears"]"
      a = str.scan(team)
      #=> ["bears", "bears", "bears"]
      a.size
      #=> 3


      which is incorrect. We could get around those problems, but the more conventional approach is the following:



      team = gets.downcase.chomp
      #=> "bears"

      a = File.readlines(filename)
      #=> ["raidersn", "bearsn", "bearskin rugn", "chargersn", "my bugbearsn", "bears"]
      a.count { |s| s.downcase.match?(/b#{team}b/) }
      #=> 2


      which gives the correct answer, as a[1] and a[-1] (and only those elements) are matched. The regular expression reads, "match a word break (b) following by the value of team followed by another word break".



      We can improve on this however. There is no need to create the temporary array, a. Instead we use IO::foreach, which reads the file line-by-line and, when used without a block, returns an enumerator:



      enum = File.foreach(filename)
      #=> #<Enumerator: File:foreach("winners.txt")>


      We can see the values that will be generated by enum by converting it to an array:



      enum.to_a
      #=> ["raidersn", "n", "bearsn", "n", "bearskin rugn", "n", "chargersn",
      # "n", "my bugbearsn", "n", "bearsn"]


      Continuing,



      enum.count { |s| s.downcase.match?(/b#{team}b/) }
      #=> 2


      One would normally chain the two methods:



      File.foreach(filename).count { |s| s.downcase.match?(/b#{team}b/) }
      #= 2


      1 I've used File as the receiver for some methods that are defined in the class IO. That's commonly done and works because File.superclass #=> IO.






      share|improve this answer


























        0












        0








        0







        Converting the array returned by IO::readlines to a string and then counting the number of times a string appears in that string can be made to work but it is not an approach that any experienced Rubiest would take.



        First, let's create a file "winners.txt".



        arr = ["Raiders", "Bears", "bearskin rug", "Chargers", "my bugbears", "bears"]
        str = arr.join("n")
        #=> "RaidersnBearsnbearskin rugnChargersnmy bugbearsnbears"
        filename = "winners.txt"
        File.write(filename, str)
        #=> 53 (characters written)


        and get the name of the team:



        team = gets.chomp
        #=> "bears"


        See IO#write.1



        The approach advocated in the question and provided in another answer is as follows:



        array = IO.readlines(filename)
        #> ["Raidersn", "Bearsn", "bearskin rugn", "Chargersn", "my bugbearsn", "bears"]
        str = array.to_s
        #=> "["Raiders\n", "Bears\n", "bearskin rug\n", "Chargers\n", "my bugbears\n", "bears"]"
        a = str.scan(team)
        #=> ["bears", "bears", "bears"]
        a.size
        #=> 3


        which is incorrect. We could get around those problems, but the more conventional approach is the following:



        team = gets.downcase.chomp
        #=> "bears"

        a = File.readlines(filename)
        #=> ["raidersn", "bearsn", "bearskin rugn", "chargersn", "my bugbearsn", "bears"]
        a.count { |s| s.downcase.match?(/b#{team}b/) }
        #=> 2


        which gives the correct answer, as a[1] and a[-1] (and only those elements) are matched. The regular expression reads, "match a word break (b) following by the value of team followed by another word break".



        We can improve on this however. There is no need to create the temporary array, a. Instead we use IO::foreach, which reads the file line-by-line and, when used without a block, returns an enumerator:



        enum = File.foreach(filename)
        #=> #<Enumerator: File:foreach("winners.txt")>


        We can see the values that will be generated by enum by converting it to an array:



        enum.to_a
        #=> ["raidersn", "n", "bearsn", "n", "bearskin rugn", "n", "chargersn",
        # "n", "my bugbearsn", "n", "bearsn"]


        Continuing,



        enum.count { |s| s.downcase.match?(/b#{team}b/) }
        #=> 2


        One would normally chain the two methods:



        File.foreach(filename).count { |s| s.downcase.match?(/b#{team}b/) }
        #= 2


        1 I've used File as the receiver for some methods that are defined in the class IO. That's commonly done and works because File.superclass #=> IO.






        share|improve this answer













        Converting the array returned by IO::readlines to a string and then counting the number of times a string appears in that string can be made to work but it is not an approach that any experienced Rubiest would take.



        First, let's create a file "winners.txt".



        arr = ["Raiders", "Bears", "bearskin rug", "Chargers", "my bugbears", "bears"]
        str = arr.join("n")
        #=> "RaidersnBearsnbearskin rugnChargersnmy bugbearsnbears"
        filename = "winners.txt"
        File.write(filename, str)
        #=> 53 (characters written)


        and get the name of the team:



        team = gets.chomp
        #=> "bears"


        See IO#write.1



        The approach advocated in the question and provided in another answer is as follows:



        array = IO.readlines(filename)
        #> ["Raidersn", "Bearsn", "bearskin rugn", "Chargersn", "my bugbearsn", "bears"]
        str = array.to_s
        #=> "["Raiders\n", "Bears\n", "bearskin rug\n", "Chargers\n", "my bugbears\n", "bears"]"
        a = str.scan(team)
        #=> ["bears", "bears", "bears"]
        a.size
        #=> 3


        which is incorrect. We could get around those problems, but the more conventional approach is the following:



        team = gets.downcase.chomp
        #=> "bears"

        a = File.readlines(filename)
        #=> ["raidersn", "bearsn", "bearskin rugn", "chargersn", "my bugbearsn", "bears"]
        a.count { |s| s.downcase.match?(/b#{team}b/) }
        #=> 2


        which gives the correct answer, as a[1] and a[-1] (and only those elements) are matched. The regular expression reads, "match a word break (b) following by the value of team followed by another word break".



        We can improve on this however. There is no need to create the temporary array, a. Instead we use IO::foreach, which reads the file line-by-line and, when used without a block, returns an enumerator:



        enum = File.foreach(filename)
        #=> #<Enumerator: File:foreach("winners.txt")>


        We can see the values that will be generated by enum by converting it to an array:



        enum.to_a
        #=> ["raidersn", "n", "bearsn", "n", "bearskin rugn", "n", "chargersn",
        # "n", "my bugbearsn", "n", "bearsn"]


        Continuing,



        enum.count { |s| s.downcase.match?(/b#{team}b/) }
        #=> 2


        One would normally chain the two methods:



        File.foreach(filename).count { |s| s.downcase.match?(/b#{team}b/) }
        #= 2


        1 I've used File as the receiver for some methods that are defined in the class IO. That's commonly done and works because File.superclass #=> IO.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 22:01









        Cary SwovelandCary Swoveland

        70.9k54167




        70.9k54167






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418354%2fruby-using-count-to-tally-instances-of-a-word-instead-of-its-component-letters%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            鏡平學校

            ꓛꓣだゔៀៅຸ໢ທຮ໕໒ ,ໂ'໥໓າ໼ឨឲ៵៭ៈゎゔit''䖳𥁄卿' ☨₤₨こゎもょの;ꜹꟚꞖꞵꟅꞛေၦေɯ,ɨɡ𛃵𛁹ޝ޳ޠ޾,ޤޒޯ޾𫝒𫠁သ𛅤チョ'サノބޘދ𛁐ᶿᶇᶀᶋᶠ㨑㽹⻮ꧬ꧹؍۩وَؠ㇕㇃㇪ ㇦㇋㇋ṜẰᵡᴠ 軌ᵕ搜۳ٰޗޮ޷ސޯ𫖾𫅀ल, ꙭ꙰ꚅꙁꚊꞻꝔ꟠Ꝭㄤﺟޱސꧨꧼ꧴ꧯꧽ꧲ꧯ'⽹⽭⾁⿞⼳⽋២៩ញណើꩯꩤ꩸ꩮᶻᶺᶧᶂ𫳲𫪭𬸄𫵰𬖩𬫣𬊉ၲ𛅬㕦䬺𫝌𫝼,,𫟖𫞽ហៅ஫㆔ాఆఅꙒꚞꙍ,Ꙟ꙱エ ,ポテ,フࢰࢯ𫟠𫞶 𫝤𫟠ﺕﹱﻜﻣ𪵕𪭸𪻆𪾩𫔷ġ,ŧآꞪ꟥,ꞔꝻ♚☹⛵𛀌ꬷꭞȄƁƪƬșƦǙǗdžƝǯǧⱦⱰꓕꓢႋ神 ဴ၀க௭எ௫ឫោ ' េㇷㇴㇼ神ㇸㇲㇽㇴㇼㇻㇸ'ㇸㇿㇸㇹㇰㆣꓚꓤ₡₧ ㄨㄟ㄂ㄖㄎ໗ツڒذ₶।ऩछएोञयूटक़कयँृी,冬'𛅢𛅥ㇱㇵㇶ𥄥𦒽𠣧𠊓𧢖𥞘𩔋цѰㄠſtʯʭɿʆʗʍʩɷɛ,əʏダヵㄐㄘR{gỚṖḺờṠṫảḙḭᴮᵏᴘᵀᵷᵕᴜᴏᵾq﮲ﲿﴽﭙ軌ﰬﶚﶧ﫲Ҝжюїкӈㇴffצּ﬘﭅﬈軌'ffistfflſtffतभफɳɰʊɲʎ𛁱𛁖𛁮𛀉 𛂯𛀞నఋŀŲ 𫟲𫠖𫞺ຆຆ ໹້໕໗ๆทԊꧢꧠ꧰ꓱ⿝⼑ŎḬẃẖỐẅ ,ờỰỈỗﮊDžȩꭏꭎꬻ꭮ꬿꭖꭥꭅ㇭神 ⾈ꓵꓑ⺄㄄ㄪㄙㄅㄇstA۵䞽ॶ𫞑𫝄㇉㇇゜軌𩜛𩳠Jﻺ‚Üမ႕ႌႊၐၸဓၞၞၡ៸wyvtᶎᶪᶹစဎ꣡꣰꣢꣤ٗ؋لㇳㇾㇻㇱ㆐㆔,,㆟Ⱶヤマފ޼ޝަݿݞݠݷݐ',ݘ,ݪݙݵ𬝉𬜁𫝨𫞘くせぉて¼óû×ó£…𛅑הㄙくԗԀ5606神45,神796'𪤻𫞧ꓐ㄁ㄘɥɺꓵꓲ3''7034׉ⱦⱠˆ“𫝋ȍ,ꩲ軌꩷ꩶꩧꩫఞ۔فڱێظペサ神ナᴦᵑ47 9238їﻂ䐊䔉㠸﬎ffiﬣ,לּᴷᴦᵛᵽ,ᴨᵤ ᵸᵥᴗᵈꚏꚉꚟ⻆rtǟƴ𬎎

            Why https connections are so slow when debugging (stepping over) in Java?