Angular Reactive Forms pattern validation: Invalid regular expression
I have a regex for Australia phone number validation working in an AngularJS website. I have set the exact pattern in the Reactive Forms validator as follows:
Validators.pattern(
'/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/'
)
The page doesn't load as it gets the following error:
Invalid regular expression: /^/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat
What is the correct way to specify this pattern when using Reactive Forms?
regex angular validation
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
add a comment |
I have a regex for Australia phone number validation working in an AngularJS website. I have set the exact pattern in the Reactive Forms validator as follows:
Validators.pattern(
'/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/'
)
The page doesn't load as it gets the following error:
Invalid regular expression: /^/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat
What is the correct way to specify this pattern when using Reactive Forms?
regex angular validation
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
1
^({0,1}...: the{0,1}quantifier repeats nothing. You should read a regex tutorial, in particular about quantifiers and character classes (to avoid useless alternations).
– Casimir et Hippolyte
Jan 29 '18 at 4:04
add a comment |
I have a regex for Australia phone number validation working in an AngularJS website. I have set the exact pattern in the Reactive Forms validator as follows:
Validators.pattern(
'/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/'
)
The page doesn't load as it gets the following error:
Invalid regular expression: /^/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat
What is the correct way to specify this pattern when using Reactive Forms?
regex angular validation
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
I have a regex for Australia phone number validation working in an AngularJS website. I have set the exact pattern in the Reactive Forms validator as follows:
Validators.pattern(
'/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/'
)
The page doesn't load as it gets the following error:
Invalid regular expression: /^/^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat
What is the correct way to specify this pattern when using Reactive Forms?
regex angular validation
regex angular validation
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
asked Jan 29 '18 at 3:32
AnthonyAnthony
1,16311638
1,16311638
1
^({0,1}...: the{0,1}quantifier repeats nothing. You should read a regex tutorial, in particular about quantifiers and character classes (to avoid useless alternations).
– Casimir et Hippolyte
Jan 29 '18 at 4:04
add a comment |
1
^({0,1}...: the{0,1}quantifier repeats nothing. You should read a regex tutorial, in particular about quantifiers and character classes (to avoid useless alternations).
– Casimir et Hippolyte
Jan 29 '18 at 4:04
1
1
^({0,1}...: the {0,1} quantifier repeats nothing. You should read a regex tutorial, in particular about quantifiers and character classes (to avoid useless alternations).– Casimir et Hippolyte
Jan 29 '18 at 4:04
^({0,1}...: the {0,1} quantifier repeats nothing. You should read a regex tutorial, in particular about quantifiers and character classes (to avoid useless alternations).– Casimir et Hippolyte
Jan 29 '18 at 4:04
add a comment |
2 Answers
2
active
oldest
votes
There are multiple issues:
- The regex literal should not be used inside quotes (or use a string pattern with double escaped special chars)
- Special chars like
(,)and+must be escaped - nothing to repeat is caused by the fact that((start of a capturing group) is quantified with{0,1}and that is an error
{0,1}is equal to?,( |-)can be written as[ -],(2|4|3|7|8)canbe written shorter as[23478].
So, you may use
Validators.pattern(
'^\(?(0|\+61)[24378]\)?[ -]?[0-9]{2}[ -]?[0-9]{2}[ -]?[0-9][ -]?[0-9]{3}$'
)
Note that you may even omit ^ and $ here since the anchors will be added by Angular automatically to the string pattern.
NOTE: if the separators should be consistent, capture the first one and then use backreferences to the group value:
Validators.pattern(
'\(?(?:0|\+61)[24378]\)?([ -]?)[0-9]{2}\1[0-9]{2}\1[0-9]\1[0-9]{3}'
)
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
add a comment |
Pass pattern as string, without / which are the delimiters for regex
Validators.pattern('^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/')
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
1
Why do I need a custom validator when there is a built-in pattern validator that should do the job?
– Anthony
Jan 29 '18 at 3:58
@Anthony I updated my answer, can you give it a shot and let me know, I'n curious if that would solve the issue.
– Nadhir Falta
Jan 29 '18 at 4:13
With the updated answer I get - SyntaxError: Invalid regular expression: /^^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat at new RegExp (<anonymous>)
– Anthony
Jan 29 '18 at 5:59
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
There are multiple issues:
- The regex literal should not be used inside quotes (or use a string pattern with double escaped special chars)
- Special chars like
(,)and+must be escaped - nothing to repeat is caused by the fact that((start of a capturing group) is quantified with{0,1}and that is an error
{0,1}is equal to?,( |-)can be written as[ -],(2|4|3|7|8)canbe written shorter as[23478].
So, you may use
Validators.pattern(
'^\(?(0|\+61)[24378]\)?[ -]?[0-9]{2}[ -]?[0-9]{2}[ -]?[0-9][ -]?[0-9]{3}$'
)
Note that you may even omit ^ and $ here since the anchors will be added by Angular automatically to the string pattern.
NOTE: if the separators should be consistent, capture the first one and then use backreferences to the group value:
Validators.pattern(
'\(?(?:0|\+61)[24378]\)?([ -]?)[0-9]{2}\1[0-9]{2}\1[0-9]\1[0-9]{3}'
)
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
add a comment |
There are multiple issues:
- The regex literal should not be used inside quotes (or use a string pattern with double escaped special chars)
- Special chars like
(,)and+must be escaped - nothing to repeat is caused by the fact that((start of a capturing group) is quantified with{0,1}and that is an error
{0,1}is equal to?,( |-)can be written as[ -],(2|4|3|7|8)canbe written shorter as[23478].
So, you may use
Validators.pattern(
'^\(?(0|\+61)[24378]\)?[ -]?[0-9]{2}[ -]?[0-9]{2}[ -]?[0-9][ -]?[0-9]{3}$'
)
Note that you may even omit ^ and $ here since the anchors will be added by Angular automatically to the string pattern.
NOTE: if the separators should be consistent, capture the first one and then use backreferences to the group value:
Validators.pattern(
'\(?(?:0|\+61)[24378]\)?([ -]?)[0-9]{2}\1[0-9]{2}\1[0-9]\1[0-9]{3}'
)
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
add a comment |
There are multiple issues:
- The regex literal should not be used inside quotes (or use a string pattern with double escaped special chars)
- Special chars like
(,)and+must be escaped - nothing to repeat is caused by the fact that((start of a capturing group) is quantified with{0,1}and that is an error
{0,1}is equal to?,( |-)can be written as[ -],(2|4|3|7|8)canbe written shorter as[23478].
So, you may use
Validators.pattern(
'^\(?(0|\+61)[24378]\)?[ -]?[0-9]{2}[ -]?[0-9]{2}[ -]?[0-9][ -]?[0-9]{3}$'
)
Note that you may even omit ^ and $ here since the anchors will be added by Angular automatically to the string pattern.
NOTE: if the separators should be consistent, capture the first one and then use backreferences to the group value:
Validators.pattern(
'\(?(?:0|\+61)[24378]\)?([ -]?)[0-9]{2}\1[0-9]{2}\1[0-9]\1[0-9]{3}'
)
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
There are multiple issues:
- The regex literal should not be used inside quotes (or use a string pattern with double escaped special chars)
- Special chars like
(,)and+must be escaped - nothing to repeat is caused by the fact that((start of a capturing group) is quantified with{0,1}and that is an error
{0,1}is equal to?,( |-)can be written as[ -],(2|4|3|7|8)canbe written shorter as[23478].
So, you may use
Validators.pattern(
'^\(?(0|\+61)[24378]\)?[ -]?[0-9]{2}[ -]?[0-9]{2}[ -]?[0-9][ -]?[0-9]{3}$'
)
Note that you may even omit ^ and $ here since the anchors will be added by Angular automatically to the string pattern.
NOTE: if the separators should be consistent, capture the first one and then use backreferences to the group value:
Validators.pattern(
'\(?(?:0|\+61)[24378]\)?([ -]?)[0-9]{2}\1[0-9]{2}\1[0-9]\1[0-9]{3}'
)
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
answered Jan 29 '18 at 8:58
Wiktor StribiżewWiktor Stribiżew
318k16139221
318k16139221
add a comment |
add a comment |
Pass pattern as string, without / which are the delimiters for regex
Validators.pattern('^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/')
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
1
Why do I need a custom validator when there is a built-in pattern validator that should do the job?
– Anthony
Jan 29 '18 at 3:58
@Anthony I updated my answer, can you give it a shot and let me know, I'n curious if that would solve the issue.
– Nadhir Falta
Jan 29 '18 at 4:13
With the updated answer I get - SyntaxError: Invalid regular expression: /^^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat at new RegExp (<anonymous>)
– Anthony
Jan 29 '18 at 5:59
add a comment |
Pass pattern as string, without / which are the delimiters for regex
Validators.pattern('^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/')
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
1
Why do I need a custom validator when there is a built-in pattern validator that should do the job?
– Anthony
Jan 29 '18 at 3:58
@Anthony I updated my answer, can you give it a shot and let me know, I'n curious if that would solve the issue.
– Nadhir Falta
Jan 29 '18 at 4:13
With the updated answer I get - SyntaxError: Invalid regular expression: /^^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat at new RegExp (<anonymous>)
– Anthony
Jan 29 '18 at 5:59
add a comment |
Pass pattern as string, without / which are the delimiters for regex
Validators.pattern('^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/')
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
Pass pattern as string, without / which are the delimiters for regex
Validators.pattern('^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/')
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
edited Jan 29 '18 at 4:03
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
answered Jan 29 '18 at 3:57
Nadhir FaltaNadhir Falta
982315
982315
1
Why do I need a custom validator when there is a built-in pattern validator that should do the job?
– Anthony
Jan 29 '18 at 3:58
@Anthony I updated my answer, can you give it a shot and let me know, I'n curious if that would solve the issue.
– Nadhir Falta
Jan 29 '18 at 4:13
With the updated answer I get - SyntaxError: Invalid regular expression: /^^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat at new RegExp (<anonymous>)
– Anthony
Jan 29 '18 at 5:59
add a comment |
1
Why do I need a custom validator when there is a built-in pattern validator that should do the job?
– Anthony
Jan 29 '18 at 3:58
@Anthony I updated my answer, can you give it a shot and let me know, I'n curious if that would solve the issue.
– Nadhir Falta
Jan 29 '18 at 4:13
With the updated answer I get - SyntaxError: Invalid regular expression: /^^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat at new RegExp (<anonymous>)
– Anthony
Jan 29 '18 at 5:59
1
1
Why do I need a custom validator when there is a built-in pattern validator that should do the job?
– Anthony
Jan 29 '18 at 3:58
Why do I need a custom validator when there is a built-in pattern validator that should do the job?
– Anthony
Jan 29 '18 at 3:58
@Anthony I updated my answer, can you give it a shot and let me know, I'n curious if that would solve the issue.
– Nadhir Falta
Jan 29 '18 at 4:13
@Anthony I updated my answer, can you give it a shot and let me know, I'n curious if that would solve the issue.
– Nadhir Falta
Jan 29 '18 at 4:13
With the updated answer I get - SyntaxError: Invalid regular expression: /^^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat at new RegExp (<anonymous>)
– Anthony
Jan 29 '18 at 5:59
With the updated answer I get - SyntaxError: Invalid regular expression: /^^({0,1}((0|+61)(2|4|3|7|8))){0,1}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{2}( |-){0,1}[0-9]{1}( |-){0,1}[0-9]{3}$/$/: Nothing to repeat at new RegExp (<anonymous>)
– Anthony
Jan 29 '18 at 5:59
add a comment |
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^({0,1}...: the{0,1}quantifier repeats nothing. You should read a regex tutorial, in particular about quantifiers and character classes (to avoid useless alternations).– Casimir et Hippolyte
Jan 29 '18 at 4:04