Error in match.names(clabs, names(xi)) : names do not match previous names
-1
- I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named
girls_age.
eg :
boys_age <- c(18,15,16,17,19)
girls_age<- c(16,14,18,17,15)
Then Append
rbind()the two vectors to create data.frame such that I have two columns namedgroupandage.The values from boys_age and girls_age should be in the column
age. Thegroupcolumn should have the category values, boys/girls, to identify the source vector.
r rbind
edited Nov 20 '18 at 9:28
Sotos
30k51640
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
add a comment |
-1
- I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named
girls_age.
eg :
boys_age <- c(18,15,16,17,19)
girls_age<- c(16,14,18,17,15)
Then Append
rbind()the two vectors to create data.frame such that I have two columns namedgroupandage.The values from boys_age and girls_age should be in the column
age. Thegroupcolumn should have the category values, boys/girls, to identify the source vector.
r rbind
edited Nov 20 '18 at 9:28
Sotos
30k51640
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
add a comment |
-1
-1
-1
- I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named
girls_age.
eg :
boys_age <- c(18,15,16,17,19)
girls_age<- c(16,14,18,17,15)
Then Append
rbind()the two vectors to create data.frame such that I have two columns namedgroupandage.The values from boys_age and girls_age should be in the column
age. Thegroupcolumn should have the category values, boys/girls, to identify the source vector.
r rbind
edited Nov 20 '18 at 9:28
Sotos
30k51640
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
- I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named
girls_age.
eg :
boys_age <- c(18,15,16,17,19)
girls_age<- c(16,14,18,17,15)
Then Append
rbind()the two vectors to create data.frame such that I have two columns namedgroupandage.The values from boys_age and girls_age should be in the column
age. Thegroupcolumn should have the category values, boys/girls, to identify the source vector.
r rbind
r rbind
edited Nov 20 '18 at 9:28
Sotos
30k51640
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
edited Nov 20 '18 at 9:28
Sotos
30k51640
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
edited Nov 20 '18 at 9:28
Sotos
30k51640
edited Nov 20 '18 at 9:28
Sotos
30k51640
edited Nov 20 '18 at 9:28
Sotos
30k51640
30k51640
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
asked Nov 20 '18 at 9:26
Himanshu GehlotHimanshu Gehlot
13
13
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
2
Its actually the most primal thing to do in R:
data:
df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))
code:
library(data.table)
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]
result:
# age group
# 1: 18 boys
# 2: 15 boys
# 3: 16 boys
# 4: 17 boys
# 5: 19 boys
# 6: 16 girls
# 7: 14 girls
# 8: 18 girls
# 9: 17 girls
#10: 15 girls
You seem to be keen on using ?rbind: (not practical though)
rbind(
cbind.data.frame(age = df1$boys_age, group = "boys"),
cbind.data.frame(age = df1$girls_age, group = "girls")
)
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
- In the
?cbindsection I'm making use of the recycling functionality R provides. Read about it. - Why am I using
cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
add a comment |
3
Here is one option using stack
out <- stack(list(boys = boys_age, girls = girls_age))
out
# values ind
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
Now change names
names(out) <- c("age", "group")
out
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
You could also do the same in one line, thanks to @Sotos
setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
3
Nice 1. You can also do all in 1 line, i.e.setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
– Sotos
Nov 20 '18 at 9:37
Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.
– Himanshu Gehlot
Nov 20 '18 at 9:39
1
That smells like homework...
– Sotos
Nov 20 '18 at 9:41
Not exactly, i am making some practice questions and got stuck with this.
– Himanshu Gehlot
Nov 20 '18 at 9:43
2
@HimanshuGehlot You can't do it directly withrbind()anddata.frame()only. You could do something likesetNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group'))which includes them, but are not explicit
– Sotos
Nov 20 '18 at 10:00
|
show 7 more comments
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
Its actually the most primal thing to do in R:
data:
df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))
code:
library(data.table)
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]
result:
# age group
# 1: 18 boys
# 2: 15 boys
# 3: 16 boys
# 4: 17 boys
# 5: 19 boys
# 6: 16 girls
# 7: 14 girls
# 8: 18 girls
# 9: 17 girls
#10: 15 girls
You seem to be keen on using ?rbind: (not practical though)
rbind(
cbind.data.frame(age = df1$boys_age, group = "boys"),
cbind.data.frame(age = df1$girls_age, group = "girls")
)
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
- In the
?cbindsection I'm making use of the recycling functionality R provides. Read about it. - Why am I using
cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
add a comment |
2
Its actually the most primal thing to do in R:
data:
df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))
code:
library(data.table)
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]
result:
# age group
# 1: 18 boys
# 2: 15 boys
# 3: 16 boys
# 4: 17 boys
# 5: 19 boys
# 6: 16 girls
# 7: 14 girls
# 8: 18 girls
# 9: 17 girls
#10: 15 girls
You seem to be keen on using ?rbind: (not practical though)
rbind(
cbind.data.frame(age = df1$boys_age, group = "boys"),
cbind.data.frame(age = df1$girls_age, group = "girls")
)
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
- In the
?cbindsection I'm making use of the recycling functionality R provides. Read about it. - Why am I using
cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
add a comment |
2
2
2
Its actually the most primal thing to do in R:
data:
df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))
code:
library(data.table)
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]
result:
# age group
# 1: 18 boys
# 2: 15 boys
# 3: 16 boys
# 4: 17 boys
# 5: 19 boys
# 6: 16 girls
# 7: 14 girls
# 8: 18 girls
# 9: 17 girls
#10: 15 girls
You seem to be keen on using ?rbind: (not practical though)
rbind(
cbind.data.frame(age = df1$boys_age, group = "boys"),
cbind.data.frame(age = df1$girls_age, group = "girls")
)
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
- In the
?cbindsection I'm making use of the recycling functionality R provides. Read about it. - Why am I using
cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
Its actually the most primal thing to do in R:
data:
df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))
code:
library(data.table)
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]
result:
# age group
# 1: 18 boys
# 2: 15 boys
# 3: 16 boys
# 4: 17 boys
# 5: 19 boys
# 6: 16 girls
# 7: 14 girls
# 8: 18 girls
# 9: 17 girls
#10: 15 girls
You seem to be keen on using ?rbind: (not practical though)
rbind(
cbind.data.frame(age = df1$boys_age, group = "boys"),
cbind.data.frame(age = df1$girls_age, group = "girls")
)
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
- In the
?cbindsection I'm making use of the recycling functionality R provides. Read about it. - Why am I using
cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
edited Nov 20 '18 at 11:29
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
answered Nov 20 '18 at 9:48
Andre ElricoAndre Elrico
5,72311229
5,72311229
add a comment |
add a comment |
3
Here is one option using stack
out <- stack(list(boys = boys_age, girls = girls_age))
out
# values ind
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
Now change names
names(out) <- c("age", "group")
out
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
You could also do the same in one line, thanks to @Sotos
setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
3
Nice 1. You can also do all in 1 line, i.e.setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
– Sotos
Nov 20 '18 at 9:37
Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.
– Himanshu Gehlot
Nov 20 '18 at 9:39
1
That smells like homework...
– Sotos
Nov 20 '18 at 9:41
Not exactly, i am making some practice questions and got stuck with this.
– Himanshu Gehlot
Nov 20 '18 at 9:43
2
@HimanshuGehlot You can't do it directly withrbind()anddata.frame()only. You could do something likesetNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group'))which includes them, but are not explicit
– Sotos
Nov 20 '18 at 10:00
|
show 7 more comments
3
Here is one option using stack
out <- stack(list(boys = boys_age, girls = girls_age))
out
# values ind
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
Now change names
names(out) <- c("age", "group")
out
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
You could also do the same in one line, thanks to @Sotos
setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
3
Nice 1. You can also do all in 1 line, i.e.setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
– Sotos
Nov 20 '18 at 9:37
Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.
– Himanshu Gehlot
Nov 20 '18 at 9:39
1
That smells like homework...
– Sotos
Nov 20 '18 at 9:41
Not exactly, i am making some practice questions and got stuck with this.
– Himanshu Gehlot
Nov 20 '18 at 9:43
2
@HimanshuGehlot You can't do it directly withrbind()anddata.frame()only. You could do something likesetNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group'))which includes them, but are not explicit
– Sotos
Nov 20 '18 at 10:00
|
show 7 more comments
3
3
3
Here is one option using stack
out <- stack(list(boys = boys_age, girls = girls_age))
out
# values ind
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
Now change names
names(out) <- c("age", "group")
out
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
You could also do the same in one line, thanks to @Sotos
setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
Here is one option using stack
out <- stack(list(boys = boys_age, girls = girls_age))
out
# values ind
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
Now change names
names(out) <- c("age", "group")
out
# age group
#1 18 boys
#2 15 boys
#3 16 boys
#4 17 boys
#5 19 boys
#6 16 girls
#7 14 girls
#8 18 girls
#9 17 girls
#10 15 girls
You could also do the same in one line, thanks to @Sotos
setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
edited Nov 20 '18 at 9:39
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
answered Nov 20 '18 at 9:33
markusmarkus
13.1k1234
13.1k1234
3
Nice 1. You can also do all in 1 line, i.e.setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
– Sotos
Nov 20 '18 at 9:37
Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.
– Himanshu Gehlot
Nov 20 '18 at 9:39
1
That smells like homework...
– Sotos
Nov 20 '18 at 9:41
Not exactly, i am making some practice questions and got stuck with this.
– Himanshu Gehlot
Nov 20 '18 at 9:43
2
@HimanshuGehlot You can't do it directly withrbind()anddata.frame()only. You could do something likesetNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group'))which includes them, but are not explicit
– Sotos
Nov 20 '18 at 10:00
|
show 7 more comments
3
Nice 1. You can also do all in 1 line, i.e.setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))
– Sotos
Nov 20 '18 at 9:37
Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.
– Himanshu Gehlot
Nov 20 '18 at 9:39
1
That smells like homework...
– Sotos
Nov 20 '18 at 9:41
Not exactly, i am making some practice questions and got stuck with this.
– Himanshu Gehlot
Nov 20 '18 at 9:43
2
@HimanshuGehlot You can't do it directly withrbind()anddata.frame()only. You could do something likesetNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group'))which includes them, but are not explicit
– Sotos
Nov 20 '18 at 10:00
3
3
Nice 1. You can also do all in 1 line, i.e.
setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))– Sotos
Nov 20 '18 at 9:37
Nice 1. You can also do all in 1 line, i.e.
setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))– Sotos
Nov 20 '18 at 9:37
Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.
– Himanshu Gehlot
Nov 20 '18 at 9:39
Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.
– Himanshu Gehlot
Nov 20 '18 at 9:39
1
1
That smells like homework...
– Sotos
Nov 20 '18 at 9:41
That smells like homework...
– Sotos
Nov 20 '18 at 9:41
Not exactly, i am making some practice questions and got stuck with this.
– Himanshu Gehlot
Nov 20 '18 at 9:43
Not exactly, i am making some practice questions and got stuck with this.
– Himanshu Gehlot
Nov 20 '18 at 9:43
2
2
@HimanshuGehlot You can't do it directly with
rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit– Sotos
Nov 20 '18 at 10:00
@HimanshuGehlot You can't do it directly with
rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit– Sotos
Nov 20 '18 at 10:00
|
show 7 more comments
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