How to add elements to an empty array in PHP?

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412

If I define an array in PHP such as (I don't define its size):

$cart = array();

Do I simply add elements to it using the following?

$cart = 13;

$cart = "foo";

$cart = obj;

Don't arrays in PHP have an add method, for example, cart.add(13)?

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

add a comment |

412

If I define an array in PHP such as (I don't define its size):

$cart = array();

Do I simply add elements to it using the following?

$cart = 13;

$cart = "foo";

$cart = obj;

Don't arrays in PHP have an add method, for example, cart.add(13)?

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

add a comment |

412

If I define an array in PHP such as (I don't define its size):

$cart = array();

Do I simply add elements to it using the following?

$cart = 13;

$cart = "foo";

$cart = obj;

Don't arrays in PHP have an add method, for example, cart.add(13)?

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

If I define an array in PHP such as (I don't define its size):

$cart = array();

Do I simply add elements to it using the following?

$cart = 13;

$cart = "foo";

$cart = obj;

Don't arrays in PHP have an add method, for example, cart.add(13)?

php arrays variables

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

edited Apr 14 '14 at 8:20

Peter Mortensen

13.9k1987114

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

asked Mar 24 '09 at 9:35

AquinasTub

3,00051814

add a comment |

9 Answers
9

active

oldest

votes

676

Both array_push and the method you described will work.

$cart = array();

$cart = 13;

$cart = 14;

// etc



//Above is correct. but below one is for further understanding

$cart = array();

for($i=0;$i<=5;$i++){

    $cart = $i;  

}

echo "<pre>";

print_r($cart);

echo "</pre>";

Is the same as:

<?php

$cart = array();

array_push($cart, 13);

array_push($cart, 14);



// Or 

$cart = array();

array_push($cart, 13, 14);

?>

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

161

As stated in the PHP documentation, if you're only pushing a single element every time (like in a loop) or a single element once, it's best to use the $cart = 13 method not only because it's less characters to do the same operation, but it also doesn't impose the performance overhead of a function call, which array_push() would. Edit: But, great answer. Effectively the same, and majority of uses won't even notice a performance difference, but helps to know those nuances.

– Mattygabe
Jan 15 '11 at 5:10

55

Is it just me or does the $cart=... syntax, at first glance, look like a variable assignment and not an implicit array_push?

– Brad Hein
Feb 5 '14 at 16:36

4

It definitely does to me. I wouldn't mind an explanation of why its not an assignment.

– limeandcoconut
May 20 '14 at 4:05

3

$cart = 13; is faster. has less characters and looks better.

– Gal Bracha
Jul 28 '14 at 6:54

11

I'll just offer my alternative viewpoint that it's VERY confusing for other language programmers to read the syntax of cart =..., I've got experience with a lot of languages and I'd never guess that's what it does.

– Erti-Chris Eelmaa
Oct 13 '16 at 18:02

|
show 6 more comments

It's better to not use array_push and just use what you suggested. The functions just add overhead.

//We don't need to define the array, but in many cases it's the best solution.

$cart = array();



//Automatic new integer key higher than the highest 

//existing integer key in the array, starts at 0.

$cart = 13;

$cart = 'text';



//Numeric key

$cart[4] = $object;



//Text key (assoc)

$cart['key'] = 'test';

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

answered Mar 24 '09 at 9:47

OIS

8,2282239

10

"If you're adding multiple values to an array in a loop, it's faster to use array_push than repeated = statements" php.net/manual/en/function.array-push.php#84959

– Ollie Glass
Dec 18 '10 at 17:15

3

Absolutely correct if your use-case is adding a single item or items one at a time. If all values are known at the same time, it's probably best just to use the array_push notation depending on how many items must be added the extra characters from re-typing the array name each time may be more of a performance hindrance than the function call over-head. As always, judgment should be exercised when choosing. Good answers!

– Mattygabe
Jan 15 '11 at 5:13

1

This answer is the most complete.

– Lokiare
May 24 '18 at 16:19

add a comment |

Based on my experience, you solution is fine(best) when keys are not important:

$cart = ;

$cart = 13;

$cart = "foo";

$cart = obj;

edited May 5 '18 at 18:26

answered Oct 14 '15 at 13:15

fico7489

3,01022447

add a comment |

You can use array_push.
It adds the elements to the end of the array, like in a stack.

You could have also done it like this:

$cart = array(13, "foo", $obj);

edited Mar 24 '09 at 10:03

answered Mar 24 '09 at 9:37

andi

8,87394245

add a comment |

REMEMBER, this method overwrites first array, so use only when you are sure!

$arr1 = $arr1 + $arr2;

(see source)

edited May 23 '17 at 11:47

Community♦

answered May 3 '15 at 17:05

T.Todua

32k12136141

1

Why the downvote, can someone explain why this is bad? is it insecure?

– Sandy
Jan 18 '17 at 14:14

2

@SandyBeach it's not an answer

– mateos
Mar 25 '17 at 6:39

add a comment |

Your first option works very fine for me.

$cart = array();

cart = 1:

$cart   = 'foo':

$cart = 3;

answered Oct 12 '18 at 14:10

Emmanuel David

246

2

Line 4 will overwrite the entire array.

– Blacksilver
Oct 12 '18 at 14:32

add a comment |

$products_arr["passenger_details"]=array();

array_push($products_arr["passenger_details"],array("Name"=>"Isuru Eshan","E-Mail"=>"isuru.eshan@gmail.com"));

echo "<pre>";

echo json_encode($products_arr,JSON_PRETTY_PRINT);

echo "</pre>";



//OR



$countries = array();

$countries["DK"] = array("code"=>"DK","name"=>"Denmark","d_code"=>"+45");

$countries["DJ"] = array("code"=>"DJ","name"=>"Djibouti","d_code"=>"+253");

$countries["DM"] = array("code"=>"DM","name"=>"Dominica","d_code"=>"+1");

foreach ($countries as $country){

echo "<pre>";

echo print_r($country);

echo "</pre>";

}

edited Nov 22 '18 at 6:42

answered Nov 22 '18 at 6:37

Isuru Eshan

add a comment |

-1

When one wants elements to be added with zero-based element indexing, I guess this will work as well:

// adding elements to an array with zero-based index

$matrix= array();

$matrix[count($matrix)]= 'element 1';

$matrix[count($matrix)]= 'element 2';

...

$matrix[count($matrix)]= 'element N';

answered Jun 23 '14 at 9:19

Gestix Team

171

add a comment |

-2

It's called array_push: http://il.php.net/function.array-push

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

2

Answers with links are not helpful unless they also quote the relevant data in case the linked page disappears.

– Lokiare
May 24 '18 at 16:18

add a comment |

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9 Answers
9

active

oldest

votes

9 Answers
9

active

oldest

votes

676

Both array_push and the method you described will work.

$cart = array();

$cart = 13;

$cart = 14;

// etc



//Above is correct. but below one is for further understanding

$cart = array();

for($i=0;$i<=5;$i++){

    $cart = $i;  

}

echo "<pre>";

print_r($cart);

echo "</pre>";

Is the same as:

<?php

$cart = array();

array_push($cart, 13);

array_push($cart, 14);



// Or 

$cart = array();

array_push($cart, 13, 14);

?>

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

161

As stated in the PHP documentation, if you're only pushing a single element every time (like in a loop) or a single element once, it's best to use the $cart = 13 method not only because it's less characters to do the same operation, but it also doesn't impose the performance overhead of a function call, which array_push() would. Edit: But, great answer. Effectively the same, and majority of uses won't even notice a performance difference, but helps to know those nuances.

– Mattygabe
Jan 15 '11 at 5:10

55

Is it just me or does the $cart=... syntax, at first glance, look like a variable assignment and not an implicit array_push?

– Brad Hein
Feb 5 '14 at 16:36

4

It definitely does to me. I wouldn't mind an explanation of why its not an assignment.

– limeandcoconut
May 20 '14 at 4:05

3

$cart = 13; is faster. has less characters and looks better.

– Gal Bracha
Jul 28 '14 at 6:54

11

I'll just offer my alternative viewpoint that it's VERY confusing for other language programmers to read the syntax of cart =..., I've got experience with a lot of languages and I'd never guess that's what it does.

– Erti-Chris Eelmaa
Oct 13 '16 at 18:02

|
show 6 more comments

676

Both array_push and the method you described will work.

$cart = array();

$cart = 13;

$cart = 14;

// etc



//Above is correct. but below one is for further understanding

$cart = array();

for($i=0;$i<=5;$i++){

    $cart = $i;  

}

echo "<pre>";

print_r($cart);

echo "</pre>";

Is the same as:

<?php

$cart = array();

array_push($cart, 13);

array_push($cart, 14);



// Or 

$cart = array();

array_push($cart, 13, 14);

?>

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

161

As stated in the PHP documentation, if you're only pushing a single element every time (like in a loop) or a single element once, it's best to use the $cart = 13 method not only because it's less characters to do the same operation, but it also doesn't impose the performance overhead of a function call, which array_push() would. Edit: But, great answer. Effectively the same, and majority of uses won't even notice a performance difference, but helps to know those nuances.

– Mattygabe
Jan 15 '11 at 5:10

55

Is it just me or does the $cart=... syntax, at first glance, look like a variable assignment and not an implicit array_push?

– Brad Hein
Feb 5 '14 at 16:36

4

It definitely does to me. I wouldn't mind an explanation of why its not an assignment.

– limeandcoconut
May 20 '14 at 4:05

3

$cart = 13; is faster. has less characters and looks better.

– Gal Bracha
Jul 28 '14 at 6:54

11

I'll just offer my alternative viewpoint that it's VERY confusing for other language programmers to read the syntax of cart =..., I've got experience with a lot of languages and I'd never guess that's what it does.

– Erti-Chris Eelmaa
Oct 13 '16 at 18:02

|
show 6 more comments

676

Both array_push and the method you described will work.

$cart = array();

$cart = 13;

$cart = 14;

// etc



//Above is correct. but below one is for further understanding

$cart = array();

for($i=0;$i<=5;$i++){

    $cart = $i;  

}

echo "<pre>";

print_r($cart);

echo "</pre>";

Is the same as:

<?php

$cart = array();

array_push($cart, 13);

array_push($cart, 14);



// Or 

$cart = array();

array_push($cart, 13, 14);

?>

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

Both array_push and the method you described will work.

$cart = array();

$cart = 13;

$cart = 14;

// etc



//Above is correct. but below one is for further understanding

$cart = array();

for($i=0;$i<=5;$i++){

    $cart = $i;  

}

echo "<pre>";

print_r($cart);

echo "</pre>";

Is the same as:

<?php

$cart = array();

array_push($cart, 13);

array_push($cart, 14);



// Or 

$cart = array();

array_push($cart, 13, 14);

?>

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

edited Nov 22 '18 at 8:58

Yoram de Langen

3,97721728

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

answered Mar 24 '09 at 9:42

Bart S.

7,53811526

161

As stated in the PHP documentation, if you're only pushing a single element every time (like in a loop) or a single element once, it's best to use the $cart = 13 method not only because it's less characters to do the same operation, but it also doesn't impose the performance overhead of a function call, which array_push() would. Edit: But, great answer. Effectively the same, and majority of uses won't even notice a performance difference, but helps to know those nuances.

– Mattygabe
Jan 15 '11 at 5:10

55

Is it just me or does the $cart=... syntax, at first glance, look like a variable assignment and not an implicit array_push?

– Brad Hein
Feb 5 '14 at 16:36

4

It definitely does to me. I wouldn't mind an explanation of why its not an assignment.

– limeandcoconut
May 20 '14 at 4:05

3

$cart = 13; is faster. has less characters and looks better.

– Gal Bracha
Jul 28 '14 at 6:54

11

I'll just offer my alternative viewpoint that it's VERY confusing for other language programmers to read the syntax of cart =..., I've got experience with a lot of languages and I'd never guess that's what it does.

– Erti-Chris Eelmaa
Oct 13 '16 at 18:02

|
show 6 more comments

161

As stated in the PHP documentation, if you're only pushing a single element every time (like in a loop) or a single element once, it's best to use the $cart = 13 method not only because it's less characters to do the same operation, but it also doesn't impose the performance overhead of a function call, which array_push() would. Edit: But, great answer. Effectively the same, and majority of uses won't even notice a performance difference, but helps to know those nuances.

– Mattygabe
Jan 15 '11 at 5:10

55

Is it just me or does the $cart=... syntax, at first glance, look like a variable assignment and not an implicit array_push?

– Brad Hein
Feb 5 '14 at 16:36

4

It definitely does to me. I wouldn't mind an explanation of why its not an assignment.

– limeandcoconut
May 20 '14 at 4:05

3

$cart = 13; is faster. has less characters and looks better.

– Gal Bracha
Jul 28 '14 at 6:54

11

I'll just offer my alternative viewpoint that it's VERY confusing for other language programmers to read the syntax of cart =..., I've got experience with a lot of languages and I'd never guess that's what it does.

– Erti-Chris Eelmaa
Oct 13 '16 at 18:02

161

As stated in the PHP documentation, if you're only pushing a single element every time (like in a loop) or a single element once, it's best to use the $cart = 13 method not only because it's less characters to do the same operation, but it also doesn't impose the performance overhead of a function call, which array_push() would. Edit: But, great answer. Effectively the same, and majority of uses won't even notice a performance difference, but helps to know those nuances.

– Mattygabe
Jan 15 '11 at 5:10

Is it just me or does the $cart=... syntax, at first glance, look like a variable assignment and not an implicit array_push?

– Brad Hein
Feb 5 '14 at 16:36

It definitely does to me. I wouldn't mind an explanation of why its not an assignment.

– limeandcoconut
May 20 '14 at 4:05

$cart = 13; is faster. has less characters and looks better.

– Gal Bracha
Jul 28 '14 at 6:54

I'll just offer my alternative viewpoint that it's VERY confusing for other language programmers to read the syntax of cart =..., I've got experience with a lot of languages and I'd never guess that's what it does.

– Erti-Chris Eelmaa
Oct 13 '16 at 18:02

|
show 6 more comments

It's better to not use array_push and just use what you suggested. The functions just add overhead.

//We don't need to define the array, but in many cases it's the best solution.

$cart = array();



//Automatic new integer key higher than the highest 

//existing integer key in the array, starts at 0.

$cart = 13;

$cart = 'text';



//Numeric key

$cart[4] = $object;



//Text key (assoc)

$cart['key'] = 'test';

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

answered Mar 24 '09 at 9:47

OIS

8,2282239

10

"If you're adding multiple values to an array in a loop, it's faster to use array_push than repeated = statements" php.net/manual/en/function.array-push.php#84959

– Ollie Glass
Dec 18 '10 at 17:15

3

Absolutely correct if your use-case is adding a single item or items one at a time. If all values are known at the same time, it's probably best just to use the array_push notation depending on how many items must be added the extra characters from re-typing the array name each time may be more of a performance hindrance than the function call over-head. As always, judgment should be exercised when choosing. Good answers!

– Mattygabe
Jan 15 '11 at 5:13

1

This answer is the most complete.

– Lokiare
May 24 '18 at 16:19

add a comment |

It's better to not use array_push and just use what you suggested. The functions just add overhead.

//We don't need to define the array, but in many cases it's the best solution.

$cart = array();



//Automatic new integer key higher than the highest 

//existing integer key in the array, starts at 0.

$cart = 13;

$cart = 'text';



//Numeric key

$cart[4] = $object;



//Text key (assoc)

$cart['key'] = 'test';

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

answered Mar 24 '09 at 9:47

OIS

8,2282239

10

"If you're adding multiple values to an array in a loop, it's faster to use array_push than repeated = statements" php.net/manual/en/function.array-push.php#84959

– Ollie Glass
Dec 18 '10 at 17:15

3

Absolutely correct if your use-case is adding a single item or items one at a time. If all values are known at the same time, it's probably best just to use the array_push notation depending on how many items must be added the extra characters from re-typing the array name each time may be more of a performance hindrance than the function call over-head. As always, judgment should be exercised when choosing. Good answers!

– Mattygabe
Jan 15 '11 at 5:13

1

This answer is the most complete.

– Lokiare
May 24 '18 at 16:19

add a comment |

It's better to not use array_push and just use what you suggested. The functions just add overhead.

//We don't need to define the array, but in many cases it's the best solution.

$cart = array();



//Automatic new integer key higher than the highest 

//existing integer key in the array, starts at 0.

$cart = 13;

$cart = 'text';



//Numeric key

$cart[4] = $object;



//Text key (assoc)

$cart['key'] = 'test';

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

answered Mar 24 '09 at 9:47

OIS

8,2282239

It's better to not use array_push and just use what you suggested. The functions just add overhead.

//We don't need to define the array, but in many cases it's the best solution.

$cart = array();



//Automatic new integer key higher than the highest 

//existing integer key in the array, starts at 0.

$cart = 13;

$cart = 'text';



//Numeric key

$cart[4] = $object;



//Text key (assoc)

$cart['key'] = 'test';

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

answered Mar 24 '09 at 9:47

OIS

8,2282239

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

edited Jul 31 '15 at 7:16

kamal pal

3,96451939

answered Mar 24 '09 at 9:47

OIS

8,2282239

answered Mar 24 '09 at 9:47

OIS

8,2282239

answered Mar 24 '09 at 9:47

OIS

8,2282239

10

"If you're adding multiple values to an array in a loop, it's faster to use array_push than repeated = statements" php.net/manual/en/function.array-push.php#84959

– Ollie Glass
Dec 18 '10 at 17:15

3

Absolutely correct if your use-case is adding a single item or items one at a time. If all values are known at the same time, it's probably best just to use the array_push notation depending on how many items must be added the extra characters from re-typing the array name each time may be more of a performance hindrance than the function call over-head. As always, judgment should be exercised when choosing. Good answers!

– Mattygabe
Jan 15 '11 at 5:13

1

This answer is the most complete.

– Lokiare
May 24 '18 at 16:19

add a comment |

10

"If you're adding multiple values to an array in a loop, it's faster to use array_push than repeated = statements" php.net/manual/en/function.array-push.php#84959

– Ollie Glass
Dec 18 '10 at 17:15

3

Absolutely correct if your use-case is adding a single item or items one at a time. If all values are known at the same time, it's probably best just to use the array_push notation depending on how many items must be added the extra characters from re-typing the array name each time may be more of a performance hindrance than the function call over-head. As always, judgment should be exercised when choosing. Good answers!

– Mattygabe
Jan 15 '11 at 5:13

1

This answer is the most complete.

– Lokiare
May 24 '18 at 16:19

"If you're adding multiple values to an array in a loop, it's faster to use array_push than repeated = statements" php.net/manual/en/function.array-push.php#84959

– Ollie Glass
Dec 18 '10 at 17:15

Absolutely correct if your use-case is adding a single item or items one at a time. If all values are known at the same time, it's probably best just to use the array_push notation depending on how many items must be added the extra characters from re-typing the array name each time may be more of a performance hindrance than the function call over-head. As always, judgment should be exercised when choosing. Good answers!

– Mattygabe
Jan 15 '11 at 5:13

This answer is the most complete.

– Lokiare
May 24 '18 at 16:19

add a comment |

Based on my experience, you solution is fine(best) when keys are not important:

$cart = ;

$cart = 13;

$cart = "foo";

$cart = obj;

edited May 5 '18 at 18:26

answered Oct 14 '15 at 13:15

fico7489

3,01022447

add a comment |

Based on my experience, you solution is fine(best) when keys are not important:

$cart = ;

$cart = 13;

$cart = "foo";

$cart = obj;

edited May 5 '18 at 18:26

answered Oct 14 '15 at 13:15

fico7489

3,01022447

add a comment |

Based on my experience, you solution is fine(best) when keys are not important:

$cart = ;

$cart = 13;

$cart = "foo";

$cart = obj;

edited May 5 '18 at 18:26

answered Oct 14 '15 at 13:15

fico7489

3,01022447

Based on my experience, you solution is fine(best) when keys are not important:

$cart = ;

$cart = 13;

$cart = "foo";

$cart = obj;

edited May 5 '18 at 18:26

answered Oct 14 '15 at 13:15

fico7489

3,01022447

edited May 5 '18 at 18:26

answered Oct 14 '15 at 13:15

fico7489

3,01022447

answered Oct 14 '15 at 13:15

fico7489

3,01022447

answered Oct 14 '15 at 13:15

fico7489

3,01022447

add a comment |

You can use array_push.
It adds the elements to the end of the array, like in a stack.

You could have also done it like this:

$cart = array(13, "foo", $obj);

edited Mar 24 '09 at 10:03

answered Mar 24 '09 at 9:37

andi

8,87394245

add a comment |

You can use array_push.
It adds the elements to the end of the array, like in a stack.

You could have also done it like this:

$cart = array(13, "foo", $obj);

edited Mar 24 '09 at 10:03

answered Mar 24 '09 at 9:37

andi

8,87394245

add a comment |

You can use array_push.
It adds the elements to the end of the array, like in a stack.

You could have also done it like this:

$cart = array(13, "foo", $obj);

edited Mar 24 '09 at 10:03

answered Mar 24 '09 at 9:37

andi

8,87394245

You can use array_push.
It adds the elements to the end of the array, like in a stack.

You could have also done it like this:

$cart = array(13, "foo", $obj);

edited Mar 24 '09 at 10:03

answered Mar 24 '09 at 9:37

andi

8,87394245

edited Mar 24 '09 at 10:03

answered Mar 24 '09 at 9:37

andi

8,87394245

answered Mar 24 '09 at 9:37

andi

8,87394245

answered Mar 24 '09 at 9:37

andi

8,87394245

add a comment |

REMEMBER, this method overwrites first array, so use only when you are sure!

$arr1 = $arr1 + $arr2;

(see source)

edited May 23 '17 at 11:47

Community♦

answered May 3 '15 at 17:05

T.Todua

32k12136141

1

Why the downvote, can someone explain why this is bad? is it insecure?

– Sandy
Jan 18 '17 at 14:14

2

@SandyBeach it's not an answer

– mateos
Mar 25 '17 at 6:39

add a comment |

REMEMBER, this method overwrites first array, so use only when you are sure!

$arr1 = $arr1 + $arr2;

(see source)

edited May 23 '17 at 11:47

Community♦

answered May 3 '15 at 17:05

T.Todua

32k12136141

1

Why the downvote, can someone explain why this is bad? is it insecure?

– Sandy
Jan 18 '17 at 14:14

2

@SandyBeach it's not an answer

– mateos
Mar 25 '17 at 6:39

add a comment |

REMEMBER, this method overwrites first array, so use only when you are sure!

$arr1 = $arr1 + $arr2;

(see source)

edited May 23 '17 at 11:47

Community♦

answered May 3 '15 at 17:05

T.Todua

32k12136141

REMEMBER, this method overwrites first array, so use only when you are sure!

$arr1 = $arr1 + $arr2;

(see source)

edited May 23 '17 at 11:47

Community♦

answered May 3 '15 at 17:05

T.Todua

32k12136141

edited May 23 '17 at 11:47

Community♦

edited May 23 '17 at 11:47

Community♦

edited May 23 '17 at 11:47

Community♦

answered May 3 '15 at 17:05

T.Todua

32k12136141

answered May 3 '15 at 17:05

T.Todua

32k12136141

answered May 3 '15 at 17:05

T.Todua

32k12136141

1

Why the downvote, can someone explain why this is bad? is it insecure?

– Sandy
Jan 18 '17 at 14:14

2

@SandyBeach it's not an answer

– mateos
Mar 25 '17 at 6:39

add a comment |

1

Why the downvote, can someone explain why this is bad? is it insecure?

– Sandy
Jan 18 '17 at 14:14

2

@SandyBeach it's not an answer

– mateos
Mar 25 '17 at 6:39

Why the downvote, can someone explain why this is bad? is it insecure?

– Sandy
Jan 18 '17 at 14:14

@SandyBeach it's not an answer

– mateos
Mar 25 '17 at 6:39

add a comment |

Your first option works very fine for me.

$cart = array();

cart = 1:

$cart   = 'foo':

$cart = 3;

answered Oct 12 '18 at 14:10

Emmanuel David

246

2

Line 4 will overwrite the entire array.

– Blacksilver
Oct 12 '18 at 14:32

add a comment |

Your first option works very fine for me.

$cart = array();

cart = 1:

$cart   = 'foo':

$cart = 3;

answered Oct 12 '18 at 14:10

Emmanuel David

246

2

Line 4 will overwrite the entire array.

– Blacksilver
Oct 12 '18 at 14:32

add a comment |

Your first option works very fine for me.

$cart = array();

cart = 1:

$cart   = 'foo':

$cart = 3;

answered Oct 12 '18 at 14:10

Emmanuel David

246

Your first option works very fine for me.

$cart = array();

cart = 1:

$cart   = 'foo':

$cart = 3;

answered Oct 12 '18 at 14:10

Emmanuel David

246

answered Oct 12 '18 at 14:10

Emmanuel David

246

answered Oct 12 '18 at 14:10

Emmanuel David

246

answered Oct 12 '18 at 14:10

Emmanuel David

246

2

Line 4 will overwrite the entire array.

– Blacksilver
Oct 12 '18 at 14:32

add a comment |

2

Line 4 will overwrite the entire array.

– Blacksilver
Oct 12 '18 at 14:32

Line 4 will overwrite the entire array.

– Blacksilver
Oct 12 '18 at 14:32

add a comment |

$products_arr["passenger_details"]=array();

array_push($products_arr["passenger_details"],array("Name"=>"Isuru Eshan","E-Mail"=>"isuru.eshan@gmail.com"));

echo "<pre>";

echo json_encode($products_arr,JSON_PRETTY_PRINT);

echo "</pre>";



//OR



$countries = array();

$countries["DK"] = array("code"=>"DK","name"=>"Denmark","d_code"=>"+45");

$countries["DJ"] = array("code"=>"DJ","name"=>"Djibouti","d_code"=>"+253");

$countries["DM"] = array("code"=>"DM","name"=>"Dominica","d_code"=>"+1");

foreach ($countries as $country){

echo "<pre>";

echo print_r($country);

echo "</pre>";

}

edited Nov 22 '18 at 6:42

answered Nov 22 '18 at 6:37

Isuru Eshan

add a comment |

$products_arr["passenger_details"]=array();

array_push($products_arr["passenger_details"],array("Name"=>"Isuru Eshan","E-Mail"=>"isuru.eshan@gmail.com"));

echo "<pre>";

echo json_encode($products_arr,JSON_PRETTY_PRINT);

echo "</pre>";



//OR



$countries = array();

$countries["DK"] = array("code"=>"DK","name"=>"Denmark","d_code"=>"+45");

$countries["DJ"] = array("code"=>"DJ","name"=>"Djibouti","d_code"=>"+253");

$countries["DM"] = array("code"=>"DM","name"=>"Dominica","d_code"=>"+1");

foreach ($countries as $country){

echo "<pre>";

echo print_r($country);

echo "</pre>";

}

edited Nov 22 '18 at 6:42

answered Nov 22 '18 at 6:37

Isuru Eshan

add a comment |

$products_arr["passenger_details"]=array();

array_push($products_arr["passenger_details"],array("Name"=>"Isuru Eshan","E-Mail"=>"isuru.eshan@gmail.com"));

echo "<pre>";

echo json_encode($products_arr,JSON_PRETTY_PRINT);

echo "</pre>";



//OR



$countries = array();

$countries["DK"] = array("code"=>"DK","name"=>"Denmark","d_code"=>"+45");

$countries["DJ"] = array("code"=>"DJ","name"=>"Djibouti","d_code"=>"+253");

$countries["DM"] = array("code"=>"DM","name"=>"Dominica","d_code"=>"+1");

foreach ($countries as $country){

echo "<pre>";

echo print_r($country);

echo "</pre>";

}

edited Nov 22 '18 at 6:42

answered Nov 22 '18 at 6:37

Isuru Eshan

$products_arr["passenger_details"]=array();

array_push($products_arr["passenger_details"],array("Name"=>"Isuru Eshan","E-Mail"=>"isuru.eshan@gmail.com"));

echo "<pre>";

echo json_encode($products_arr,JSON_PRETTY_PRINT);

echo "</pre>";



//OR



$countries = array();

$countries["DK"] = array("code"=>"DK","name"=>"Denmark","d_code"=>"+45");

$countries["DJ"] = array("code"=>"DJ","name"=>"Djibouti","d_code"=>"+253");

$countries["DM"] = array("code"=>"DM","name"=>"Dominica","d_code"=>"+1");

foreach ($countries as $country){

echo "<pre>";

echo print_r($country);

echo "</pre>";

}

edited Nov 22 '18 at 6:42

answered Nov 22 '18 at 6:37

Isuru Eshan

edited Nov 22 '18 at 6:42

answered Nov 22 '18 at 6:37

Isuru Eshan

answered Nov 22 '18 at 6:37

Isuru Eshan

answered Nov 22 '18 at 6:37

Isuru Eshan

add a comment |

-1

When one wants elements to be added with zero-based element indexing, I guess this will work as well:

// adding elements to an array with zero-based index

$matrix= array();

$matrix[count($matrix)]= 'element 1';

$matrix[count($matrix)]= 'element 2';

...

$matrix[count($matrix)]= 'element N';

answered Jun 23 '14 at 9:19

Gestix Team

171

add a comment |

-1

When one wants elements to be added with zero-based element indexing, I guess this will work as well:

// adding elements to an array with zero-based index

$matrix= array();

$matrix[count($matrix)]= 'element 1';

$matrix[count($matrix)]= 'element 2';

...

$matrix[count($matrix)]= 'element N';

answered Jun 23 '14 at 9:19

Gestix Team

171

add a comment |

-1

When one wants elements to be added with zero-based element indexing, I guess this will work as well:

// adding elements to an array with zero-based index

$matrix= array();

$matrix[count($matrix)]= 'element 1';

$matrix[count($matrix)]= 'element 2';

...

$matrix[count($matrix)]= 'element N';

answered Jun 23 '14 at 9:19

Gestix Team

171

When one wants elements to be added with zero-based element indexing, I guess this will work as well:

// adding elements to an array with zero-based index

$matrix= array();

$matrix[count($matrix)]= 'element 1';

$matrix[count($matrix)]= 'element 2';

...

$matrix[count($matrix)]= 'element N';

answered Jun 23 '14 at 9:19

Gestix Team

171

answered Jun 23 '14 at 9:19

Gestix Team

171

answered Jun 23 '14 at 9:19

Gestix Team

171

answered Jun 23 '14 at 9:19

Gestix Team

171

add a comment |

-2

It's called array_push: http://il.php.net/function.array-push

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

2

Answers with links are not helpful unless they also quote the relevant data in case the linked page disappears.

– Lokiare
May 24 '18 at 16:18

add a comment |

-2

It's called array_push: http://il.php.net/function.array-push

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

2

Answers with links are not helpful unless they also quote the relevant data in case the linked page disappears.

– Lokiare
May 24 '18 at 16:18

add a comment |

-2

It's called array_push: http://il.php.net/function.array-push

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

It's called array_push: http://il.php.net/function.array-push

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

answered Mar 24 '09 at 9:37

Assaf Lavie

43.1k28127184

2

Answers with links are not helpful unless they also quote the relevant data in case the linked page disappears.

– Lokiare
May 24 '18 at 16:18

add a comment |

2

Answers with links are not helpful unless they also quote the relevant data in case the linked page disappears.

– Lokiare
May 24 '18 at 16:18

Answers with links are not helpful unless they also quote the relevant data in case the linked page disappears.

– Lokiare
May 24 '18 at 16:18

add a comment |

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