Alter number sort / number sequence
I have an array / number sequence a=[1,2,3,4,5] and I'm trying
to create an array / number sequence that looks like a_new below:
The columns represent the orders / index the numbers should go in.
a_new=...
[1,2,3,4,5;
2,1,2,3,4;
3,3,1,2,3;
4,4,4,1,2;
5,5,5,5,1]
My thoughts where to use circshift but quickly found out that would not work.
a=[1,2,3,4,5];
for n=1:5
a_wrong(:,n)=circshift(a(:)',[0 n])(:)
end
produces
a_wrong=[
5 4 3 2 1
1 5 4 3 2
2 1 5 4 3
3 2 1 5 4
4 3 2 1 5]
Any thoughts? It doesn't need to use circshift if that won't work.
PS: I'm using Octave 4.2 which is similar to Matlab
matlab sequence octave
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
asked Nov 13 at 17:00
Rick T
1,52042971
add a comment |
I have an array / number sequence a=[1,2,3,4,5] and I'm trying
to create an array / number sequence that looks like a_new below:
The columns represent the orders / index the numbers should go in.
a_new=...
[1,2,3,4,5;
2,1,2,3,4;
3,3,1,2,3;
4,4,4,1,2;
5,5,5,5,1]
My thoughts where to use circshift but quickly found out that would not work.
a=[1,2,3,4,5];
for n=1:5
a_wrong(:,n)=circshift(a(:)',[0 n])(:)
end
produces
a_wrong=[
5 4 3 2 1
1 5 4 3 2
2 1 5 4 3
3 2 1 5 4
4 3 2 1 5]
Any thoughts? It doesn't need to use circshift if that won't work.
PS: I'm using Octave 4.2 which is similar to Matlab
matlab sequence octave
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
asked Nov 13 at 17:00
Rick T
1,52042971
can you explain your matrix? why is the first column a different direction than the others? Are you 100% sure this is what you want?circshiftwont work because of this, the first column is a special case
– Ander Biguri
Nov 13 at 17:11
@AnderBiguri the columns represent the orders / index the numbers should go in.
– Rick T
Nov 13 at 17:17
add a comment |
I have an array / number sequence a=[1,2,3,4,5] and I'm trying
to create an array / number sequence that looks like a_new below:
The columns represent the orders / index the numbers should go in.
a_new=...
[1,2,3,4,5;
2,1,2,3,4;
3,3,1,2,3;
4,4,4,1,2;
5,5,5,5,1]
My thoughts where to use circshift but quickly found out that would not work.
a=[1,2,3,4,5];
for n=1:5
a_wrong(:,n)=circshift(a(:)',[0 n])(:)
end
produces
a_wrong=[
5 4 3 2 1
1 5 4 3 2
2 1 5 4 3
3 2 1 5 4
4 3 2 1 5]
Any thoughts? It doesn't need to use circshift if that won't work.
PS: I'm using Octave 4.2 which is similar to Matlab
matlab sequence octave
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
asked Nov 13 at 17:00
Rick T
1,52042971
I have an array / number sequence a=[1,2,3,4,5] and I'm trying
to create an array / number sequence that looks like a_new below:
The columns represent the orders / index the numbers should go in.
a_new=...
[1,2,3,4,5;
2,1,2,3,4;
3,3,1,2,3;
4,4,4,1,2;
5,5,5,5,1]
My thoughts where to use circshift but quickly found out that would not work.
a=[1,2,3,4,5];
for n=1:5
a_wrong(:,n)=circshift(a(:)',[0 n])(:)
end
produces
a_wrong=[
5 4 3 2 1
1 5 4 3 2
2 1 5 4 3
3 2 1 5 4
4 3 2 1 5]
Any thoughts? It doesn't need to use circshift if that won't work.
PS: I'm using Octave 4.2 which is similar to Matlab
matlab sequence octave
matlab sequence octave
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
asked Nov 13 at 17:00
Rick T
1,52042971
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
asked Nov 13 at 17:00
Rick T
1,52042971
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
edited Nov 13 at 17:28
Cris Luengo
18.6k51947
18.6k51947
asked Nov 13 at 17:00
Rick T
1,52042971
asked Nov 13 at 17:00
Rick T
1,52042971
asked Nov 13 at 17:00
Rick T
1,52042971
1,52042971
can you explain your matrix? why is the first column a different direction than the others? Are you 100% sure this is what you want?circshiftwont work because of this, the first column is a special case
– Ander Biguri
Nov 13 at 17:11
@AnderBiguri the columns represent the orders / index the numbers should go in.
– Rick T
Nov 13 at 17:17
add a comment |
can you explain your matrix? why is the first column a different direction than the others? Are you 100% sure this is what you want?circshiftwont work because of this, the first column is a special case
– Ander Biguri
Nov 13 at 17:11
@AnderBiguri the columns represent the orders / index the numbers should go in.
– Rick T
Nov 13 at 17:17
can you explain your matrix? why is the first column a different direction than the others? Are you 100% sure this is what you want?
circshift wont work because of this, the first column is a special case– Ander Biguri
Nov 13 at 17:11
can you explain your matrix? why is the first column a different direction than the others? Are you 100% sure this is what you want?
circshift wont work because of this, the first column is a special case– Ander Biguri
Nov 13 at 17:11
@AnderBiguri the columns represent the orders / index the numbers should go in.
– Rick T
Nov 13 at 17:17
@AnderBiguri the columns represent the orders / index the numbers should go in.
– Rick T
Nov 13 at 17:17
add a comment |
3 Answers
3
active
oldest
votes
There are probably quite a few different ways to generate this matrix. Here's one using the functions repmat, toeplitz, tril, and triu:
>> a_new = tril(repmat(a.', 1, numel(a)), -1)+triu(toeplitz(a))
a_new =
1 2 3 4 5
2 1 2 3 4
3 3 1 2 3
4 4 4 1 2
5 5 5 5 1
answered Nov 13 at 17:11
gnovice
115k13229332
add a comment |
I'm not sure about a built-in function, but this should work;
a=[1,2,3,4,5];
a_out = ones(length(a), length(a))
for n=1:5
a_out(n,:) = [n*ones(n-1),a(n:end)]
end
I do not have Octave or MATLAB installed on my computer, so I cannot test it. This may have a silly error, forgive me for that!
answered Nov 13 at 17:19
SRT HellKitty
2938
add a comment |
You can use spdiags to generate the matrix:
n = numel(a);
a_new = spdiags([repmat(flip(a).',1,n); repmat(a,n-1,1)],(1-n):0);
answered Nov 14 at 4:04
rahnema1
9,8752922
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
There are probably quite a few different ways to generate this matrix. Here's one using the functions repmat, toeplitz, tril, and triu:
>> a_new = tril(repmat(a.', 1, numel(a)), -1)+triu(toeplitz(a))
a_new =
1 2 3 4 5
2 1 2 3 4
3 3 1 2 3
4 4 4 1 2
5 5 5 5 1
answered Nov 13 at 17:11
gnovice
115k13229332
add a comment |
There are probably quite a few different ways to generate this matrix. Here's one using the functions repmat, toeplitz, tril, and triu:
>> a_new = tril(repmat(a.', 1, numel(a)), -1)+triu(toeplitz(a))
a_new =
1 2 3 4 5
2 1 2 3 4
3 3 1 2 3
4 4 4 1 2
5 5 5 5 1
answered Nov 13 at 17:11
gnovice
115k13229332
add a comment |
There are probably quite a few different ways to generate this matrix. Here's one using the functions repmat, toeplitz, tril, and triu:
>> a_new = tril(repmat(a.', 1, numel(a)), -1)+triu(toeplitz(a))
a_new =
1 2 3 4 5
2 1 2 3 4
3 3 1 2 3
4 4 4 1 2
5 5 5 5 1
answered Nov 13 at 17:11
gnovice
115k13229332
There are probably quite a few different ways to generate this matrix. Here's one using the functions repmat, toeplitz, tril, and triu:
>> a_new = tril(repmat(a.', 1, numel(a)), -1)+triu(toeplitz(a))
a_new =
1 2 3 4 5
2 1 2 3 4
3 3 1 2 3
4 4 4 1 2
5 5 5 5 1
answered Nov 13 at 17:11
gnovice
115k13229332
edited Nov 13 at 17:18
answered Nov 13 at 17:11
gnovice
115k13229332
answered Nov 13 at 17:11
gnovice
115k13229332
answered Nov 13 at 17:11
gnovice
115k13229332
115k13229332
add a comment |
add a comment |
I'm not sure about a built-in function, but this should work;
a=[1,2,3,4,5];
a_out = ones(length(a), length(a))
for n=1:5
a_out(n,:) = [n*ones(n-1),a(n:end)]
end
I do not have Octave or MATLAB installed on my computer, so I cannot test it. This may have a silly error, forgive me for that!
answered Nov 13 at 17:19
SRT HellKitty
2938
add a comment |
I'm not sure about a built-in function, but this should work;
a=[1,2,3,4,5];
a_out = ones(length(a), length(a))
for n=1:5
a_out(n,:) = [n*ones(n-1),a(n:end)]
end
I do not have Octave or MATLAB installed on my computer, so I cannot test it. This may have a silly error, forgive me for that!
answered Nov 13 at 17:19
SRT HellKitty
2938
add a comment |
I'm not sure about a built-in function, but this should work;
a=[1,2,3,4,5];
a_out = ones(length(a), length(a))
for n=1:5
a_out(n,:) = [n*ones(n-1),a(n:end)]
end
I do not have Octave or MATLAB installed on my computer, so I cannot test it. This may have a silly error, forgive me for that!
answered Nov 13 at 17:19
SRT HellKitty
2938
I'm not sure about a built-in function, but this should work;
a=[1,2,3,4,5];
a_out = ones(length(a), length(a))
for n=1:5
a_out(n,:) = [n*ones(n-1),a(n:end)]
end
I do not have Octave or MATLAB installed on my computer, so I cannot test it. This may have a silly error, forgive me for that!
answered Nov 13 at 17:19
SRT HellKitty
2938
answered Nov 13 at 17:19
SRT HellKitty
2938
answered Nov 13 at 17:19
SRT HellKitty
2938
answered Nov 13 at 17:19
SRT HellKitty
2938
2938
add a comment |
add a comment |
You can use spdiags to generate the matrix:
n = numel(a);
a_new = spdiags([repmat(flip(a).',1,n); repmat(a,n-1,1)],(1-n):0);
answered Nov 14 at 4:04
rahnema1
9,8752922
add a comment |
You can use spdiags to generate the matrix:
n = numel(a);
a_new = spdiags([repmat(flip(a).',1,n); repmat(a,n-1,1)],(1-n):0);
answered Nov 14 at 4:04
rahnema1
9,8752922
add a comment |
You can use spdiags to generate the matrix:
n = numel(a);
a_new = spdiags([repmat(flip(a).',1,n); repmat(a,n-1,1)],(1-n):0);
answered Nov 14 at 4:04
rahnema1
9,8752922
You can use spdiags to generate the matrix:
n = numel(a);
a_new = spdiags([repmat(flip(a).',1,n); repmat(a,n-1,1)],(1-n):0);
answered Nov 14 at 4:04
rahnema1
9,8752922
answered Nov 14 at 4:04
rahnema1
9,8752922
answered Nov 14 at 4:04
rahnema1
9,8752922
answered Nov 14 at 4:04
rahnema1
9,8752922
9,8752922
add a comment |
add a comment |
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can you explain your matrix? why is the first column a different direction than the others? Are you 100% sure this is what you want?
circshiftwont work because of this, the first column is a special case– Ander Biguri
Nov 13 at 17:11
@AnderBiguri the columns represent the orders / index the numbers should go in.
– Rick T
Nov 13 at 17:17