Ajax post FormData and the form





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







2















I have this form:



<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"> </script>
<link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">


<div class='col-sm-6' style="padding-left:0px;" >
<form action="/main/" method="post" id="my_form" enctype="multipart/form-data">
{% csrf_token %}
<br>

<div> <input type="text" name="description" id="id_description" /> </div>
<div> <input type="file" name="image" id="id_image" /> </div>


<button type="submit" disabled style="display: none" aria-hidden="true"></button>
<input class="btn btn-success" type="submit" name="submit" value="Gem" />
</form>
</div>


This successfully sends the form and it is valid on the server side. But I can´t access the image from the form on the server.



<script>
var frm = $('#my_form');
frm.submit(function (e) {
e.preventDefault(e);
$.ajax({
async: true,
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
console.log("success")
},
error: function(request, status, error) {
console.log("error")
}
});
});
</script>


This solution sends the FormData with the image file, but it does not include the other form data and the form is not valid on the server side:



<script type="text/javascript">
var frm = $('#my_form');
frm.submit(function (e) {
e.preventDefault(e);

var formData = new FormData();
formData.append(
"image",
document.getElementById("id_image").files[0]
);

$.ajax({
async: true,
type: frm.attr('method'),
url: frm.attr('action'),
data: formData,
cache: false,
processData: false,
contentType: false,
type: 'POST',

success: function (data) {
console.log("success")
},
error: function(request, status, error) {
console.log("error")
}
});
});


</script>


Is there a way to send both the file and the other form dara at the same time?










share|improve this question





























    2















    I have this form:



    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"> </script>
    <link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">


    <div class='col-sm-6' style="padding-left:0px;" >
    <form action="/main/" method="post" id="my_form" enctype="multipart/form-data">
    {% csrf_token %}
    <br>

    <div> <input type="text" name="description" id="id_description" /> </div>
    <div> <input type="file" name="image" id="id_image" /> </div>


    <button type="submit" disabled style="display: none" aria-hidden="true"></button>
    <input class="btn btn-success" type="submit" name="submit" value="Gem" />
    </form>
    </div>


    This successfully sends the form and it is valid on the server side. But I can´t access the image from the form on the server.



    <script>
    var frm = $('#my_form');
    frm.submit(function (e) {
    e.preventDefault(e);
    $.ajax({
    async: true,
    type: frm.attr('method'),
    url: frm.attr('action'),
    data: frm.serialize(),
    success: function (data) {
    console.log("success")
    },
    error: function(request, status, error) {
    console.log("error")
    }
    });
    });
    </script>


    This solution sends the FormData with the image file, but it does not include the other form data and the form is not valid on the server side:



    <script type="text/javascript">
    var frm = $('#my_form');
    frm.submit(function (e) {
    e.preventDefault(e);

    var formData = new FormData();
    formData.append(
    "image",
    document.getElementById("id_image").files[0]
    );

    $.ajax({
    async: true,
    type: frm.attr('method'),
    url: frm.attr('action'),
    data: formData,
    cache: false,
    processData: false,
    contentType: false,
    type: 'POST',

    success: function (data) {
    console.log("success")
    },
    error: function(request, status, error) {
    console.log("error")
    }
    });
    });


    </script>


    Is there a way to send both the file and the other form dara at the same time?










    share|improve this question

























      2












      2








      2








      I have this form:



      <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"> </script>
      <link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">


      <div class='col-sm-6' style="padding-left:0px;" >
      <form action="/main/" method="post" id="my_form" enctype="multipart/form-data">
      {% csrf_token %}
      <br>

      <div> <input type="text" name="description" id="id_description" /> </div>
      <div> <input type="file" name="image" id="id_image" /> </div>


      <button type="submit" disabled style="display: none" aria-hidden="true"></button>
      <input class="btn btn-success" type="submit" name="submit" value="Gem" />
      </form>
      </div>


      This successfully sends the form and it is valid on the server side. But I can´t access the image from the form on the server.



      <script>
      var frm = $('#my_form');
      frm.submit(function (e) {
      e.preventDefault(e);
      $.ajax({
      async: true,
      type: frm.attr('method'),
      url: frm.attr('action'),
      data: frm.serialize(),
      success: function (data) {
      console.log("success")
      },
      error: function(request, status, error) {
      console.log("error")
      }
      });
      });
      </script>


      This solution sends the FormData with the image file, but it does not include the other form data and the form is not valid on the server side:



      <script type="text/javascript">
      var frm = $('#my_form');
      frm.submit(function (e) {
      e.preventDefault(e);

      var formData = new FormData();
      formData.append(
      "image",
      document.getElementById("id_image").files[0]
      );

      $.ajax({
      async: true,
      type: frm.attr('method'),
      url: frm.attr('action'),
      data: formData,
      cache: false,
      processData: false,
      contentType: false,
      type: 'POST',

      success: function (data) {
      console.log("success")
      },
      error: function(request, status, error) {
      console.log("error")
      }
      });
      });


      </script>


      Is there a way to send both the file and the other form dara at the same time?










      share|improve this question














      I have this form:



      <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"> </script>
      <link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">


      <div class='col-sm-6' style="padding-left:0px;" >
      <form action="/main/" method="post" id="my_form" enctype="multipart/form-data">
      {% csrf_token %}
      <br>

      <div> <input type="text" name="description" id="id_description" /> </div>
      <div> <input type="file" name="image" id="id_image" /> </div>


      <button type="submit" disabled style="display: none" aria-hidden="true"></button>
      <input class="btn btn-success" type="submit" name="submit" value="Gem" />
      </form>
      </div>


      This successfully sends the form and it is valid on the server side. But I can´t access the image from the form on the server.



      <script>
      var frm = $('#my_form');
      frm.submit(function (e) {
      e.preventDefault(e);
      $.ajax({
      async: true,
      type: frm.attr('method'),
      url: frm.attr('action'),
      data: frm.serialize(),
      success: function (data) {
      console.log("success")
      },
      error: function(request, status, error) {
      console.log("error")
      }
      });
      });
      </script>


      This solution sends the FormData with the image file, but it does not include the other form data and the form is not valid on the server side:



      <script type="text/javascript">
      var frm = $('#my_form');
      frm.submit(function (e) {
      e.preventDefault(e);

      var formData = new FormData();
      formData.append(
      "image",
      document.getElementById("id_image").files[0]
      );

      $.ajax({
      async: true,
      type: frm.attr('method'),
      url: frm.attr('action'),
      data: formData,
      cache: false,
      processData: false,
      contentType: false,
      type: 'POST',

      success: function (data) {
      console.log("success")
      },
      error: function(request, status, error) {
      console.log("error")
      }
      });
      });


      </script>


      Is there a way to send both the file and the other form dara at the same time?







      javascript jquery html ajax






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 21 '18 at 22:02









      DevB2FDevB2F

      1,94821332




      1,94821332
























          2 Answers
          2






          active

          oldest

          votes


















          3














          Try passing this to FormData Also, you were setting type twice.



          var frm = $('#my_form');
          frm.submit(function (e) {
          e.preventDefault(e);

          var formData = new FormData(this);

          $.ajax({
          async: true,
          type: frm.attr('method'),
          url: frm.attr('action'),
          data: formData,
          cache: false,
          processData: false,
          contentType: false,

          success: function (data) {
          console.log("success")
          },
          error: function(request, status, error) {
          console.log("error")
          }
          });
          });





          share|improve this answer



















          • 1





            works, nice and easy solution

            – DevB2F
            Nov 21 '18 at 22:27



















          0














          Your last block using formData is only appending the file. This is why data only contains the file no other form data. Be sure to fully populate formData first.






          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            Try passing this to FormData Also, you were setting type twice.



            var frm = $('#my_form');
            frm.submit(function (e) {
            e.preventDefault(e);

            var formData = new FormData(this);

            $.ajax({
            async: true,
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: formData,
            cache: false,
            processData: false,
            contentType: false,

            success: function (data) {
            console.log("success")
            },
            error: function(request, status, error) {
            console.log("error")
            }
            });
            });





            share|improve this answer



















            • 1





              works, nice and easy solution

              – DevB2F
              Nov 21 '18 at 22:27
















            3














            Try passing this to FormData Also, you were setting type twice.



            var frm = $('#my_form');
            frm.submit(function (e) {
            e.preventDefault(e);

            var formData = new FormData(this);

            $.ajax({
            async: true,
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: formData,
            cache: false,
            processData: false,
            contentType: false,

            success: function (data) {
            console.log("success")
            },
            error: function(request, status, error) {
            console.log("error")
            }
            });
            });





            share|improve this answer



















            • 1





              works, nice and easy solution

              – DevB2F
              Nov 21 '18 at 22:27














            3












            3








            3







            Try passing this to FormData Also, you were setting type twice.



            var frm = $('#my_form');
            frm.submit(function (e) {
            e.preventDefault(e);

            var formData = new FormData(this);

            $.ajax({
            async: true,
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: formData,
            cache: false,
            processData: false,
            contentType: false,

            success: function (data) {
            console.log("success")
            },
            error: function(request, status, error) {
            console.log("error")
            }
            });
            });





            share|improve this answer













            Try passing this to FormData Also, you were setting type twice.



            var frm = $('#my_form');
            frm.submit(function (e) {
            e.preventDefault(e);

            var formData = new FormData(this);

            $.ajax({
            async: true,
            type: frm.attr('method'),
            url: frm.attr('action'),
            data: formData,
            cache: false,
            processData: false,
            contentType: false,

            success: function (data) {
            console.log("success")
            },
            error: function(request, status, error) {
            console.log("error")
            }
            });
            });






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 21 '18 at 22:20









            AnonymousSBAnonymousSB

            2,229221




            2,229221








            • 1





              works, nice and easy solution

              – DevB2F
              Nov 21 '18 at 22:27














            • 1





              works, nice and easy solution

              – DevB2F
              Nov 21 '18 at 22:27








            1




            1





            works, nice and easy solution

            – DevB2F
            Nov 21 '18 at 22:27





            works, nice and easy solution

            – DevB2F
            Nov 21 '18 at 22:27













            0














            Your last block using formData is only appending the file. This is why data only contains the file no other form data. Be sure to fully populate formData first.






            share|improve this answer




























              0














              Your last block using formData is only appending the file. This is why data only contains the file no other form data. Be sure to fully populate formData first.






              share|improve this answer


























                0












                0








                0







                Your last block using formData is only appending the file. This is why data only contains the file no other form data. Be sure to fully populate formData first.






                share|improve this answer













                Your last block using formData is only appending the file. This is why data only contains the file no other form data. Be sure to fully populate formData first.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 21 '18 at 22:19









                CodeTheInternetCodeTheInternet

                14




                14






























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