jQuery get data as object or array












2















I would like to get all elements with class .my-data-tid and data-tid values into an object or array



<div class="my-data-tid" data-tid="1">1</div>
<div class="my-data-tid" data-tid="2">2</div>
<div class="my-data-tid" data-tid="3">3</div>
<div class="my-data-tid" data-tid="4">4</div>


with



var tid = $('.my-data-tid').data('tid');


I get only the first value










share|improve this question





























    2















    I would like to get all elements with class .my-data-tid and data-tid values into an object or array



    <div class="my-data-tid" data-tid="1">1</div>
    <div class="my-data-tid" data-tid="2">2</div>
    <div class="my-data-tid" data-tid="3">3</div>
    <div class="my-data-tid" data-tid="4">4</div>


    with



    var tid = $('.my-data-tid').data('tid');


    I get only the first value










    share|improve this question



























      2












      2








      2


      0






      I would like to get all elements with class .my-data-tid and data-tid values into an object or array



      <div class="my-data-tid" data-tid="1">1</div>
      <div class="my-data-tid" data-tid="2">2</div>
      <div class="my-data-tid" data-tid="3">3</div>
      <div class="my-data-tid" data-tid="4">4</div>


      with



      var tid = $('.my-data-tid').data('tid');


      I get only the first value










      share|improve this question
















      I would like to get all elements with class .my-data-tid and data-tid values into an object or array



      <div class="my-data-tid" data-tid="1">1</div>
      <div class="my-data-tid" data-tid="2">2</div>
      <div class="my-data-tid" data-tid="3">3</div>
      <div class="my-data-tid" data-tid="4">4</div>


      with



      var tid = $('.my-data-tid').data('tid');


      I get only the first value







      javascript jquery arrays custom-data-attribute






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 16 '18 at 14:41









      Mohammad

      15.4k123461




      15.4k123461










      asked Nov 16 '18 at 14:35









      al404ITal404IT

      5501931




      5501931
























          1 Answer
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          4














          You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.






          var tid = $('.my-data-tid').map(function(){
          return $(this).data('tid');
          }).toArray();
          console.log(tid);

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class="my-data-tid" data-tid="1">1</div>
          <div class="my-data-tid" data-tid="2">2</div>
          <div class="my-data-tid" data-tid="3">3</div>
          <div class="my-data-tid" data-tid="4">4</div>








          share|improve this answer























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            1 Answer
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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.






            var tid = $('.my-data-tid').map(function(){
            return $(this).data('tid');
            }).toArray();
            console.log(tid);

            <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
            <div class="my-data-tid" data-tid="1">1</div>
            <div class="my-data-tid" data-tid="2">2</div>
            <div class="my-data-tid" data-tid="3">3</div>
            <div class="my-data-tid" data-tid="4">4</div>








            share|improve this answer




























              4














              You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.






              var tid = $('.my-data-tid').map(function(){
              return $(this).data('tid');
              }).toArray();
              console.log(tid);

              <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
              <div class="my-data-tid" data-tid="1">1</div>
              <div class="my-data-tid" data-tid="2">2</div>
              <div class="my-data-tid" data-tid="3">3</div>
              <div class="my-data-tid" data-tid="4">4</div>








              share|improve this answer


























                4












                4








                4







                You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.






                var tid = $('.my-data-tid').map(function(){
                return $(this).data('tid');
                }).toArray();
                console.log(tid);

                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                <div class="my-data-tid" data-tid="1">1</div>
                <div class="my-data-tid" data-tid="2">2</div>
                <div class="my-data-tid" data-tid="3">3</div>
                <div class="my-data-tid" data-tid="4">4</div>








                share|improve this answer













                You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.






                var tid = $('.my-data-tid').map(function(){
                return $(this).data('tid');
                }).toArray();
                console.log(tid);

                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                <div class="my-data-tid" data-tid="1">1</div>
                <div class="my-data-tid" data-tid="2">2</div>
                <div class="my-data-tid" data-tid="3">3</div>
                <div class="my-data-tid" data-tid="4">4</div>








                var tid = $('.my-data-tid').map(function(){
                return $(this).data('tid');
                }).toArray();
                console.log(tid);

                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                <div class="my-data-tid" data-tid="1">1</div>
                <div class="my-data-tid" data-tid="2">2</div>
                <div class="my-data-tid" data-tid="3">3</div>
                <div class="my-data-tid" data-tid="4">4</div>





                var tid = $('.my-data-tid').map(function(){
                return $(this).data('tid');
                }).toArray();
                console.log(tid);

                <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
                <div class="my-data-tid" data-tid="1">1</div>
                <div class="my-data-tid" data-tid="2">2</div>
                <div class="my-data-tid" data-tid="3">3</div>
                <div class="my-data-tid" data-tid="4">4</div>






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 16 '18 at 14:36









                MohammadMohammad

                15.4k123461




                15.4k123461






























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