Why does int('.0') give ValueError?

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

edited Nov 20 '18 at 2:15

smci

15k676104

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

3

Because integers are not floating-point.

– SLaks
Nov 20 '18 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.

– Nishant Kadivar
Nov 20 '18 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.

– Loocid
Nov 20 '18 at 2:01

add a comment |

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

edited Nov 20 '18 at 2:15

smci

15k676104

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

3

Because integers are not floating-point.

– SLaks
Nov 20 '18 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.

– Nishant Kadivar
Nov 20 '18 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.

– Loocid
Nov 20 '18 at 2:01

add a comment |

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

edited Nov 20 '18 at 2:15

smci

15k676104

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

I pass float number as string format in int('.0')

0.0 is valid floating point number, so why it is giving error?

python floating-point type-conversion int valueerror

edited Nov 20 '18 at 2:15

smci

15k676104

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

edited Nov 20 '18 at 2:15

smci

15k676104

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

edited Nov 20 '18 at 2:15

smci

15k676104

edited Nov 20 '18 at 2:15

smci

15k676104

edited Nov 20 '18 at 2:15

smci

15k676104

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

asked Nov 20 '18 at 1:53

Nishant Kadivar

204

3

Because integers are not floating-point.

– SLaks
Nov 20 '18 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.

– Nishant Kadivar
Nov 20 '18 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.

– Loocid
Nov 20 '18 at 2:01

add a comment |

3

Because integers are not floating-point.

– SLaks
Nov 20 '18 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.

– Nishant Kadivar
Nov 20 '18 at 1:58

3

int('2.1') returns a value error too. Similarly int(0.1) returns 0.

– Loocid
Nov 20 '18 at 2:01

Because integers are not floating-point.

– SLaks
Nov 20 '18 at 1:55

Thanks for answering. int(2.1) gives 2 in return. so int convert it into int.

– Nishant Kadivar
Nov 20 '18 at 1:58

int('2.1') returns a value error too. Similarly int(0.1) returns 0.

– Loocid
Nov 20 '18 at 2:01

add a comment |

3 Answers
3

active

oldest

votes

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".

– martineau
Nov 20 '18 at 2:23

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 '18 at 2:00

Kireeti K

342211

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53385136%2fwhy-does-int-0-give-valueerror%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".

– martineau
Nov 20 '18 at 2:23

add a comment |

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".

– martineau
Nov 20 '18 at 2:23

add a comment |

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

From the documentation of int:

If x is not a number or if base is given, then x must be a string,
bytes, or bytearray instance representing an integer literal in radix
base. Optionally, the literal can be preceded by + or - (with no space
in between) and surrounded by whitespace.

So it gives you ValueError because the string '.0' does not represent an integer literal.

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

answered Nov 20 '18 at 2:13

Daniel Mesejo

18.4k21432

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".

– martineau
Nov 20 '18 at 2:23

add a comment |

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".

– martineau
Nov 20 '18 at 2:23

@Nishant: Notice how it doesn't say "the literal can be preceded by a .".

– martineau
Nov 20 '18 at 2:23

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 '18 at 2:00

Kireeti K

342211

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 '18 at 2:00

Kireeti K

342211

add a comment |

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 '18 at 2:00

Kireeti K

342211

Because you can type cast one step at a time. For example you can convert float to int or string to int. Not a floating point string which here is 2steps.

answered Nov 20 '18 at 2:00

Kireeti K

342211

answered Nov 20 '18 at 2:00

Kireeti K

342211

answered Nov 20 '18 at 2:00

Kireeti K

342211

answered Nov 20 '18 at 2:00

Kireeti K

342211

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

add a comment |

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

You can do it if you remove the quotes and make it a float like:

int(.1)

But strings don't work if inside the string is a float, because they will think it's a number and will break saying '.' is not a numeric value, also the reason the above works is because:

>>> .1

0.1

>>>

And:

float(0.1)

Works.

Note that even a real float in a string can't be converted into an integer:

>>> int('3.1')

Traceback (most recent call last):

  File "<pyshell#1>", line 1, in <module>

    int('3.1')

ValueError: invalid literal for int() with base 10: '3.1'

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

edited Nov 20 '18 at 7:10

Rudy Velthuis

24.4k43574

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

answered Nov 20 '18 at 2:41

U9-Forward

15.3k41439

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Agfdhyk